TSTP Solution File: GRP012+5 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : GRP012+5 : TPTP v8.1.0. Released v3.1.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n015.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 12:55:51 EDT 2022

% Result   : Theorem 1.92s 2.12s
% Output   : Refutation 1.92s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    5
%            Number of leaves      :    9
% Syntax   : Number of clauses     :   14 (  12 unt;   0 nHn;  10 RR)
%            Number of literals    :   20 (   0 equ;   7 neg)
%            Maximal clause size   :    4 (   1 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    2 (   1 usr;   1 prp; 0-3 aty)
%            Number of functors    :    6 (   6 usr;   5 con; 0-1 aty)
%            Number of variables   :   16 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    ( ~ product(A,B,C)
    | ~ product(B,D,E)
    | ~ product(C,D,F)
    | product(A,E,F) ),
    file('GRP012+5.p',unknown),
    [] ).

cnf(2,axiom,
    ( ~ product(A,B,C)
    | ~ product(B,D,E)
    | ~ product(A,E,F)
    | product(C,D,F) ),
    file('GRP012+5.p',unknown),
    [] ).

cnf(3,axiom,
    ~ product(inverse(dollar_c2),inverse(dollar_c1),dollar_c5),
    file('GRP012+5.p',unknown),
    [] ).

cnf(5,axiom,
    product(A,dollar_c5,A),
    file('GRP012+5.p',unknown),
    [] ).

cnf(6,axiom,
    product(dollar_c5,A,A),
    file('GRP012+5.p',unknown),
    [] ).

cnf(7,axiom,
    product(A,inverse(A),dollar_c5),
    file('GRP012+5.p',unknown),
    [] ).

cnf(8,axiom,
    product(inverse(A),A,dollar_c5),
    file('GRP012+5.p',unknown),
    [] ).

cnf(9,axiom,
    product(inverse(dollar_c4),inverse(dollar_c3),dollar_c2),
    file('GRP012+5.p',unknown),
    [] ).

cnf(10,axiom,
    product(dollar_c3,dollar_c4,dollar_c1),
    file('GRP012+5.p',unknown),
    [] ).

cnf(98,plain,
    product(inverse(dollar_c3),dollar_c1,dollar_c4),
    inference(hyper,[status(thm)],[8,1,10,6]),
    [iquote('hyper,8,1,10,6')] ).

cnf(219,plain,
    product(dollar_c2,dollar_c1,dollar_c5),
    inference(hyper,[status(thm)],[9,2,98,8]),
    [iquote('hyper,9,2,98,8')] ).

cnf(252,plain,
    product(dollar_c5,dollar_c1,inverse(dollar_c2)),
    inference(hyper,[status(thm)],[219,2,8,5]),
    [iquote('hyper,219,2,8,5')] ).

cnf(616,plain,
    product(inverse(dollar_c2),inverse(dollar_c1),dollar_c5),
    inference(hyper,[status(thm)],[252,2,7,6]),
    [iquote('hyper,252,2,7,6')] ).

