TSTP Solution File: GRP409-1 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : GRP409-1 : TPTP v8.1.0. Released v2.6.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n014.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 12:56:57 EDT 2022

% Result   : Unsatisfiable 1.68s 1.89s
% Output   : Refutation 1.68s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    8
%            Number of leaves      :    2
% Syntax   : Number of clauses     :   14 (  14 unt;   0 nHn;   4 RR)
%            Number of literals    :   14 (  13 equ;   3 neg)
%            Maximal clause size   :    1 (   1 avg)
%            Maximal term depth    :   10 (   3 avg)
%            Number of predicates  :    2 (   0 usr;   1 prp; 0-2 aty)
%            Number of functors    :    4 (   4 usr;   2 con; 0-2 aty)
%            Number of variables   :   40 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    multiply(inverse(a1),a1) != multiply(inverse(b1),b1),
    file('GRP409-1.p',unknown),
    [] ).

cnf(2,plain,
    multiply(inverse(b1),b1) != multiply(inverse(a1),a1),
    inference(flip,[status(thm),theory(equality)],[inference(copy,[status(thm)],[1])]),
    [iquote('copy,1,flip.1')] ).

cnf(4,axiom,
    multiply(multiply(inverse(multiply(A,inverse(multiply(B,C)))),multiply(A,inverse(C))),inverse(multiply(inverse(C),C))) = B,
    file('GRP409-1.p',unknown),
    [] ).

cnf(6,plain,
    multiply(multiply(inverse(multiply(A,inverse(B))),multiply(A,inverse(inverse(multiply(inverse(C),C))))),inverse(multiply(inverse(inverse(multiply(inverse(C),C))),inverse(multiply(inverse(C),C))))) = multiply(inverse(multiply(D,inverse(multiply(B,C)))),multiply(D,inverse(C))),
    inference(para_into,[status(thm),theory(equality)],[4,4]),
    [iquote('para_into,4.1.1.1.1.1.2.1,4.1.1')] ).

cnf(10,plain,
    multiply(multiply(inverse(multiply(multiply(inverse(multiply(A,inverse(multiply(B,C)))),multiply(A,inverse(C))),inverse(multiply(D,multiply(inverse(C),C))))),B),inverse(multiply(inverse(multiply(inverse(C),C)),multiply(inverse(C),C)))) = D,
    inference(para_into,[status(thm),theory(equality)],[4,4]),
    [iquote('para_into,4.1.1.1.2,4.1.1')] ).

cnf(89,plain,
    multiply(inverse(multiply(A,inverse(multiply(B,C)))),multiply(A,inverse(C))) = multiply(inverse(multiply(D,inverse(multiply(B,C)))),multiply(D,inverse(C))),
    inference(para_into,[status(thm),theory(equality)],[6,6]),
    [iquote('para_into,6.1.1,6.1.1')] ).

cnf(91,plain,
    multiply(inverse(multiply(A,inverse(multiply(multiply(B,inverse(multiply(inverse(C),C))),C)))),multiply(A,inverse(C))) = B,
    inference(flip,[status(thm),theory(equality)],[inference(para_into,[status(thm),theory(equality)],[6,4])]),
    [iquote('para_into,6.1.1,4.1.1,flip.1')] ).

cnf(128,plain,
    multiply(inverse(multiply(A,inverse(B))),multiply(A,inverse(multiply(C,inverse(D))))) = multiply(inverse(multiply(E,inverse(B))),multiply(E,inverse(multiply(C,inverse(D))))),
    inference(demod,[status(thm),theory(equality)],[inference(para_into,[status(thm),theory(equality)],[89,91]),91]),
    [iquote('para_into,89.1.1.1.1.2.1,90.1.1,demod,91')] ).

cnf(133,plain,
    multiply(inverse(multiply(A,inverse(B))),multiply(A,inverse(C))) = multiply(inverse(multiply(D,inverse(B))),multiply(D,inverse(C))),
    inference(demod,[status(thm),theory(equality)],[inference(para_into,[status(thm),theory(equality)],[128,10]),10]),
    [iquote('para_into,128.1.1.2.2.1,9.1.1,demod,10')] ).

