TSTP Solution File: GRP022-2 by Prover9---1109a
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- Process Solution
%------------------------------------------------------------------------------
% File : Prover9---1109a
% Problem : GRP022-2 : TPTP v8.1.0. Released v1.0.0.
% Transfm : none
% Format : tptp:raw
% Command : tptp2X_and_run_prover9 %d %s
% Computer : n006.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Sat Jul 16 11:16:45 EDT 2022
% Result : Unsatisfiable 0.44s 1.01s
% Output : Refutation 0.44s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12 % Problem : GRP022-2 : TPTP v8.1.0. Released v1.0.0.
% 0.03/0.13 % Command : tptp2X_and_run_prover9 %d %s
% 0.13/0.34 % Computer : n006.cluster.edu
% 0.13/0.34 % Model : x86_64 x86_64
% 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34 % Memory : 8042.1875MB
% 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34 % CPULimit : 300
% 0.13/0.34 % WCLimit : 600
% 0.13/0.34 % DateTime : Tue Jun 14 14:00:26 EDT 2022
% 0.13/0.34 % CPUTime :
% 0.44/1.01 ============================== Prover9 ===============================
% 0.44/1.01 Prover9 (32) version 2009-11A, November 2009.
% 0.44/1.01 Process 11406 was started by sandbox on n006.cluster.edu,
% 0.44/1.01 Tue Jun 14 14:00:27 2022
% 0.44/1.01 The command was "/export/starexec/sandbox/solver/bin/prover9 -t 300 -f /tmp/Prover9_11236_n006.cluster.edu".
% 0.44/1.01 ============================== end of head ===========================
% 0.44/1.01
% 0.44/1.01 ============================== INPUT =================================
% 0.44/1.01
% 0.44/1.01 % Reading from file /tmp/Prover9_11236_n006.cluster.edu
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% 0.44/1.01 set(prolog_style_variables).
% 0.44/1.01 set(auto2).
% 0.44/1.01 % set(auto2) -> set(auto).
% 0.44/1.01 % set(auto) -> set(auto_inference).
% 0.44/1.01 % set(auto) -> set(auto_setup).
% 0.44/1.01 % set(auto_setup) -> set(predicate_elim).
% 0.44/1.01 % set(auto_setup) -> assign(eq_defs, unfold).
% 0.44/1.01 % set(auto) -> set(auto_limits).
% 0.44/1.01 % set(auto_limits) -> assign(max_weight, "100.000").
% 0.44/1.01 % set(auto_limits) -> assign(sos_limit, 20000).
% 0.44/1.01 % set(auto) -> set(auto_denials).
% 0.44/1.01 % set(auto) -> set(auto_process).
% 0.44/1.01 % set(auto2) -> assign(new_constants, 1).
% 0.44/1.01 % set(auto2) -> assign(fold_denial_max, 3).
% 0.44/1.01 % set(auto2) -> assign(max_weight, "200.000").
% 0.44/1.01 % set(auto2) -> assign(max_hours, 1).
% 0.44/1.01 % assign(max_hours, 1) -> assign(max_seconds, 3600).
% 0.44/1.01 % set(auto2) -> assign(max_seconds, 0).
% 0.44/1.01 % set(auto2) -> assign(max_minutes, 5).
% 0.44/1.01 % assign(max_minutes, 5) -> assign(max_seconds, 300).
% 0.44/1.01 % set(auto2) -> set(sort_initial_sos).
% 0.44/1.01 % set(auto2) -> assign(sos_limit, -1).
% 0.44/1.01 % set(auto2) -> assign(lrs_ticks, 3000).
% 0.44/1.01 % set(auto2) -> assign(max_megs, 400).
% 0.44/1.01 % set(auto2) -> assign(stats, some).
% 0.44/1.01 % set(auto2) -> clear(echo_input).
% 0.44/1.01 % set(auto2) -> set(quiet).
% 0.44/1.01 % set(auto2) -> clear(print_initial_clauses).
% 0.44/1.01 % set(auto2) -> clear(print_given).
% 0.44/1.01 assign(lrs_ticks,-1).
% 0.44/1.01 assign(sos_limit,10000).
% 0.44/1.01 assign(order,kbo).
% 0.44/1.01 set(lex_order_vars).
% 0.44/1.01 clear(print_given).
% 0.44/1.01
% 0.44/1.01 % formulas(sos). % not echoed (6 formulas)
% 0.44/1.01
% 0.44/1.01 ============================== end of input ==========================
% 0.44/1.01
% 0.44/1.01 % From the command line: assign(max_seconds, 300).