cnf(617,plain,
    $false,
    inference(binary,[status(thm)],[616,3]),
    [iquote('binary,616.1,3.1')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.11  % Problem  : GRP012+5 : TPTP v8.1.0. Released v3.1.0.
% 0.11/0.12  % Command  : otter-tptp-script %s
% 0.12/0.33  % Computer : n015.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 300
% 0.12/0.33  % DateTime : Wed Jul 27 05:45:26 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 1.92/2.12  ----- Otter 3.3f, August 2004 -----
% 1.92/2.12  The process was started by sandbox on n015.cluster.edu,
% 1.92/2.12  Wed Jul 27 05:45:26 2022
% 1.92/2.12  The command was "./otter".  The process ID is 22315.
% 1.92/2.12  
% 1.92/2.12  set(prolog_style_variables).
% 1.92/2.12  set(auto).
% 1.92/2.12     dependent: set(auto1).
% 1.92/2.12     dependent: set(process_input).
% 1.92/2.12     dependent: clear(print_kept).
% 1.92/2.12     dependent: clear(print_new_demod).
% 1.92/2.12     dependent: clear(print_back_demod).
% 1.92/2.12     dependent: clear(print_back_sub).
% 1.92/2.12     dependent: set(control_memory).
% 1.92/2.12     dependent: assign(max_mem, 12000).
% 1.92/2.12     dependent: assign(pick_given_ratio, 4).
% 1.92/2.12     dependent: assign(stats_level, 1).
% 1.92/2.12     dependent: assign(max_seconds, 10800).
% 1.92/2.12  clear(print_given).
% 1.92/2.12  
% 1.92/2.12  formula_list(usable).
% 1.92/2.12  -(all E ((all X Y exists Z product(X,Y,Z))& (all X Y Z U V W (product(X,Y,U)&product(Y,Z,V)&product(U,Z,W)->product(X,V,W)))& (all X Y Z U V W (product(X,Y,U)&product(Y,Z,V)&product(X,V,W)->product(U,Z,W)))& (all X product(X,E,X))& (all X product(E,X,X))& (all X product(X,inverse(X),E))& (all X product(inverse(X),X,E))-> (all U V W X (product(inverse(U),inverse(V),W)&product(V,U,X)->product(inverse(W),inverse(X),E))))).
% 1.92/2.12  end_of_list.
% 1.92/2.12  
% 1.92/2.12  -------> usable clausifies to:
% 1.92/2.12  
% 1.92/2.12  list(usable).
% 1.92/2.12  0 [] product(X,Y,$f1(X,Y)).
% 1.92/2.12  0 [] -product(X1,X2,U)| -product(X2,Z,V)| -product(U,Z,W)|product(X1,V,W).
% 1.92/2.12  0 [] -product(X3,X4,X6)| -product(X4,X5,X7)| -product(X3,X7,X8)|product(X6,X5,X8).
% 1.92/2.12  0 [] product(X9,$c5,X9).
% 1.92/2.12  0 [] product($c5,X10,X10).
% 1.92/2.12  0 [] product(X11,inverse(X11),$c5).
% 1.92/2.12  0 [] product(inverse(X12),X12,$c5).
% 1.92/2.12  0 [] product(inverse($c4),inverse($c3),$c2).
% 1.92/2.12  0 [] product($c3,$c4,$c1).
% 1.92/2.12  0 [] -product(inverse($c2),inverse($c1),$c5).
% 1.92/2.12  end_of_list.
% 1.92/2.12  
% 1.92/2.12  SCAN INPUT: prop=0, horn=1, equality=0, symmetry=0, max_lits=4.
% 1.92/2.12  
% 1.92/2.12  This is a Horn set without equality.  The strategy will
% 1.92/2.12  be hyperresolution, with satellites in sos and nuclei
% 1.92/2.12  in usable.
% 1.92/2.12  
% 1.92/2.12     dependent: set(hyper_res).
% 1.92/2.12     dependent: clear(order_hyper).
% 1.92/2.12  
% 1.92/2.12  ------------> process usable:
% 1.92/2.12  ** KEPT (pick-wt=16): 1 [] -product(A,B,C)| -product(B,D,E)| -product(C,D,F)|product(A,E,F).
% 1.92/2.12  ** KEPT (pick-wt=16): 2 [] -product(A,B,C)| -product(B,D,E)| -product(A,E,F)|product(C,D,F).
% 1.92/2.12  ** KEPT (pick-wt=6): 3 [] -product(inverse($c2),inverse($c1),$c5).
% 1.92/2.12  
% 1.92/2.12  ------------> process sos:
% 1.92/2.12  ** KEPT (pick-wt=6): 4 [] product(A,B,$f1(A,B)).
% 1.92/2.12  ** KEPT (pick-wt=4): 5 [] product(A,$c5,A).
% 1.92/2.12  ** KEPT (pick-wt=4): 6 [] product($c5,A,A).
% 1.92/2.12  ** KEPT (pick-wt=5): 7 [] product(A,inverse(A),$c5).
% 1.92/2.12  ** KEPT (pick-wt=5): 8 [] product(inverse(A),A,$c5).
% 1.92/2.12  ** KEPT (pick-wt=6): 9 [] product(inverse($c4),inverse($c3),$c2).
% 1.92/2.12  ** KEPT (pick-wt=4): 10 [] product($c3,$c4,$c1).
% 1.92/2.12  
% 1.92/2.12  ======= end of input processing =======
% 1.92/2.12  
% 1.92/2.12  =========== start of search ===========
% 1.92/2.12  
% 1.92/2.12  -------- PROOF -------- 
% 1.92/2.12  
% 1.92/2.12  ----> UNIT CONFLICT at   0.01 sec ----> 617 [binary,616.1,3.1] $F.
% 1.92/2.12  
% 1.92/2.12  Length of proof is 4.  Level of proof is 4.
% 1.92/2.12  
% 1.92/2.12  ---------------- PROOF ----------------
% 1.92/2.12  % SZS status Theorem
% 1.92/2.12  % SZS output start Refutation
% See solution above
% 1.92/2.12  ------------ end of proof -------------
% 1.92/2.12  
% 1.92/2.12  
% 1.92/2.12  Search stopped by max_proofs option.
% 1.92/2.12  
% 1.92/2.12  
% 1.92/2.12  Search stopped by max_proofs option.
% 1.92/2.12  
% 1.92/2.12  ============ end of search ============
% 1.92/2.12  
% 1.92/2.12  -------------- statistics -------------
% 1.92/2.12  clauses given                 18
% 1.92/2.12  clauses generated           1487
% 1.92/2.12  clauses kept                 616
% 1.92/2.12  clauses forward subsumed     881
% 1.92/2.12  clauses back subsumed          8
% 1.92/2.12  Kbytes malloced              976
% 1.92/2.12  
% 1.92/2.12  ----------- times (seconds) -----------
% 1.92/2.12  user CPU time          0.01          (0 hr, 0 min, 0 sec)
% 1.92/2.12  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.92/2.12  wall-clock time        2             (0 hr, 0 min, 2 sec)
% 1.92/2.12  
% 1.92/2.12  That finishes the proof of the theorem.
% 1.92/2.12  
% 1.92/2.12  Process 22315 finished Wed Jul 27 05:45:28 2022
% 1.92/2.12  Otter interrupted
% 1.92/2.12  PROOF FOUND
%------------------------------------------------------------------------------