cnf(138,plain,
    multiply(inverse(A),multiply(multiply(inverse(multiply(B,inverse(multiply(A,C)))),multiply(B,inverse(C))),inverse(D))) = multiply(inverse(multiply(E,inverse(multiply(inverse(C),C)))),multiply(E,inverse(D))),
    inference(para_into,[status(thm),theory(equality)],[133,4]),
    [iquote('para_into,133.1.1.1.1,4.1.1')] ).

cnf(158,plain,
    multiply(inverse(A),A) = multiply(inverse(multiply(B,inverse(multiply(inverse(C),C)))),multiply(B,inverse(multiply(inverse(C),C)))),
    inference(para_into,[status(thm),theory(equality)],[138,4]),
    [iquote('para_into,138.1.1.2,4.1.1')] ).

cnf(160,plain,
    multiply(inverse(multiply(A,inverse(multiply(inverse(B),B)))),multiply(A,inverse(multiply(inverse(B),B)))) = multiply(inverse(C),C),
    inference(flip,[status(thm),theory(equality)],[inference(copy,[status(thm)],[158])]),
    [iquote('copy,158,flip.1')] ).

cnf(188,plain,
    multiply(inverse(multiply(A,inverse(multiply(inverse(B),B)))),multiply(A,inverse(multiply(inverse(B),B)))) != multiply(inverse(a1),a1),
    inference(para_from,[status(thm),theory(equality)],[158,2]),
    [iquote('para_from,158.1.1,2.1.1')] ).

