TSTP Solution File: GRP533-1 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : GRP533-1 : TPTP v8.1.0. Released v2.6.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n026.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 12:57:12 EDT 2022

% Result   : Unsatisfiable 1.97s 2.11s
% Output   : Refutation 1.97s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    4
%            Number of leaves      :    5
% Syntax   : Number of clauses     :   11 (  11 unt;   0 nHn;   4 RR)
%            Number of literals    :   11 (  10 equ;   3 neg)
%            Maximal clause size   :    1 (   1 avg)
%            Maximal term depth    :    4 (   2 avg)
%            Number of predicates  :    2 (   0 usr;   1 prp; 0-2 aty)
%            Number of functors    :    6 (   6 usr;   3 con; 0-2 aty)
%            Number of variables   :   11 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    multiply(inverse(a1),a1) != multiply(inverse(b1),b1),
    file('GRP533-1.p',unknown),
    [] ).

cnf(2,plain,
    multiply(inverse(b1),b1) != multiply(inverse(a1),a1),
    inference(flip,[status(thm),theory(equality)],[inference(copy,[status(thm)],[1])]),
    [iquote('copy,1,flip.1')] ).

cnf(3,axiom,
    A = A,
    file('GRP533-1.p',unknown),
    [] ).

cnf(6,axiom,
    multiply(A,B) = divide(A,divide(divide(C,C),B)),
    file('GRP533-1.p',unknown),
    [] ).

cnf(7,axiom,
    inverse(A) = divide(divide(B,B),A),
    file('GRP533-1.p',unknown),
    [] ).

cnf(8,axiom,
    identity = divide(A,A),
    file('GRP533-1.p',unknown),
    [] ).

cnf(10,plain,
    divide(A,A) = identity,
    inference(flip,[status(thm),theory(equality)],[inference(copy,[status(thm)],[8])]),
    [iquote('copy,8,flip.1')] ).

cnf(12,plain,
    multiply(A,B) = divide(A,divide(identity,B)),
    inference(flip,[status(thm),theory(equality)],[inference(demod,[status(thm),theory(equality)],[inference(flip,[status(thm),theory(equality)],[inference(copy,[status(thm)],[6])]),10])]),
    [iquote('copy,6,flip.1,demod,10,flip.1')] ).

cnf(14,plain,
    inverse(A) = divide(identity,A),
    inference(flip,[status(thm),theory(equality)],[inference(demod,[status(thm),theory(equality)],[inference(flip,[status(thm),theory(equality)],[inference(copy,[status(thm)],[7])]),10])]),
    [iquote('copy,7,flip.1,demod,10,flip.1')] ).

cnf(15,plain,
    identity != identity,
    inference(demod,[status(thm),theory(equality)],[inference(back_demod,[status(thm)],[2]),14,12,10,14,12,10]),
    [iquote('back_demod,2,demod,14,12,10,14,12,10')] ).

