TSTP Solution File: GRP022-2 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : GRP022-2 : TPTP v8.1.0. Released v1.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n010.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 12:55:53 EDT 2022

% Result   : Unsatisfiable 1.22s 1.74s
% Output   : Refutation 1.22s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    3
%            Number of leaves      :    5
% Syntax   : Number of clauses     :    8 (   8 unt;   0 nHn;   2 RR)
%            Number of literals    :    8 (   7 equ;   1 neg)
%            Maximal clause size   :    1 (   1 avg)
%            Maximal term depth    :    3 (   2 avg)
%            Number of predicates  :    2 (   0 usr;   1 prp; 0-2 aty)
%            Number of functors    :    4 (   4 usr;   2 con; 0-2 aty)
%            Number of variables   :    9 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    inverse(inverse(a)) != a,
    file('GRP022-2.p',unknown),
    [] ).

cnf(4,axiom,
    multiply(identity,A) = A,
    file('GRP022-2.p',unknown),
    [] ).

cnf(5,axiom,
    multiply(inverse(A),A) = identity,
    file('GRP022-2.p',unknown),
    [] ).

cnf(7,axiom,
    multiply(multiply(A,B),C) = multiply(A,multiply(B,C)),
    file('GRP022-2.p',unknown),
    [] ).

cnf(10,axiom,
    multiply(A,identity) = A,
    file('GRP022-2.p',unknown),
    [] ).

cnf(15,plain,
    multiply(inverse(A),multiply(A,B)) = B,
    inference(flip,[status(thm),theory(equality)],[inference(demod,[status(thm),theory(equality)],[inference(para_into,[status(thm),theory(equality)],[7,5]),4])]),
    [iquote('para_into,7.1.1.1,5.1.1,demod,4,flip.1')] ).

cnf(25,plain,
    inverse(inverse(A)) = A,
    inference(demod,[status(thm),theory(equality)],[inference(para_into,[status(thm),theory(equality)],[15,5]),10]),
    [iquote('para_into,15.1.1.2,5.1.1,demod,10')] ).

