TSTP Solution File: GRP047-2 by SOS---2.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SOS---2.0
% Problem  : GRP047-2 : TPTP v8.1.0. Released v1.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : sos-script %s

% Computer : n025.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Sat Jul 16 11:41:12 EDT 2022

% Result   : Unsatisfiable 0.20s 0.40s
% Output   : Refutation 0.20s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem  : GRP047-2 : TPTP v8.1.0. Released v1.0.0.
% 0.00/0.12  % Command  : sos-script %s
% 0.13/0.33  % Computer : n025.cluster.edu
% 0.13/0.33  % Model    : x86_64 x86_64
% 0.13/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.33  % Memory   : 8042.1875MB
% 0.13/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.33  % CPULimit : 300
% 0.13/0.33  % WCLimit  : 600
% 0.13/0.33  % DateTime : Mon Jun 13 12:13:39 EDT 2022
% 0.13/0.33  % CPUTime  : 
% 0.20/0.35  ----- Otter 3.2, August 2001 -----
% 0.20/0.35  The process was started by sandbox2 on n025.cluster.edu,
% 0.20/0.35  Mon Jun 13 12:13:39 2022
% 0.20/0.35  The command was "./sos".  The process ID is 23662.
% 0.20/0.35  
% 0.20/0.35  set(prolog_style_variables).
% 0.20/0.35  set(auto).
% 0.20/0.35     dependent: set(auto1).
% 0.20/0.35     dependent: set(process_input).
% 0.20/0.35     dependent: clear(print_kept).
% 0.20/0.35     dependent: clear(print_new_demod).
% 0.20/0.35     dependent: clear(print_back_demod).
% 0.20/0.35     dependent: clear(print_back_sub).
% 0.20/0.35     dependent: set(control_memory).
% 0.20/0.35     dependent: assign(max_mem, 12000).
% 0.20/0.35     dependent: assign(pick_given_ratio, 4).
% 0.20/0.35     dependent: assign(stats_level, 1).
% 0.20/0.35     dependent: assign(pick_semantic_ratio, 3).
% 0.20/0.35     dependent: assign(sos_limit, 5000).
% 0.20/0.35     dependent: assign(max_weight, 60).
% 0.20/0.35  clear(print_given).
% 0.20/0.35  
% 0.20/0.35  list(usable).
% 0.20/0.35  
% 0.20/0.35  SCAN INPUT: prop=0, horn=1, equality=1, symmetry=0, max_lits=4.
% 0.20/0.35  
% 0.20/0.35  This is a Horn set with equality.  The strategy will be
% 0.20/0.35  Knuth-Bendix and hyper_res, with positive clauses in
% 0.20/0.35  sos and nonpositive clauses in usable.
% 0.20/0.35  
% 0.20/0.35     dependent: set(knuth_bendix).
% 0.20/0.35     dependent: set(para_from).
% 0.20/0.35     dependent: set(para_into).
% 0.20/0.35     dependent: clear(para_from_right).
% 0.20/0.35     dependent: clear(para_into_right).
% 0.20/0.35     dependent: set(para_from_vars).
% 0.20/0.35     dependent: set(eq_units_both_ways).
% 0.20/0.35     dependent: set(dynamic_demod_all).
% 0.20/0.35     dependent: set(dynamic_demod).
% 0.20/0.35     dependent: set(order_eq).
% 0.20/0.35     dependent: set(back_demod).
% 0.20/0.35     dependent: set(lrpo).
% 0.20/0.35     dependent: set(hyper_res).
% 0.20/0.35     dependent: clear(order_hyper).
% 0.20/0.35  
% 0.20/0.35  ------------> process usable:
% 0.20/0.35  
% 0.20/0.35  ------------> process sos:
% 0.20/0.35    Following clause subsumed by 13 during input processing: 0 [copy,13,flip.1] {-} -equalish(multiply(c,a),multiply(c,a)).