cnf(16,plain,
    $false,
    inference(binary,[status(thm)],[15,3]),
    [iquote('binary,15.1,3.1')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12  % Problem  : GRP533-1 : TPTP v8.1.0. Released v2.6.0.
% 0.07/0.12  % Command  : otter-tptp-script %s
% 0.13/0.34  % Computer : n026.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % WCLimit  : 300
% 0.13/0.34  % DateTime : Wed Jul 27 05:36:09 EDT 2022
% 0.13/0.34  % CPUTime  : 
% 1.97/2.11  
% 1.97/2.11  -------- PROOF -------- 
% 1.97/2.11  ----- Otter 3.3f, August 2004 -----
% 1.97/2.11  The process was started by sandbox2 on n026.cluster.edu,
% 1.97/2.11  Wed Jul 27 05:36:09 2022
% 1.97/2.11  The command was "./otter".  The process ID is 11032.
% 1.97/2.11  
% 1.97/2.11  set(prolog_style_variables).
% 1.97/2.11  set(auto).
% 1.97/2.11     dependent: set(auto1).
% 1.97/2.11     dependent: set(process_input).
% 1.97/2.11     dependent: clear(print_kept).
% 1.97/2.11     dependent: clear(print_new_demod).
% 1.97/2.11     dependent: clear(print_back_demod).
% 1.97/2.11     dependent: clear(print_back_sub).
% 1.97/2.11     dependent: set(control_memory).
% 1.97/2.11     dependent: assign(max_mem, 12000).
% 1.97/2.11     dependent: assign(pick_given_ratio, 4).
% 1.97/2.11     dependent: assign(stats_level, 1).
% 1.97/2.11     dependent: assign(max_seconds, 10800).
% 1.97/2.11  clear(print_given).
% 1.97/2.11  
% 1.97/2.11  list(usable).
% 1.97/2.11  0 [] A=A.
% 1.97/2.11  0 [] divide(divide(A,divide(divide(A,B),C)),B)=C.
% 1.97/2.11  0 [] multiply(A,B)=divide(A,divide(divide(C,C),B)).
% 1.97/2.11  0 [] inverse(A)=divide(divide(B,B),A).
% 1.97/2.11  0 [] identity=divide(A,A).
% 1.97/2.11  0 [] multiply(inverse(a1),a1)!=multiply(inverse(b1),b1).
% 1.97/2.11  end_of_list.
% 1.97/2.11  
% 1.97/2.11  SCAN INPUT: prop=0, horn=1, equality=1, symmetry=0, max_lits=1.
% 1.97/2.11  
% 1.97/2.11  All clauses are units, and equality is present; the
% 1.97/2.11  strategy will be Knuth-Bendix with positive clauses in sos.
% 1.97/2.11  
% 1.97/2.11     dependent: set(knuth_bendix).
% 1.97/2.11     dependent: set(anl_eq).
% 1.97/2.11     dependent: set(para_from).
% 1.97/2.11     dependent: set(para_into).
% 1.97/2.11     dependent: clear(para_from_right).
% 1.97/2.11     dependent: clear(para_into_right).
% 1.97/2.11     dependent: set(para_from_vars).
% 1.97/2.11     dependent: set(eq_units_both_ways).
% 1.97/2.11     dependent: set(dynamic_demod_all).
% 1.97/2.11     dependent: set(dynamic_demod).
% 1.97/2.11     dependent: set(order_eq).
% 1.97/2.11     dependent: set(back_demod).
% 1.97/2.11     dependent: set(lrpo).
% 1.97/2.11  
% 1.97/2.11  ------------> process usable:
% 1.97/2.11  ** KEPT (pick-wt=9): 2 [copy,1,flip.1] multiply(inverse(b1),b1)!=multiply(inverse(a1),a1).
% 1.97/2.11  
% 1.97/2.11  ------------> process sos:
% 1.97/2.11  ** KEPT (pick-wt=3): 3 [] A=A.
% 1.97/2.11  ** KEPT (pick-wt=11): 4 [] divide(divide(A,divide(divide(A,B),C)),B)=C.
% 1.97/2.11  ---> New Demodulator: 5 [new_demod,4] divide(divide(A,divide(divide(A,B),C)),B)=C.
% 1.97/2.11  ** KEPT (pick-wt=11): 6 [] multiply(A,B)=divide(A,divide(divide(C,C),B)).
% 1.97/2.11  ** KEPT (pick-wt=8): 7 [] inverse(A)=divide(divide(B,B),A).
% 1.97/2.11  ** KEPT (pick-wt=5): 9 [copy,8,flip.1] divide(A,A)=identity.
% 1.97/2.11  ---> New Demodulator: 10 [new_demod,9] divide(A,A)=identity.
% 1.97/2.11    Following clause subsumed by 3 during input processing: 0 [copy,3,flip.1] A=A.
% 1.97/2.11  >>>> Starting back demodulation with 5.
% 1.97/2.11  ** KEPT (pick-wt=9): 11 [copy,6,flip.1,demod,10,flip.1] multiply(A,B)=divide(A,divide(identity,B)).
% 1.97/2.11  ---> New Demodulator: 12 [new_demod,11] multiply(A,B)=divide(A,divide(identity,B)).
% 1.97/2.11  ** KEPT (pick-wt=6): 13 [copy,7,flip.1,demod,10,flip.1] inverse(A)=divide(identity,A).
% 1.97/2.11  ---> New Demodulator: 14 [new_demod,13] inverse(A)=divide(identity,A).
% 1.97/2.11  >>>> Starting back demodulation with 10.
% 1.97/2.11      >> back demodulating 7 with 10.
% 1.97/2.11      >> back demodulating 6 with 10.
% 1.97/2.11  >>>> Starting back demodulation with 12.
% 1.97/2.11      >> back demodulating 2 with 12.
% 1.97/2.11  
% 1.97/2.11  ----> UNIT CONFLICT at   0.00 sec ----> 16 [binary,15.1,3.1] $F.
% 1.97/2.11  
% 1.97/2.11  Length of proof is 5.  Level of proof is 3.
% 1.97/2.11  
% 1.97/2.11  ---------------- PROOF ----------------
% 1.97/2.11  % SZS status Unsatisfiable
% 1.97/2.11  % SZS output start Refutation
% See solution above
% 1.97/2.11  ------------ end of proof -------------
% 1.97/2.11  
% 1.97/2.11  
% 1.97/2.11  Search stopped by max_proofs option.
% 1.97/2.11  
% 1.97/2.11  
% 1.97/2.11  Search stopped by max_proofs option.
% 1.97/2.11  
% 1.97/2.11  ============ end of search ============
% 1.97/2.11  
% 1.97/2.11  -------------- statistics -------------
% 1.97/2.11  clauses given                  0
% 1.97/2.11  clauses generated              0
% 1.97/2.11  clauses kept                   9
% 1.97/2.11  clauses forward subsumed       3
% 1.97/2.11  clauses back subsumed          0
% 1.97/2.11  Kbytes malloced              976
% 1.97/2.11  
% 1.97/2.11  ----------- times (seconds) -----------
% 1.97/2.11  user CPU time          0.00          (0 hr, 0 min, 0 sec)
% 1.97/2.11  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.97/2.11  wall-clock time        1             (0 hr, 0 min, 1 sec)
% 1.97/2.11  
% 1.97/2.11  That finishes the proof of the theorem.
% 1.97/2.11  
% 1.97/2.11  Process 11032 finished Wed Jul 27 05:36:10 2022
% 1.97/2.11  Otter interrupted
% 1.97/2.11  PROOF FOUND
%------------------------------------------------------------------------------