TSTP Solution File: GEO647+1 by Twee---2.4.2
View Problem
- Process Solution
%------------------------------------------------------------------------------
% File : Twee---2.4.2
% Problem : GEO647+1 : TPTP v8.1.2. Released v7.5.0.
% Transfm : none
% Format : tptp:raw
% Command : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof
% Computer : n022.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Wed Aug 30 23:29:41 EDT 2023
% Result : Theorem 11.93s 1.89s
% Output : Proof 11.93s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.13 % Problem : GEO647+1 : TPTP v8.1.2. Released v7.5.0.
% 0.03/0.13 % Command : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof
% 0.14/0.35 % Computer : n022.cluster.edu
% 0.14/0.35 % Model : x86_64 x86_64
% 0.14/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.35 % Memory : 8042.1875MB
% 0.14/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.14/0.35 % CPULimit : 300
% 0.14/0.35 % WCLimit : 300
% 0.14/0.35 % DateTime : Tue Aug 29 23:03:23 EDT 2023
% 0.14/0.35 % CPUTime :
% 11.93/1.89 Command-line arguments: --kbo-weight0 --lhs-weight 5 --flip-ordering --normalise-queue-percent 10 --cp-renormalise-threshold 10 --goal-heuristic
% 11.93/1.89
% 11.93/1.89 % SZS status Theorem
% 11.93/1.89
% 11.93/1.91 % SZS output start Proof
% 11.93/1.91 Take the following subset of the input axioms:
% 11.93/1.91 fof(exemplo6GDDFULLmoreE0156, conjecture, ![A, B, C, D, E, F, G]: ((midp(D, A, C) & (midp(E, B, A) & (midp(F, C, B) & (para(A, F, G, D) & para(A, C, G, F))))) => para(C, E, G, B))).
% 11.93/1.91 fof(ruleD1, axiom, ![A2, B2, C2]: (coll(A2, B2, C2) => coll(A2, C2, B2))).
% 11.93/1.91 fof(ruleD14, axiom, ![B2, C2, D2, A2_2]: (cyclic(A2_2, B2, C2, D2) => cyclic(A2_2, B2, D2, C2))).
% 11.93/1.91 fof(ruleD15, axiom, ![B2, C2, D2, A2_2]: (cyclic(A2_2, B2, C2, D2) => cyclic(A2_2, C2, B2, D2))).
% 11.93/1.91 fof(ruleD16, axiom, ![B2, C2, D2, A2_2]: (cyclic(A2_2, B2, C2, D2) => cyclic(B2, A2_2, C2, D2))).
% 11.93/1.91 fof(ruleD17, axiom, ![B2, C2, D2, E2, A2_2]: ((cyclic(A2_2, B2, C2, D2) & cyclic(A2_2, B2, C2, E2)) => cyclic(B2, C2, D2, E2))).
% 11.93/1.91 fof(ruleD19, axiom, ![P, Q, U, V, B2, C2, D2, A2_2]: (eqangle(A2_2, B2, C2, D2, P, Q, U, V) => eqangle(C2, D2, A2_2, B2, U, V, P, Q))).
% 11.93/1.91 fof(ruleD2, axiom, ![B2, C2, A2_2]: (coll(A2_2, B2, C2) => coll(B2, A2_2, C2))).
% 11.93/1.91 fof(ruleD21, axiom, ![B2, C2, D2, A2_2, P2, Q2, U2, V2]: (eqangle(A2_2, B2, C2, D2, P2, Q2, U2, V2) => eqangle(A2_2, B2, P2, Q2, C2, D2, U2, V2))).
% 11.93/1.91 fof(ruleD40, axiom, ![B2, C2, D2, A2_2, P2, Q2]: (para(A2_2, B2, C2, D2) => eqangle(A2_2, B2, P2, Q2, C2, D2, P2, Q2))).
% 11.93/1.91 fof(ruleD42b, axiom, ![B2, A2_2, P2, Q2]: ((eqangle(P2, A2_2, P2, B2, Q2, A2_2, Q2, B2) & coll(P2, Q2, B2)) => cyclic(A2_2, B2, P2, Q2))).
