TSTP Solution File: GRP516-1 by Otter---3.3
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%------------------------------------------------------------------------------
% File : Otter---3.3
% Problem : GRP516-1 : TPTP v8.1.0. Bugfixed v2.7.0.
% Transfm : none
% Format : tptp:raw
% Command : otter-tptp-script %s
% Computer : n025.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Wed Jul 27 12:57:09 EDT 2022
% Result : Unsatisfiable 1.84s 2.04s
% Output : Refutation 1.84s
% Verified :
% SZS Type : Refutation
% Derivation depth : 8
% Number of leaves : 2
% Syntax : Number of clauses : 13 ( 13 unt; 0 nHn; 3 RR)
% Number of literals : 13 ( 12 equ; 2 neg)
% Maximal clause size : 1 ( 1 avg)
% Maximal term depth : 8 ( 2 avg)
% Number of predicates : 2 ( 0 usr; 1 prp; 0-2 aty)
% Number of functors : 4 ( 4 usr; 2 con; 0-2 aty)
% Number of variables : 29 ( 0 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(1,axiom,
multiply(a,b) != multiply(b,a),
file('GRP516-1.p',unknown),
[] ).
cnf(2,plain,
multiply(b,a) != multiply(a,b),
inference(flip,[status(thm),theory(equality)],[inference(copy,[status(thm)],[1])]),
[iquote('copy,1,flip.1')] ).
cnf(4,axiom,
multiply(A,multiply(multiply(B,C),inverse(multiply(A,C)))) = B,
file('GRP516-1.p',unknown),
[] ).
cnf(6,plain,
multiply(A,multiply(B,inverse(multiply(A,multiply(multiply(B,C),inverse(multiply(D,C))))))) = D,
inference(para_into,[status(thm),theory(equality)],[4,4]),
[iquote('para_into,4.1.1.2.1,4.1.1')] ).
cnf(8,plain,
multiply(A,multiply(multiply(B,multiply(multiply(C,D),inverse(multiply(A,D)))),inverse(C))) = B,
inference(para_into,[status(thm),theory(equality)],[4,4]),
[iquote('para_into,4.1.1.2.2.1,4.1.1')] ).
cnf(18,plain,
multiply(A,multiply(B,inverse(B))) = A,
inference(para_into,[status(thm),theory(equality)],[6,4]),
[iquote('para_into,6.1.1.2.2.1,4.1.1')] ).
cnf(22,plain,
multiply(A,multiply(B,inverse(A))) = B,
inference(para_from,[status(thm),theory(equality)],[18,6]),
[iquote('para_from,18.1.1,6.1.1.2.2.1')] ).
cnf(26,plain,
multiply(multiply(A,B),multiply(C,inverse(multiply(C,B)))) = A,
inference(para_from,[status(thm),theory(equality)],[22,6]),
[iquote('para_from,22.1.1,6.1.1.2.2.1')] ).
cnf(49,plain,
multiply(A,multiply(multiply(B,C),inverse(B))) = multiply(A,C),
inference(para_into,[status(thm),theory(equality)],[8,22]),
[iquote('para_into,8.1.1.2.1,22.1.1')] ).
cnf(64,plain,
multiply(multiply(A,multiply(B,inverse(multiply(B,C)))),C) = A,
inference(demod,[status(thm),theory(equality)],[inference(para_into,[status(thm),theory(equality)],[26,26]),49]),
[iquote('para_into,26.1.1.2.2.1,26.1.1,demod,49')] ).
cnf(124,plain,
multiply(A,multiply(B,inverse(multiply(B,inverse(C))))) = multiply(A,C),
inference(flip,[status(thm),theory(equality)],[inference(para_from,[status(thm),theory(equality)],[64,49])]),
[iquote('para_from,64.1.1,48.1.1.2,flip.1')] ).
cnf(125,plain,
multiply(A,B) = multiply(B,A),
inference(demod,[status(thm),theory(equality)],[inference(para_from,[status(thm),theory(equality)],[64,22]),124]),
[iquote('para_from,64.1.1,22.1.1.2,demod,124')] ).
cnf(126,plain,
$false,
inference(binary,[status(thm)],[125,2]),
[iquote('binary,125.1,2.1')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.11 % Problem : GRP516-1 : TPTP v8.1.0. Bugfixed v2.7.0.
% 0.06/0.12 % Command : otter-tptp-script %s
% 0.12/0.33 % Computer : n025.cluster.edu
% 0.12/0.33 % Model : x86_64 x86_64
% 0.12/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33 % Memory : 8042.1875MB
% 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33 % CPULimit : 300
% 0.12/0.33 % WCLimit : 300
% 0.12/0.33 % DateTime : Wed Jul 27 05:15:30 EDT 2022
% 0.12/0.33 % CPUTime :
% 1.84/2.04 ----- Otter 3.3f, August 2004 -----
% 1.84/2.04 The process was started by sandbox2 on n025.cluster.edu,
% 1.84/2.04 Wed Jul 27 05:15:30 2022
% 1.84/2.04 The command was "./otter". The process ID is 11002.
% 1.84/2.04
% 1.84/2.04 set(prolog_style_variables).
% 1.84/2.04 set(auto).
