TSTP Solution File: GRP467-1 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : GRP467-1 : TPTP v8.1.0. Released v2.6.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n015.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 12:57:04 EDT 2022

% Result   : Unsatisfiable 1.95s 2.12s
% Output   : Refutation 1.95s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    9
%            Number of leaves      :    3
% Syntax   : Number of clauses     :   16 (  16 unt;   0 nHn;   4 RR)
%            Number of literals    :   16 (  15 equ;   3 neg)
%            Maximal clause size   :    1 (   1 avg)
%            Maximal term depth    :    7 (   2 avg)
%            Number of predicates  :    2 (   0 usr;   1 prp; 0-2 aty)
%            Number of functors    :    5 (   5 usr;   2 con; 0-2 aty)
%            Number of variables   :   44 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    multiply(multiply(inverse(b2),b2),a2) != a2,
    file('GRP467-1.p',unknown),
    [] ).

cnf(3,axiom,
    divide(divide(A,A),divide(B,divide(divide(C,divide(D,B)),inverse(D)))) = C,
    file('GRP467-1.p',unknown),
    [] ).

cnf(5,axiom,
    multiply(A,B) = divide(A,inverse(B)),
    file('GRP467-1.p',unknown),
    [] ).

cnf(6,plain,
    divide(A,inverse(B)) = multiply(A,B),
    inference(flip,[status(thm),theory(equality)],[inference(copy,[status(thm)],[5])]),
    [iquote('copy,5,flip.1')] ).

cnf(8,plain,
    multiply(divide(inverse(b2),inverse(b2)),a2) != a2,
    inference(para_from,[status(thm),theory(equality)],[5,1]),
    [iquote('para_from,5.1.1,1.1.1.1')] ).

cnf(14,plain,
    divide(divide(A,A),divide(divide(B,divide(divide(C,divide(D,B)),inverse(D))),divide(divide(E,C),inverse(divide(F,F))))) = E,
    inference(para_into,[status(thm),theory(equality)],[3,3]),
    [iquote('para_into,3.1.1.2.2.1.2,3.1.1')] ).

cnf(17,plain,
    divide(divide(A,A),divide(B,multiply(divide(C,divide(D,B)),D))) = C,
    inference(para_into,[status(thm),theory(equality)],[3,6]),
    [iquote('para_into,3.1.1.2.2,6.1.1')] ).

cnf(28,plain,
    divide(divide(A,A),divide(multiply(divide(B,divide(C,D)),C),multiply(B,D))) = divide(E,E),
    inference(para_into,[status(thm),theory(equality)],[17,17]),
    [iquote('para_into,17.1.1.2.2.1,17.1.1')] ).

cnf(170,plain,
    divide(A,A) = divide(B,B),
    inference(para_into,[status(thm),theory(equality)],[28,28]),
    [iquote('para_into,28.1.1,28.1.1')] ).

cnf(288,plain,
    divide(divide(A,A),divide(divide(B,divide(divide(C,divide(D,B)),inverse(D))),divide(divide(E,E),inverse(divide(F,F))))) = C,
    inference(para_from,[status(thm),theory(equality)],[170,14]),
    [iquote('para_from,170.1.1,14.1.1.2.2.1')] ).

cnf(294,plain,
    multiply(divide(A,A),a2) != a2,
    inference(para_from,[status(thm),theory(equality)],[170,8]),
    [iquote('para_from,170.1.1,8.1.1.1')] ).

cnf(296,plain,
    divide(divide(A,A),divide(B,multiply(divide(C,C),D))) = divide(D,B),
    inference(para_from,[status(thm),theory(equality)],[170,17]),
    [iquote('para_from,170.1.1,17.1.1.2.2.1')] ).

cnf(441,plain,
    divide(A,A) = divide(B,multiply(divide(C,C),B)),
    inference(para_into,[status(thm),theory(equality)],[296,170]),
    [iquote('para_into,296.1.1,170.1.1')] ).

cnf(446,plain,
    divide(A,multiply(divide(B,B),A)) = divide(C,C),
    inference(flip,[status(thm),theory(equality)],[inference(copy,[status(thm)],[441])]),
    [iquote('copy,441,flip.1')] ).

cnf(461,plain,
    multiply(divide(A,A),B) = B,
    inference(demod,[status(thm),theory(equality)],[inference(para_from,[status(thm),theory(equality)],[446,14]),288]),
    [iquote('para_from,446.1.1,14.1.1.2.2.1,demod,288')] ).