cnf(27,plain,
    $false,
    inference(binary,[status(thm)],[25,1]),
    [iquote('binary,25.1,1.1')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.11  % Problem  : GRP022-2 : TPTP v8.1.0. Released v1.0.0.
% 0.11/0.12  % Command  : otter-tptp-script %s
% 0.12/0.33  % Computer : n010.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 300
% 0.12/0.33  % DateTime : Wed Jul 27 05:26:54 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 1.22/1.74  ----- Otter 3.3f, August 2004 -----
% 1.22/1.74  The process was started by sandbox on n010.cluster.edu,
% 1.22/1.74  Wed Jul 27 05:26:55 2022
% 1.22/1.74  The command was "./otter".  The process ID is 31962.
% 1.22/1.74  
% 1.22/1.74  set(prolog_style_variables).
% 1.22/1.74  set(auto).
% 1.22/1.74     dependent: set(auto1).
% 1.22/1.74     dependent: set(process_input).
% 1.22/1.74     dependent: clear(print_kept).
% 1.22/1.74     dependent: clear(print_new_demod).
% 1.22/1.74     dependent: clear(print_back_demod).
% 1.22/1.74     dependent: clear(print_back_sub).
% 1.22/1.74     dependent: set(control_memory).
% 1.22/1.74     dependent: assign(max_mem, 12000).
% 1.22/1.74     dependent: assign(pick_given_ratio, 4).
% 1.22/1.74     dependent: assign(stats_level, 1).
% 1.22/1.74     dependent: assign(max_seconds, 10800).
% 1.22/1.74  clear(print_given).
% 1.22/1.74  
% 1.22/1.74  list(usable).
% 1.22/1.74  0 [] A=A.
% 1.22/1.74  0 [] multiply(identity,X)=X.
% 1.22/1.74  0 [] multiply(inverse(X),X)=identity.
% 1.22/1.74  0 [] multiply(multiply(X,Y),Z)=multiply(X,multiply(Y,Z)).
% 1.22/1.74  0 [] multiply(X,identity)=X.
% 1.22/1.74  0 [] multiply(X,inverse(X))=identity.
% 1.22/1.74  0 [] inverse(inverse(a))!=a.
% 1.22/1.74  end_of_list.
% 1.22/1.74  
% 1.22/1.74  SCAN INPUT: prop=0, horn=1, equality=1, symmetry=0, max_lits=1.
% 1.22/1.74  
% 1.22/1.74  All clauses are units, and equality is present; the
% 1.22/1.74  strategy will be Knuth-Bendix with positive clauses in sos.
% 1.22/1.74  
% 1.22/1.74     dependent: set(knuth_bendix).
% 1.22/1.74     dependent: set(anl_eq).
% 1.22/1.74     dependent: set(para_from).
% 1.22/1.74     dependent: set(para_into).
% 1.22/1.74     dependent: clear(para_from_right).
% 1.22/1.74     dependent: clear(para_into_right).
% 1.22/1.74     dependent: set(para_from_vars).
% 1.22/1.74     dependent: set(eq_units_both_ways).
% 1.22/1.74     dependent: set(dynamic_demod_all).
% 1.22/1.74     dependent: set(dynamic_demod).
% 1.22/1.74     dependent: set(order_eq).
% 1.22/1.74     dependent: set(back_demod).
% 1.22/1.74     dependent: set(lrpo).
% 1.22/1.74  
% 1.22/1.74  ------------> process usable:
% 1.22/1.74  ** KEPT (pick-wt=5): 1 [] inverse(inverse(a))!=a.
% 1.22/1.74  
% 1.22/1.74  ------------> process sos:
% 1.22/1.74  ** KEPT (pick-wt=3): 2 [] A=A.
% 1.22/1.74  ** KEPT (pick-wt=5): 3 [] multiply(identity,A)=A.
% 1.22/1.74  ---> New Demodulator: 4 [new_demod,3] multiply(identity,A)=A.
% 1.22/1.74  ** KEPT (pick-wt=6): 5 [] multiply(inverse(A),A)=identity.
% 1.22/1.74  ---> New Demodulator: 6 [new_demod,5] multiply(inverse(A),A)=identity.
% 1.22/1.74  ** KEPT (pick-wt=11): 7 [] multiply(multiply(A,B),C)=multiply(A,multiply(B,C)).
% 1.22/1.74  ---> New Demodulator: 8 [new_demod,7] multiply(multiply(A,B),C)=multiply(A,multiply(B,C)).
% 1.22/1.74  ** KEPT (pick-wt=5): 9 [] multiply(A,identity)=A.
% 1.22/1.74  ---> New Demodulator: 10 [new_demod,9] multiply(A,identity)=A.
% 1.22/1.74  ** KEPT (pick-wt=6): 11 [] multiply(A,inverse(A))=identity.
% 1.22/1.74  ---> New Demodulator: 12 [new_demod,11] multiply(A,inverse(A))=identity.
% 1.22/1.74    Following clause subsumed by 2 during input processing: 0 [copy,2,flip.1] A=A.
% 1.22/1.74  >>>> Starting back demodulation with 4.
% 1.22/1.74  >>>> Starting back demodulation with 6.
% 1.22/1.74  >>>> Starting back demodulation with 8.
% 1.22/1.74  >>>> Starting back demodulation with 10.
% 1.22/1.74  >>>> Starting back demodulation with 12.
% 1.22/1.74  
% 1.22/1.74  ======= end of input processing =======
% 1.22/1.74  
% 1.22/1.74  =========== start of search ===========
% 1.22/1.74  
% 1.22/1.74  -------- PROOF -------- 
% 1.22/1.74  
% 1.22/1.74  ----> UNIT CONFLICT at   0.00 sec ----> 27 [binary,25.1,1.1] $F.
% 1.22/1.74  
% 1.22/1.74  Length of proof is 2.  Level of proof is 2.
% 1.22/1.74  
% 1.22/1.74  ---------------- PROOF ----------------
% 1.22/1.74  % SZS status Unsatisfiable
% 1.22/1.74  % SZS output start Refutation
% See solution above
% 1.22/1.74  ------------ end of proof -------------
% 1.22/1.74  
% 1.22/1.74  
% 1.22/1.74  Search stopped by max_proofs option.
% 1.22/1.74  
% 1.22/1.74  
% 1.22/1.74  Search stopped by max_proofs option.
% 1.22/1.74  
% 1.22/1.74  ============ end of search ============
% 1.22/1.74  
% 1.22/1.74  -------------- statistics -------------
% 1.22/1.74  clauses given                  8
% 1.22/1.74  clauses generated             36
% 1.22/1.74  clauses kept                  14
% 1.22/1.74  clauses forward subsumed      30
% 1.22/1.74  clauses back subsumed          0
% 1.22/1.74  Kbytes malloced              976
% 1.22/1.74  
% 1.22/1.74  ----------- times (seconds) -----------
% 1.22/1.74  user CPU time          0.00          (0 hr, 0 min, 0 sec)
% 1.22/1.74  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.22/1.74  wall-clock time        1             (0 hr, 0 min, 1 sec)
% 1.22/1.74  
% 1.22/1.74  That finishes the proof of the theorem.
% 1.22/1.74  
% 1.22/1.74  Process 31962 finished Wed Jul 27 05:26:56 2022
% 1.22/1.74  Otter interrupted
% 1.22/1.74  PROOF FOUND
%------------------------------------------------------------------------------