TSTP Solution File: GRP020-1 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : GRP020-1 : TPTP v8.1.0. Released v1.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n011.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 12:55:52 EDT 2022

% Result   : Unsatisfiable 1.80s 2.01s
% Output   : Refutation 1.80s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    2
%            Number of leaves      :    4
% Syntax   : Number of clauses     :    6 (   5 unt;   0 nHn;   3 RR)
%            Number of literals    :    8 (   3 equ;   3 neg)
%            Maximal clause size   :    3 (   1 avg)
%            Maximal term depth    :    3 (   1 avg)
%            Number of predicates  :    3 (   1 usr;   1 prp; 0-3 aty)
%            Number of functors    :    4 (   4 usr;   2 con; 0-2 aty)
%            Number of variables   :    8 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    ( ~ product(A,B,C)
    | ~ product(A,B,D)
    | C = D ),
    file('GRP020-1.p',unknown),
    [] ).

cnf(4,axiom,
    multiply(inverse(a),a) != identity,
    file('GRP020-1.p',unknown),
    [] ).

cnf(8,axiom,
    product(inverse(A),A,identity),
    file('GRP020-1.p',unknown),
    [] ).

cnf(10,axiom,
    product(A,B,multiply(A,B)),
    file('GRP020-1.p',unknown),
    [] ).

cnf(83,plain,
    multiply(inverse(A),A) = identity,
    inference(flip,[status(thm),theory(equality)],[inference(hyper,[status(thm)],[10,1,8])]),
    [iquote('hyper,10,1,8,flip.1')] ).