cnf(189,plain,
    $false,
    inference(binary,[status(thm)],[188,160]),
    [iquote('binary,188.1,160.1')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.12  % Problem  : GRP409-1 : TPTP v8.1.0. Released v2.6.0.
% 0.11/0.12  % Command  : otter-tptp-script %s
% 0.13/0.33  % Computer : n014.cluster.edu
% 0.13/0.33  % Model    : x86_64 x86_64
% 0.13/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.33  % Memory   : 8042.1875MB
% 0.13/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.33  % CPULimit : 300
% 0.13/0.33  % WCLimit  : 300
% 0.13/0.33  % DateTime : Wed Jul 27 05:09:09 EDT 2022
% 0.13/0.33  % CPUTime  : 
% 1.68/1.89  ----- Otter 3.3f, August 2004 -----
% 1.68/1.89  The process was started by sandbox2 on n014.cluster.edu,
% 1.68/1.89  Wed Jul 27 05:09:09 2022
% 1.68/1.89  The command was "./otter".  The process ID is 14089.
% 1.68/1.89  
% 1.68/1.89  set(prolog_style_variables).
% 1.68/1.89  set(auto).
% 1.68/1.89     dependent: set(auto1).
% 1.68/1.89     dependent: set(process_input).
% 1.68/1.89     dependent: clear(print_kept).
% 1.68/1.89     dependent: clear(print_new_demod).
% 1.68/1.89     dependent: clear(print_back_demod).
% 1.68/1.89     dependent: clear(print_back_sub).
% 1.68/1.89     dependent: set(control_memory).
% 1.68/1.89     dependent: assign(max_mem, 12000).
% 1.68/1.89     dependent: assign(pick_given_ratio, 4).
% 1.68/1.89     dependent: assign(stats_level, 1).
% 1.68/1.89     dependent: assign(max_seconds, 10800).
% 1.68/1.89  clear(print_given).
% 1.68/1.89  
% 1.68/1.89  list(usable).
% 1.68/1.89  0 [] A=A.
% 1.68/1.89  0 [] multiply(multiply(inverse(multiply(A,inverse(multiply(B,C)))),multiply(A,inverse(C))),inverse(multiply(inverse(C),C)))=B.
% 1.68/1.89  0 [] multiply(inverse(a1),a1)!=multiply(inverse(b1),b1).
% 1.68/1.89  end_of_list.
% 1.68/1.89  
% 1.68/1.89  SCAN INPUT: prop=0, horn=1, equality=1, symmetry=0, max_lits=1.
% 1.68/1.89  
% 1.68/1.89  All clauses are units, and equality is present; the
% 1.68/1.89  strategy will be Knuth-Bendix with positive clauses in sos.
% 1.68/1.89  
% 1.68/1.89     dependent: set(knuth_bendix).
% 1.68/1.89     dependent: set(anl_eq).
% 1.68/1.89     dependent: set(para_from).
% 1.68/1.89     dependent: set(para_into).
% 1.68/1.89     dependent: clear(para_from_right).
% 1.68/1.89     dependent: clear(para_into_right).
% 1.68/1.89     dependent: set(para_from_vars).
% 1.68/1.89     dependent: set(eq_units_both_ways).
% 1.68/1.89     dependent: set(dynamic_demod_all).
% 1.68/1.89     dependent: set(dynamic_demod).
% 1.68/1.89     dependent: set(order_eq).
% 1.68/1.89     dependent: set(back_demod).
% 1.68/1.89     dependent: set(lrpo).
% 1.68/1.89  
% 1.68/1.89  ------------> process usable:
% 1.68/1.89  ** KEPT (pick-wt=9): 2 [copy,1,flip.1] multiply(inverse(b1),b1)!=multiply(inverse(a1),a1).
% 1.68/1.89  
% 1.68/1.89  ------------> process sos:
% 1.68/1.89  ** KEPT (pick-wt=3): 3 [] A=A.
% 1.68/1.89  ** KEPT (pick-wt=20): 4 [] multiply(multiply(inverse(multiply(A,inverse(multiply(B,C)))),multiply(A,inverse(C))),inverse(multiply(inverse(C),C)))=B.
% 1.68/1.89  ---> New Demodulator: 5 [new_demod,4] multiply(multiply(inverse(multiply(A,inverse(multiply(B,C)))),multiply(A,inverse(C))),inverse(multiply(inverse(C),C)))=B.
% 1.68/1.89    Following clause subsumed by 3 during input processing: 0 [copy,3,flip.1] A=A.
% 1.68/1.89  >>>> Starting back demodulation with 5.
% 1.68/1.89  
% 1.68/1.89  ======= end of input processing =======
% 1.68/1.89  
% 1.68/1.89  =========== start of search ===========
% 1.68/1.89  
% 1.68/1.89  
% 1.68/1.89  Resetting weight limit to 44.
% 1.68/1.89  
% 1.68/1.89  
% 1.68/1.89  Resetting weight limit to 44.
% 1.68/1.89  
% 1.68/1.89  sos_size=60
% 1.68/1.89  
% 1.68/1.89  -------- PROOF -------- 
% 1.68/1.89  
% 1.68/1.89  ----> UNIT CONFLICT at   0.01 sec ----> 189 [binary,188.1,160.1] $F.
% 1.68/1.89  
% 1.68/1.89  Length of proof is 11.  Level of proof is 7.
% 1.68/1.89  
% 1.68/1.89  ---------------- PROOF ----------------
% 1.68/1.89  % SZS status Unsatisfiable
% 1.68/1.89  % SZS output start Refutation
% See solution above
% 1.68/1.89  ------------ end of proof -------------
% 1.68/1.89  
% 1.68/1.89  
% 1.68/1.89  Search stopped by max_proofs option.
% 1.68/1.89  
% 1.68/1.89  
% 1.68/1.89  Search stopped by max_proofs option.
% 1.68/1.89  
% 1.68/1.89  ============ end of search ============
% 1.68/1.89  
% 1.68/1.89  -------------- statistics -------------
% 1.68/1.89  clauses given                 13
% 1.68/1.89  clauses generated            310
% 1.68/1.89  clauses kept                 123
% 1.68/1.89  clauses forward subsumed     118
% 1.68/1.89  clauses back subsumed         18
% 1.68/1.89  Kbytes malloced             6835
% 1.68/1.89  
% 1.68/1.89  ----------- times (seconds) -----------
% 1.68/1.89  user CPU time          0.01          (0 hr, 0 min, 0 sec)
% 1.68/1.89  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.68/1.89  wall-clock time        1             (0 hr, 0 min, 1 sec)
% 1.68/1.89  
% 1.68/1.89  That finishes the proof of the theorem.
% 1.68/1.89  
% 1.68/1.89  Process 14089 finished Wed Jul 27 05:09:10 2022
% 1.68/1.89  Otter interrupted
% 1.68/1.89  PROOF FOUND
%------------------------------------------------------------------------------