% 0.20/0.35  
% 0.20/0.35  ======= end of input processing =======
% 0.20/0.40  
% 0.20/0.40  Model 1 (0.00 seconds, 0 Inserts)
% 0.20/0.40  
% 0.20/0.40  Stopped by limit on number of solutions
% 0.20/0.40  
% 0.20/0.40  
% 0.20/0.40  -------------- Softie stats --------------
% 0.20/0.40  
% 0.20/0.40  UPDATE_STOP: 300
% 0.20/0.40  SFINDER_TIME_LIMIT: 2
% 0.20/0.40  SHORT_CLAUSE_CUTOFF: 4
% 0.20/0.40  number of clauses in intial UL: 4
% 0.20/0.40  number of clauses initially in problem: 10
% 0.20/0.40  percentage of clauses intially in UL: 40
% 0.20/0.40  percentage of distinct symbols occuring in initial UL: 25
% 0.20/0.40  percent of all initial clauses that are short: 100
% 0.20/0.40  absolute distinct symbol count: 8
% 0.20/0.40     distinct predicate count: 2
% 0.20/0.40     distinct function count: 2
% 0.20/0.40     distinct constant count: 4
% 0.20/0.40  
% 0.20/0.40  ---------- no more Softie stats ----------
% 0.20/0.40  
% 0.20/0.40  
% 0.20/0.40  
% 0.20/0.40  Model 2 (0.00 seconds, 0 Inserts)
% 0.20/0.40  
% 0.20/0.40  Stopped by limit on number of solutions
% 0.20/0.40  
% 0.20/0.40  =========== start of search ===========
% 0.20/0.40  
% 0.20/0.40  -------- PROOF -------- 
% 0.20/0.40  % SZS status Unsatisfiable
% 0.20/0.40  % SZS output start Refutation
% 0.20/0.40  
% 0.20/0.40  ----> UNIT CONFLICT at   0.02 sec ----> 15 [binary,14.1,13.1] {-} $F.
% 0.20/0.40  
% 0.20/0.40  Length of proof is 4.  Level of proof is 2.
% 0.20/0.40  
% 0.20/0.40  ---------------- PROOF ----------------
% 0.20/0.40  % SZS status Unsatisfiable
% 0.20/0.40  % SZS output start Refutation
% 0.20/0.40  
% 0.20/0.40  1 [] {+} -product(A,B,C)| -product(A,B,D)|equalish(C,D).
% 0.20/0.40  5 [] {-} -equalish(multiply(c,a),multiply(c,b)).
% 0.20/0.40  6 [copy,5,flip.1] {-} -equalish(multiply(c,b),multiply(c,a)).
% 0.20/0.40  7 [] {+} product(identity,A,A).
% 0.20/0.40  10 [] {-} equalish(a,b).
% 0.20/0.40  12,11 [copy,10,flip.1] {+} equalish(b,a).
% 0.20/0.40  13 [back_demod,6,demod,12] {-} -equalish(multiply(c,a),multiply(c,a)).
% 0.20/0.40  14 [hyper,7,1,7] {-} equalish(A,A).
% 0.20/0.40  15 [binary,14.1,13.1] {-} $F.
% 0.20/0.40  
% 0.20/0.40  % SZS output end Refutation
% 0.20/0.40  ------------ end of proof -------------
% 0.20/0.40  
% 0.20/0.40  
% 0.20/0.40  Search stopped by max_proofs option.
% 0.20/0.40  
% 0.20/0.40  
% 0.20/0.40  Search stopped by max_proofs option.
% 0.20/0.40  
% 0.20/0.40  ============ end of search ============
% 0.20/0.40  
% 0.20/0.40  ----------- soft-scott stats ----------
% 0.20/0.40  
% 0.20/0.40  true clauses given           0      (0.0%)
% 0.20/0.40  false clauses given          1
% 0.20/0.40  
% 0.20/0.40        FALSE     TRUE
% 0.20/0.40     3  0         1
% 0.20/0.40     5  1         0
% 0.20/0.40     6  1         0
% 0.20/0.40     7  1         0
% 0.20/0.40  tot:  3         1      (25.0% true)
% 0.20/0.40  
% 0.20/0.40  
% 0.20/0.40  Model 2 (0.00 seconds, 0 Inserts)
% 0.20/0.40  
% 0.20/0.40  That finishes the proof of the theorem.
% 0.20/0.40  
% 0.20/0.40  Process 23662 finished Mon Jun 13 12:13:39 2022
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