TSTP Solution File: GRP519-1 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : GRP519-1 : TPTP v8.1.0. Released v2.6.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n022.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 12:57:10 EDT 2022

% Result   : Unsatisfiable 1.61s 1.78s
% Output   : Refutation 1.61s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    6
%            Number of leaves      :    2
% Syntax   : Number of clauses     :    9 (   9 unt;   0 nHn;   2 RR)
%            Number of literals    :    9 (   8 equ;   1 neg)
%            Maximal clause size   :    1 (   1 avg)
%            Maximal term depth    :    7 (   2 avg)
%            Number of predicates  :    2 (   0 usr;   1 prp; 0-2 aty)
%            Number of functors    :    5 (   5 usr;   3 con; 0-2 aty)
%            Number of variables   :   22 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    multiply(multiply(a3,b3),c3) != multiply(a3,multiply(b3,c3)),
    file('GRP519-1.p',unknown),
    [] ).

cnf(3,axiom,
    multiply(A,multiply(multiply(inverse(multiply(A,B)),C),B)) = C,
    file('GRP519-1.p',unknown),
    [] ).

cnf(5,plain,
    multiply(A,multiply(multiply(inverse(B),C),multiply(multiply(inverse(multiply(A,D)),B),D))) = C,
    inference(para_into,[status(thm),theory(equality)],[3,3]),
    [iquote('para_into,3.1.1.2.1.1.1,3.1.1')] ).

cnf(17,plain,
    multiply(multiply(inverse(A),B),A) = B,
    inference(para_into,[status(thm),theory(equality)],[5,3]),
    [iquote('para_into,5.1.1.2,3.1.1')] ).

cnf(23,plain,
    multiply(multiply(inverse(A),B),multiply(multiply(inverse(multiply(inverse(C),D)),A),D)) = multiply(B,C),
    inference(flip,[status(thm),theory(equality)],[inference(para_into,[status(thm),theory(equality)],[17,5])]),
    [iquote('para_into,17.1.1.1,5.1.1,flip.1')] ).

cnf(26,plain,
    multiply(multiply(inverse(multiply(inverse(A),B)),C),B) = multiply(C,A),
    inference(flip,[status(thm),theory(equality)],[inference(para_into,[status(thm),theory(equality)],[17,3])]),
    [iquote('para_into,17.1.1.1,3.1.1,flip.1')] ).

cnf(29,plain,
    multiply(multiply(inverse(A),B),multiply(A,C)) = multiply(B,C),
    inference(demod,[status(thm),theory(equality)],[inference(back_demod,[status(thm)],[23]),26]),
    [iquote('back_demod,23,demod,26')] ).

cnf(84,plain,
    multiply(multiply(A,B),C) = multiply(A,multiply(B,C)),
    inference(flip,[status(thm),theory(equality)],[inference(demod,[status(thm),theory(equality)],[inference(para_into,[status(thm),theory(equality)],[29,3]),26])]),
    [iquote('para_into,29.1.1.1,3.1.1,demod,26,flip.1')] ).