% 0.44/1.01
% 0.44/1.01 ============================== PROCESS NON-CLAUSAL FORMULAS ==========
% 0.44/1.01
% 0.44/1.01 % Formulas that are not ordinary clauses:
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% 0.44/1.01 ============================== end of process non-clausal formulas ===
% 0.44/1.01
% 0.44/1.01 ============================== PROCESS INITIAL CLAUSES ===============
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% 0.44/1.01 ============================== PREDICATE ELIMINATION =================
% 0.44/1.01
% 0.44/1.01 ============================== end predicate elimination =============
% 0.44/1.01
% 0.44/1.01 Auto_denials:
% 0.44/1.01 % copying label prove_inverse_of_inverse_is_original to answer in negative clause
% 0.44/1.01
% 0.44/1.01 Term ordering decisions:
% 0.44/1.01
% 0.44/1.01 % Assigning unary symbol inverse kb_weight 0 and highest precedence (5).
% 0.44/1.01 Function symbol KB weights: identity=1. a=1. multiply=1. inverse=0.
% 0.44/1.01
% 0.44/1.01 ============================== end of process initial clauses ========
% 0.44/1.01
% 0.44/1.01 ============================== CLAUSES FOR SEARCH ====================
% 0.44/1.01
% 0.44/1.01 ============================== end of clauses for search =============
% 0.44/1.01
% 0.44/1.01 ============================== SEARCH ================================
% 0.44/1.01
% 0.44/1.01 % Starting search at 0.01 seconds.
% 0.44/1.01
% 0.44/1.01 ============================== PROOF =================================
% 0.44/1.01 % SZS status Unsatisfiable
% 0.44/1.01 % SZS output start Refutation
% 0.44/1.01
% 0.44/1.01 % Proof 1 at 0.01 (+ 0.00) seconds: prove_inverse_of_inverse_is_original.
% 0.44/1.01 % Length of proof is 8.
% 0.44/1.01 % Level of proof is 3.
% 0.44/1.01 % Maximum clause weight is 11.000.
% 0.44/1.01 % Given clauses 8.
% 0.44/1.01
% 0.44/1.01 1 multiply(identity,A) = A # label(left_identity) # label(axiom). [assumption].
% 0.44/1.01 2 multiply(A,identity) = A # label(right_identity) # label(axiom). [assumption].
% 0.44/1.01 3 multiply(inverse(A),A) = identity # label(left_inverse) # label(axiom). [assumption].
% 0.44/1.01 5 multiply(multiply(A,B),C) = multiply(A,multiply(B,C)) # label(associativity) # label(axiom). [assumption].
% 0.44/1.01 6 inverse(inverse(a)) != a # label(prove_inverse_of_inverse_is_original) # label(negated_conjecture) # answer(prove_inverse_of_inverse_is_original). [assumption].
% 0.44/1.01 8 multiply(inverse(A),multiply(A,B)) = B. [para(3(a,1),5(a,1,1)),rewrite([1(2)]),flip(a)].
% 0.44/1.01 11 inverse(inverse(A)) = A. [para(3(a,1),8(a,1,2)),rewrite([2(4)])].
% 0.44/1.01 12 $F # answer(prove_inverse_of_inverse_is_original). [resolve(11,a,6,a)].
% 0.44/1.01
% 0.44/1.01 % SZS output end Refutation
% 0.44/1.01 ============================== end of proof ==========================
% 0.44/1.01
% 0.44/1.01 ============================== STATISTICS ============================
% 0.44/1.01
% 0.44/1.01 Given=8. Generated=38. Kept=11. proofs=1.
% 0.44/1.01 Usable=8. Sos=2. Demods=9. Limbo=0, Disabled=6. Hints=0.
% 0.44/1.01 Megabytes=0.03.
% 0.44/1.01 User_CPU=0.01, System_CPU=0.00, Wall_clock=0.
% 0.44/1.01
% 0.44/1.01 ============================== end of statistics =====================
% 0.44/1.01
% 0.44/1.01 ============================== end of search =========================
% 0.44/1.01
% 0.44/1.01 THEOREM PROVED
% 0.44/1.01 % SZS status Unsatisfiable
% 0.44/1.01
% 0.44/1.01 Exiting with 1 proof.
% 0.44/1.01
% 0.44/1.01 Process 11406 exit (max_proofs) Tue Jun 14 14:00:27 2022
% 0.44/1.01 Prover9 interrupted
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