% 11.93/1.91 fof(ruleD43, axiom, ![R, B2, C2, A2_2, P2, Q2]: ((cyclic(A2_2, B2, C2, P2) & (cyclic(A2_2, B2, C2, Q2) & (cyclic(A2_2, B2, C2, R) & eqangle(C2, A2_2, C2, B2, R, P2, R, Q2)))) => cong(A2_2, B2, P2, Q2))).
% 11.93/1.91 fof(ruleD56, axiom, ![B2, A2_2, P2, Q2]: ((cong(A2_2, P2, B2, P2) & cong(A2_2, Q2, B2, Q2)) => perp(A2_2, B2, P2, Q2))).
% 11.93/1.91 fof(ruleD66, axiom, ![B2, C2, A2_2]: (para(A2_2, B2, A2_2, C2) => coll(A2_2, B2, C2))).
% 11.93/1.91 fof(ruleD73, axiom, ![B2, C2, D2, A2_2, P2, Q2, U2, V2]: ((eqangle(A2_2, B2, C2, D2, P2, Q2, U2, V2) & para(P2, Q2, U2, V2)) => para(A2_2, B2, C2, D2))).
% 11.93/1.91 fof(ruleD8, axiom, ![B2, C2, D2, A2_2]: (perp(A2_2, B2, C2, D2) => perp(C2, D2, A2_2, B2))).
% 11.93/1.91 fof(ruleD9, axiom, ![B2, C2, D2, E2, F2, A2_2]: ((perp(A2_2, B2, C2, D2) & perp(C2, D2, E2, F2)) => para(A2_2, B2, E2, F2))).
% 11.93/1.91
% 11.93/1.91 Now clausify the problem and encode Horn clauses using encoding 3 of
% 11.93/1.91 http://www.cse.chalmers.se/~nicsma/papers/horn.pdf.
% 11.93/1.91 We repeatedly replace C & s=t => u=v by the two clauses:
% 11.93/1.91 fresh(y, y, x1...xn) = u
% 11.93/1.91 C => fresh(s, t, x1...xn) = v
% 11.93/1.91 where fresh is a fresh function symbol and x1..xn are the free
% 11.93/1.91 variables of u and v.
% 11.93/1.91 A predicate p(X) is encoded as p(X)=true (this is sound, because the
% 11.93/1.91 input problem has no model of domain size 1).
% 11.93/1.91
% 11.93/1.91 The encoding turns the above axioms into the following unit equations and goals:
% 11.93/1.91
% 11.93/1.91 Axiom 1 (exemplo6GDDFULLmoreE0156): para(a, c, g, f) = true.
% 11.93/1.91 Axiom 2 (ruleD1): fresh146(X, X, Y, Z, W) = true.
% 11.93/1.91 Axiom 3 (ruleD2): fresh133(X, X, Y, Z, W) = true.
% 11.93/1.91 Axiom 4 (ruleD66): fresh66(X, X, Y, Z, W) = true.
% 11.93/1.91 Axiom 5 (ruleD43): fresh185(X, X, Y, Z, W, V) = true.
% 11.93/1.91 Axiom 6 (ruleD14): fresh140(X, X, Y, Z, W, V) = true.
% 11.93/1.91 Axiom 7 (ruleD15): fresh139(X, X, Y, Z, W, V) = true.
% 11.93/1.91 Axiom 8 (ruleD16): fresh138(X, X, Y, Z, W, V) = true.
% 11.93/1.91 Axiom 9 (ruleD17): fresh136(X, X, Y, Z, W, V) = true.
% 11.93/1.91 Axiom 10 (ruleD42b): fresh102(X, X, Y, Z, W, V) = cyclic(Y, Z, W, V).
% 11.93/1.91 Axiom 11 (ruleD42b): fresh101(X, X, Y, Z, W, V) = true.
% 11.93/1.91 Axiom 12 (ruleD56): fresh80(X, X, Y, Z, W, V) = perp(Y, Z, W, V).