cnf(85,plain,
    $false,
    inference(binary,[status(thm)],[83,4]),
    [iquote('binary,83.1,4.1')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12  % Problem  : GRP020-1 : TPTP v8.1.0. Released v1.0.0.
% 0.07/0.12  % Command  : otter-tptp-script %s
% 0.14/0.33  % Computer : n011.cluster.edu
% 0.14/0.33  % Model    : x86_64 x86_64
% 0.14/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.33  % Memory   : 8042.1875MB
% 0.14/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.33  % CPULimit : 300
% 0.14/0.33  % WCLimit  : 300
% 0.14/0.33  % DateTime : Wed Jul 27 05:12:40 EDT 2022
% 0.14/0.33  % CPUTime  : 
% 1.80/2.01  ----- Otter 3.3f, August 2004 -----
% 1.80/2.01  The process was started by sandbox2 on n011.cluster.edu,
% 1.80/2.01  Wed Jul 27 05:12:40 2022
% 1.80/2.01  The command was "./otter".  The process ID is 5632.
% 1.80/2.01  
% 1.80/2.01  set(prolog_style_variables).
% 1.80/2.01  set(auto).
% 1.80/2.01     dependent: set(auto1).
% 1.80/2.01     dependent: set(process_input).
% 1.80/2.01     dependent: clear(print_kept).
% 1.80/2.01     dependent: clear(print_new_demod).
% 1.80/2.01     dependent: clear(print_back_demod).
% 1.80/2.01     dependent: clear(print_back_sub).
% 1.80/2.01     dependent: set(control_memory).
% 1.80/2.01     dependent: assign(max_mem, 12000).
% 1.80/2.01     dependent: assign(pick_given_ratio, 4).
% 1.80/2.01     dependent: assign(stats_level, 1).
% 1.80/2.01     dependent: assign(max_seconds, 10800).
% 1.80/2.01  clear(print_given).
% 1.80/2.01  
% 1.80/2.01  list(usable).
% 1.80/2.01  0 [] A=A.
% 1.80/2.01  0 [] product(identity,X,X).
% 1.80/2.01  0 [] product(X,identity,X).
% 1.80/2.01  0 [] product(inverse(X),X,identity).
% 1.80/2.01  0 [] product(X,inverse(X),identity).
% 1.80/2.01  0 [] product(X,Y,multiply(X,Y)).
% 1.80/2.01  0 [] -product(X,Y,Z)| -product(X,Y,W)|Z=W.
% 1.80/2.01  0 [] -product(X,Y,U)| -product(Y,Z,V)| -product(U,Z,W)|product(X,V,W).
% 1.80/2.01  0 [] -product(X,Y,U)| -product(Y,Z,V)| -product(X,V,W)|product(U,Z,W).
% 1.80/2.01  0 [] multiply(inverse(a),a)!=identity.
% 1.80/2.01  end_of_list.
% 1.80/2.01  
% 1.80/2.01  SCAN INPUT: prop=0, horn=1, equality=1, symmetry=0, max_lits=4.
% 1.80/2.01  
% 1.80/2.01  This is a Horn set with equality.  The strategy will be
% 1.80/2.01  Knuth-Bendix and hyper_res, with positive clauses in
% 1.80/2.01  sos and nonpositive clauses in usable.
% 1.80/2.01  
% 1.80/2.01     dependent: set(knuth_bendix).
% 1.80/2.01     dependent: set(anl_eq).
% 1.80/2.01     dependent: set(para_from).
% 1.80/2.01     dependent: set(para_into).
% 1.80/2.01     dependent: clear(para_from_right).
% 1.80/2.01     dependent: clear(para_into_right).
% 1.80/2.01     dependent: set(para_from_vars).
% 1.80/2.01     dependent: set(eq_units_both_ways).
% 1.80/2.01     dependent: set(dynamic_demod_all).
% 1.80/2.01     dependent: set(dynamic_demod).
% 1.80/2.01     dependent: set(order_eq).
% 1.80/2.01     dependent: set(back_demod).
% 1.80/2.01     dependent: set(lrpo).
% 1.80/2.01     dependent: set(hyper_res).
% 1.80/2.01     dependent: clear(order_hyper).
% 1.80/2.01  
% 1.80/2.01  ------------> process usable:
% 1.80/2.01  ** KEPT (pick-wt=11): 1 [] -product(A,B,C)| -product(A,B,D)|C=D.
% 1.80/2.01  ** KEPT (pick-wt=16): 2 [] -product(A,B,C)| -product(B,D,E)| -product(C,D,F)|product(A,E,F).
% 1.80/2.01  ** KEPT (pick-wt=16): 3 [] -product(A,B,C)| -product(B,D,E)| -product(A,E,F)|product(C,D,F).
% 1.80/2.01  ** KEPT (pick-wt=6): 4 [] multiply(inverse(a),a)!=identity.
% 1.80/2.01  
% 1.80/2.01  ------------> process sos:
% 1.80/2.01  ** KEPT (pick-wt=3): 5 [] A=A.
% 1.80/2.01  ** KEPT (pick-wt=4): 6 [] product(identity,A,A).
% 1.80/2.01  ** KEPT (pick-wt=4): 7 [] product(A,identity,A).
% 1.80/2.01  ** KEPT (pick-wt=5): 8 [] product(inverse(A),A,identity).
% 1.80/2.01  ** KEPT (pick-wt=5): 9 [] product(A,inverse(A),identity).
% 1.80/2.01  ** KEPT (pick-wt=6): 10 [] product(A,B,multiply(A,B)).
% 1.80/2.01    Following clause subsumed by 5 during input processing: 0 [copy,5,flip.1] A=A.
% 1.80/2.01  
% 1.80/2.01  ======= end of input processing =======
% 1.80/2.01  
% 1.80/2.01  =========== start of search ===========
% 1.80/2.01  
% 1.80/2.01  -------- PROOF -------- 
% 1.80/2.01  
% 1.80/2.01  ----> UNIT CONFLICT at   0.00 sec ----> 85 [binary,83.1,4.1] $F.
% 1.80/2.01  
% 1.80/2.01  Length of proof is 1.  Level of proof is 1.
% 1.80/2.01  
% 1.80/2.01  ---------------- PROOF ----------------
% 1.80/2.01  % SZS status Unsatisfiable
% 1.80/2.01  % SZS output start Refutation
% See solution above
% 1.80/2.01  ------------ end of proof -------------
% 1.80/2.01  
% 1.80/2.01  
% 1.80/2.01  Search stopped by max_proofs option.
% 1.80/2.01  
% 1.80/2.01  
% 1.80/2.01  Search stopped by max_proofs option.
% 1.80/2.01  
% 1.80/2.01  ============ end of search ============
% 1.80/2.01  
% 1.80/2.01  -------------- statistics -------------
% 1.80/2.01  clauses given                  7
% 1.80/2.01  clauses generated            240
% 1.80/2.01  clauses kept                  81
% 1.80/2.01  clauses forward subsumed     172
% 1.80/2.01  clauses back subsumed          1
% 1.80/2.01  Kbytes malloced              976
% 1.80/2.01  
% 1.80/2.01  ----------- times (seconds) -----------
% 1.80/2.01  user CPU time          0.00          (0 hr, 0 min, 0 sec)
% 1.80/2.01  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.80/2.01  wall-clock time        2             (0 hr, 0 min, 2 sec)
% 1.80/2.01  
% 1.80/2.01  That finishes the proof of the theorem.
% 1.80/2.01  
% 1.80/2.01  Process 5632 finished Wed Jul 27 05:12:42 2022
% 1.80/2.01  Otter interrupted
% 1.80/2.01  PROOF FOUND
%------------------------------------------------------------------------------