cnf(86,plain,
    $false,
    inference(binary,[status(thm)],[84,1]),
    [iquote('binary,84.1,1.1')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12  % Problem  : GRP519-1 : TPTP v8.1.0. Released v2.6.0.
% 0.07/0.13  % Command  : otter-tptp-script %s
% 0.12/0.34  % Computer : n022.cluster.edu
% 0.12/0.34  % Model    : x86_64 x86_64
% 0.12/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34  % Memory   : 8042.1875MB
% 0.12/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34  % CPULimit : 300
% 0.12/0.34  % WCLimit  : 300
% 0.12/0.34  % DateTime : Wed Jul 27 05:00:05 EDT 2022
% 0.12/0.34  % CPUTime  : 
% 1.61/1.78  ----- Otter 3.3f, August 2004 -----
% 1.61/1.78  The process was started by sandbox2 on n022.cluster.edu,
% 1.61/1.78  Wed Jul 27 05:00:05 2022
% 1.61/1.78  The command was "./otter".  The process ID is 17892.
% 1.61/1.78  
% 1.61/1.78  set(prolog_style_variables).
% 1.61/1.78  set(auto).
% 1.61/1.78     dependent: set(auto1).
% 1.61/1.78     dependent: set(process_input).
% 1.61/1.78     dependent: clear(print_kept).
% 1.61/1.78     dependent: clear(print_new_demod).
% 1.61/1.78     dependent: clear(print_back_demod).
% 1.61/1.78     dependent: clear(print_back_sub).
% 1.61/1.78     dependent: set(control_memory).
% 1.61/1.78     dependent: assign(max_mem, 12000).
% 1.61/1.78     dependent: assign(pick_given_ratio, 4).
% 1.61/1.78     dependent: assign(stats_level, 1).
% 1.61/1.78     dependent: assign(max_seconds, 10800).
% 1.61/1.78  clear(print_given).
% 1.61/1.78  
% 1.61/1.78  list(usable).
% 1.61/1.78  0 [] A=A.
% 1.61/1.78  0 [] multiply(A,multiply(multiply(inverse(multiply(A,B)),C),B))=C.
% 1.61/1.78  0 [] multiply(multiply(a3,b3),c3)!=multiply(a3,multiply(b3,c3)).
% 1.61/1.78  end_of_list.
% 1.61/1.78  
% 1.61/1.78  SCAN INPUT: prop=0, horn=1, equality=1, symmetry=0, max_lits=1.
% 1.61/1.78  
% 1.61/1.78  All clauses are units, and equality is present; the
% 1.61/1.78  strategy will be Knuth-Bendix with positive clauses in sos.
% 1.61/1.78  
% 1.61/1.78     dependent: set(knuth_bendix).
% 1.61/1.78     dependent: set(anl_eq).
% 1.61/1.78     dependent: set(para_from).
% 1.61/1.78     dependent: set(para_into).
% 1.61/1.78     dependent: clear(para_from_right).
% 1.61/1.78     dependent: clear(para_into_right).
% 1.61/1.78     dependent: set(para_from_vars).
% 1.61/1.78     dependent: set(eq_units_both_ways).
% 1.61/1.78     dependent: set(dynamic_demod_all).
% 1.61/1.78     dependent: set(dynamic_demod).
% 1.61/1.78     dependent: set(order_eq).
% 1.61/1.78     dependent: set(back_demod).
% 1.61/1.78     dependent: set(lrpo).
% 1.61/1.78  
% 1.61/1.78  ------------> process usable:
% 1.61/1.78  ** KEPT (pick-wt=11): 1 [] multiply(multiply(a3,b3),c3)!=multiply(a3,multiply(b3,c3)).
% 1.61/1.78  
% 1.61/1.78  ------------> process sos:
% 1.61/1.78  ** KEPT (pick-wt=3): 2 [] A=A.
% 1.61/1.78  ** KEPT (pick-wt=12): 3 [] multiply(A,multiply(multiply(inverse(multiply(A,B)),C),B))=C.
% 1.61/1.78  ---> New Demodulator: 4 [new_demod,3] multiply(A,multiply(multiply(inverse(multiply(A,B)),C),B))=C.
% 1.61/1.78    Following clause subsumed by 2 during input processing: 0 [copy,2,flip.1] A=A.
% 1.61/1.78  >>>> Starting back demodulation with 4.
% 1.61/1.78  
% 1.61/1.78  ======= end of input processing =======
% 1.61/1.78  
% 1.61/1.78  =========== start of search ===========
% 1.61/1.78  
% 1.61/1.78  -------- PROOF -------- 
% 1.61/1.78  
% 1.61/1.78  ----> UNIT CONFLICT at   0.00 sec ----> 86 [binary,84.1,1.1] $F.
% 1.61/1.78  
% 1.61/1.78  Length of proof is 6.  Level of proof is 5.
% 1.61/1.78  
% 1.61/1.78  ---------------- PROOF ----------------
% 1.61/1.78  % SZS status Unsatisfiable
% 1.61/1.78  % SZS output start Refutation
% See solution above
% 1.61/1.78  ------------ end of proof -------------
% 1.61/1.78  
% 1.61/1.78  
% 1.61/1.78  Search stopped by max_proofs option.
% 1.61/1.78  
% 1.61/1.78  
% 1.61/1.78  Search stopped by max_proofs option.
% 1.61/1.78  
% 1.61/1.78  ============ end of search ============
% 1.61/1.78  
% 1.61/1.78  -------------- statistics -------------
% 1.61/1.78  clauses given                  7
% 1.61/1.78  clauses generated             64
% 1.61/1.78  clauses kept                  50
% 1.61/1.78  clauses forward subsumed      42
% 1.61/1.78  clauses back subsumed          0
% 1.61/1.78  Kbytes malloced             1953
% 1.61/1.78  
% 1.61/1.78  ----------- times (seconds) -----------
% 1.61/1.78  user CPU time          0.00          (0 hr, 0 min, 0 sec)
% 1.61/1.78  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.61/1.78  wall-clock time        1             (0 hr, 0 min, 1 sec)
% 1.61/1.78  
% 1.61/1.78  That finishes the proof of the theorem.
% 1.61/1.78  
% 1.61/1.78  Process 17892 finished Wed Jul 27 05:00:06 2022
% 1.61/1.78  Otter interrupted
% 1.61/1.78  PROOF FOUND
%------------------------------------------------------------------------------