% 1.84/2.04 dependent: set(auto1).
% 1.84/2.04 dependent: set(process_input).
% 1.84/2.04 dependent: clear(print_kept).
% 1.84/2.04 dependent: clear(print_new_demod).
% 1.84/2.04 dependent: clear(print_back_demod).
% 1.84/2.04 dependent: clear(print_back_sub).
% 1.84/2.04 dependent: set(control_memory).
% 1.84/2.04 dependent: assign(max_mem, 12000).
% 1.84/2.04 dependent: assign(pick_given_ratio, 4).
% 1.84/2.04 dependent: assign(stats_level, 1).
% 1.84/2.04 dependent: assign(max_seconds, 10800).
% 1.84/2.04 clear(print_given).
% 1.84/2.04
% 1.84/2.04 list(usable).
% 1.84/2.04 0 [] A=A.
% 1.84/2.04 0 [] multiply(A,multiply(multiply(B,C),inverse(multiply(A,C))))=B.
% 1.84/2.04 0 [] multiply(a,b)!=multiply(b,a).
% 1.84/2.04 end_of_list.
% 1.84/2.04
% 1.84/2.04 SCAN INPUT: prop=0, horn=1, equality=1, symmetry=0, max_lits=1.
% 1.84/2.04
% 1.84/2.04 All clauses are units, and equality is present; the
% 1.84/2.04 strategy will be Knuth-Bendix with positive clauses in sos.
% 1.84/2.04
% 1.84/2.04 dependent: set(knuth_bendix).
% 1.84/2.04 dependent: set(anl_eq).
% 1.84/2.04 dependent: set(para_from).
% 1.84/2.04 dependent: set(para_into).
% 1.84/2.04 dependent: clear(para_from_right).
% 1.84/2.04 dependent: clear(para_into_right).
% 1.84/2.04 dependent: set(para_from_vars).
% 1.84/2.04 dependent: set(eq_units_both_ways).
% 1.84/2.04 dependent: set(dynamic_demod_all).
% 1.84/2.04 dependent: set(dynamic_demod).
% 1.84/2.04 dependent: set(order_eq).
% 1.84/2.04 dependent: set(back_demod).
% 1.84/2.04 dependent: set(lrpo).
% 1.84/2.04
% 1.84/2.04 ------------> process usable:
% 1.84/2.04 ** KEPT (pick-wt=7): 2 [copy,1,flip.1] multiply(b,a)!=multiply(a,b).
% 1.84/2.04
% 1.84/2.04 ------------> process sos:
% 1.84/2.04 ** KEPT (pick-wt=3): 3 [] A=A.
% 1.84/2.04 ** KEPT (pick-wt=12): 4 [] multiply(A,multiply(multiply(B,C),inverse(multiply(A,C))))=B.
% 1.84/2.04 ---> New Demodulator: 5 [new_demod,4] multiply(A,multiply(multiply(B,C),inverse(multiply(A,C))))=B.
% 1.84/2.04 Following clause subsumed by 3 during input processing: 0 [copy,3,flip.1] A=A.
% 1.84/2.04 >>>> Starting back demodulation with 5.
% 1.84/2.04
% 1.84/2.04 ======= end of input processing =======
% 1.84/2.04
% 1.84/2.04 =========== start of search ===========
% 1.84/2.04
% 1.84/2.04 -------- PROOF --------
% 1.84/2.04
% 1.84/2.04 ----> UNIT CONFLICT at 0.01 sec ----> 126 [binary,125.1,2.1] $F.
% 1.84/2.04
% 1.84/2.04 Length of proof is 10. Level of proof is 7.
% 1.84/2.04
% 1.84/2.04 ---------------- PROOF ----------------
% 1.84/2.04 % SZS status Unsatisfiable
% 1.84/2.04 % SZS output start Refutation
% See solution above
% 1.84/2.04 ------------ end of proof -------------
% 1.84/2.04
% 1.84/2.04
% 1.84/2.04 Search stopped by max_proofs option.
% 1.84/2.04
% 1.84/2.04
% 1.84/2.04 Search stopped by max_proofs option.
% 1.84/2.04
% 1.84/2.04 ============ end of search ============
% 1.84/2.04
% 1.84/2.04 -------------- statistics -------------
% 1.84/2.04 clauses given 9
% 1.84/2.04 clauses generated 120
% 1.84/2.04 clauses kept 65
% 1.84/2.04 clauses forward subsumed 103
% 1.84/2.04 clauses back subsumed 0
% 1.84/2.04 Kbytes malloced 976
% 1.84/2.04
% 1.84/2.04 ----------- times (seconds) -----------
% 1.84/2.04 user CPU time 0.01 (0 hr, 0 min, 0 sec)
% 1.84/2.04 system CPU time 0.00 (0 hr, 0 min, 0 sec)
% 1.84/2.04 wall-clock time 2 (0 hr, 0 min, 2 sec)
% 1.84/2.04
% 1.84/2.04 That finishes the proof of the theorem.
% 1.84/2.04
% 1.84/2.04 Process 11002 finished Wed Jul 27 05:15:32 2022
% 1.84/2.04 Otter interrupted
% 1.84/2.04 PROOF FOUND
%------------------------------------------------------------------------------