cnf(463,plain,
    $false,
    inference(binary,[status(thm)],[461,294]),
    [iquote('binary,461.1,294.1')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12  % Problem  : GRP467-1 : TPTP v8.1.0. Released v2.6.0.
% 0.03/0.12  % Command  : otter-tptp-script %s
% 0.12/0.33  % Computer : n015.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 300
% 0.12/0.33  % DateTime : Wed Jul 27 05:30:56 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 1.95/2.12  ----- Otter 3.3f, August 2004 -----
% 1.95/2.12  The process was started by sandbox2 on n015.cluster.edu,
% 1.95/2.12  Wed Jul 27 05:30:56 2022
% 1.95/2.12  The command was "./otter".  The process ID is 4382.
% 1.95/2.12  
% 1.95/2.12  set(prolog_style_variables).
% 1.95/2.12  set(auto).
% 1.95/2.12     dependent: set(auto1).
% 1.95/2.12     dependent: set(process_input).
% 1.95/2.12     dependent: clear(print_kept).
% 1.95/2.12     dependent: clear(print_new_demod).
% 1.95/2.12     dependent: clear(print_back_demod).
% 1.95/2.12     dependent: clear(print_back_sub).
% 1.95/2.12     dependent: set(control_memory).
% 1.95/2.12     dependent: assign(max_mem, 12000).
% 1.95/2.12     dependent: assign(pick_given_ratio, 4).
% 1.95/2.12     dependent: assign(stats_level, 1).
% 1.95/2.12     dependent: assign(max_seconds, 10800).
% 1.95/2.12  clear(print_given).
% 1.95/2.12  
% 1.95/2.12  list(usable).
% 1.95/2.12  0 [] A=A.
% 1.95/2.12  0 [] divide(divide(A,A),divide(B,divide(divide(C,divide(D,B)),inverse(D))))=C.
% 1.95/2.12  0 [] multiply(A,B)=divide(A,inverse(B)).
% 1.95/2.12  0 [] multiply(multiply(inverse(b2),b2),a2)!=a2.
% 1.95/2.12  end_of_list.
% 1.95/2.12  
% 1.95/2.12  SCAN INPUT: prop=0, horn=1, equality=1, symmetry=0, max_lits=1.
% 1.95/2.12  
% 1.95/2.12  All clauses are units, and equality is present; the
% 1.95/2.12  strategy will be Knuth-Bendix with positive clauses in sos.
% 1.95/2.12  
% 1.95/2.12     dependent: set(knuth_bendix).
% 1.95/2.12     dependent: set(anl_eq).
% 1.95/2.12     dependent: set(para_from).
% 1.95/2.12     dependent: set(para_into).
% 1.95/2.12     dependent: clear(para_from_right).
% 1.95/2.12     dependent: clear(para_into_right).
% 1.95/2.12     dependent: set(para_from_vars).
% 1.95/2.12     dependent: set(eq_units_both_ways).
% 1.95/2.12     dependent: set(dynamic_demod_all).
% 1.95/2.12     dependent: set(dynamic_demod).
% 1.95/2.12     dependent: set(order_eq).
% 1.95/2.12     dependent: set(back_demod).
% 1.95/2.12     dependent: set(lrpo).
% 1.95/2.12  
% 1.95/2.12  ------------> process usable:
% 1.95/2.12  ** KEPT (pick-wt=8): 1 [] multiply(multiply(inverse(b2),b2),a2)!=a2.
% 1.95/2.12  
% 1.95/2.12  ------------> process sos:
% 1.95/2.12  ** KEPT (pick-wt=3): 2 [] A=A.
% 1.95/2.12  ** KEPT (pick-wt=16): 3 [] divide(divide(A,A),divide(B,divide(divide(C,divide(D,B)),inverse(D))))=C.
% 1.95/2.12  ---> New Demodulator: 4 [new_demod,3] divide(divide(A,A),divide(B,divide(divide(C,divide(D,B)),inverse(D))))=C.
% 1.95/2.12  ** KEPT (pick-wt=8): 5 [] multiply(A,B)=divide(A,inverse(B)).
% 1.95/2.12    Following clause subsumed by 2 during input processing: 0 [copy,2,flip.1] A=A.
% 1.95/2.12  >>>> Starting back demodulation with 4.
% 1.95/2.12  ** KEPT (pick-wt=8): 6 [copy,5,flip.1] divide(A,inverse(B))=multiply(A,B).
% 1.95/2.12    Following clause subsumed by 5 during input processing: 0 [copy,6,flip.1] multiply(A,B)=divide(A,inverse(B)).
% 1.95/2.12  
% 1.95/2.12  ======= end of input processing =======
% 1.95/2.12  
% 1.95/2.12  =========== start of search ===========
% 1.95/2.12  
% 1.95/2.12  
% 1.95/2.12  Resetting weight limit to 16.
% 1.95/2.12  
% 1.95/2.12  
% 1.95/2.12  Resetting weight limit to 16.
% 1.95/2.12  
% 1.95/2.12  sos_size=324
% 1.95/2.12  
% 1.95/2.12  -------- PROOF -------- 
% 1.95/2.12  
% 1.95/2.12  ----> UNIT CONFLICT at   0.02 sec ----> 463 [binary,461.1,294.1] $F.
% 1.95/2.12  
% 1.95/2.12  Length of proof is 12.  Level of proof is 8.
% 1.95/2.12  
% 1.95/2.12  ---------------- PROOF ----------------
% 1.95/2.12  % SZS status Unsatisfiable
% 1.95/2.12  % SZS output start Refutation
% See solution above
% 1.95/2.12  ------------ end of proof -------------
% 1.95/2.12  
% 1.95/2.12  
% 1.95/2.12  Search stopped by max_proofs option.
% 1.95/2.12  
% 1.95/2.12  
% 1.95/2.12  Search stopped by max_proofs option.
% 1.95/2.12  
% 1.95/2.12  ============ end of search ============
% 1.95/2.12  
% 1.95/2.12  -------------- statistics -------------
% 1.95/2.12  clauses given                 29
% 1.95/2.12  clauses generated            520
% 1.95/2.12  clauses kept                 374
% 1.95/2.12  clauses forward subsumed     317
% 1.95/2.12  clauses back subsumed          4
% 1.95/2.12  Kbytes malloced             4882
% 1.95/2.12  
% 1.95/2.12  ----------- times (seconds) -----------
% 1.95/2.12  user CPU time          0.02          (0 hr, 0 min, 0 sec)
% 1.95/2.12  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.95/2.12  wall-clock time        2             (0 hr, 0 min, 2 sec)
% 1.95/2.12  
% 1.95/2.12  That finishes the proof of the theorem.
% 1.95/2.12  
% 1.95/2.12  Process 4382 finished Wed Jul 27 05:30:58 2022
% 1.95/2.12  Otter interrupted
% 1.95/2.12  PROOF FOUND
%------------------------------------------------------------------------------