% 11.93/1.91 Axiom 13 (ruleD56): fresh79(X, X, Y, Z, W, V) = true.
% 11.93/1.91 Axiom 14 (ruleD73): fresh57(X, X, Y, Z, W, V) = true.
% 11.93/1.91 Axiom 15 (ruleD8): fresh52(X, X, Y, Z, W, V) = true.
% 11.93/1.91 Axiom 16 (ruleD9): fresh50(X, X, Y, Z, W, V) = true.
% 11.93/1.91 Axiom 17 (ruleD43): fresh183(X, X, Y, Z, W, V, U) = cong(Y, Z, V, U).
% 11.93/1.91 Axiom 18 (ruleD1): fresh146(coll(X, Y, Z), true, X, Y, Z) = coll(X, Z, Y).
% 11.93/1.91 Axiom 19 (ruleD17): fresh137(X, X, Y, Z, W, V, U) = cyclic(Z, W, V, U).
% 11.93/1.91 Axiom 20 (ruleD2): fresh133(coll(X, Y, Z), true, X, Y, Z) = coll(Y, X, Z).
% 11.93/1.91 Axiom 21 (ruleD40): fresh104(X, X, Y, Z, W, V, U, T) = true.
% 11.93/1.91 Axiom 22 (ruleD66): fresh66(para(X, Y, X, Z), true, X, Y, Z) = coll(X, Y, Z).
% 11.93/1.91 Axiom 23 (ruleD9): fresh51(X, X, Y, Z, W, V, U, T) = para(Y, Z, U, T).
% 11.93/1.91 Axiom 24 (ruleD43): fresh184(X, X, Y, Z, W, V, U) = fresh185(cyclic(Y, Z, W, V), true, Y, Z, V, U).
% 11.93/1.91 Axiom 25 (ruleD14): fresh140(cyclic(X, Y, Z, W), true, X, Y, Z, W) = cyclic(X, Y, W, Z).
% 11.93/1.91 Axiom 26 (ruleD15): fresh139(cyclic(X, Y, Z, W), true, X, Y, Z, W) = cyclic(X, Z, Y, W).
% 11.93/1.91 Axiom 27 (ruleD16): fresh138(cyclic(X, Y, Z, W), true, X, Y, Z, W) = cyclic(Y, X, Z, W).
% 11.93/1.91 Axiom 28 (ruleD56): fresh80(cong(X, Y, Z, Y), true, X, Z, W, Y) = fresh79(cong(X, W, Z, W), true, X, Z, W, Y).
% 11.93/1.91 Axiom 29 (ruleD8): fresh52(perp(X, Y, Z, W), true, X, Y, Z, W) = perp(Z, W, X, Y).
% 11.93/1.91 Axiom 30 (ruleD43): fresh182(X, X, Y, Z, W, V, U, T) = fresh183(cyclic(Y, Z, W, U), true, Y, Z, W, V, U).
% 11.93/1.91 Axiom 31 (ruleD17): fresh137(cyclic(X, Y, Z, W), true, X, Y, Z, V, W) = fresh136(cyclic(X, Y, Z, V), true, Y, Z, V, W).
% 11.93/1.91 Axiom 32 (ruleD19): fresh134(X, X, Y, Z, W, V, U, T, S, X2) = true.
% 11.93/1.91 Axiom 33 (ruleD21): fresh131(X, X, Y, Z, W, V, U, T, S, X2) = true.
% 11.93/1.91 Axiom 34 (ruleD73): fresh58(X, X, Y, Z, W, V, U, T, S, X2) = para(Y, Z, W, V).
% 11.93/1.91 Axiom 35 (ruleD40): fresh104(para(X, Y, Z, W), true, X, Y, Z, W, V, U) = eqangle(X, Y, V, U, Z, W, V, U).
% 11.93/1.91 Axiom 36 (ruleD9): fresh51(perp(X, Y, Z, W), true, V, U, X, Y, Z, W) = fresh50(perp(V, U, X, Y), true, V, U, Z, W).
% 11.93/1.91 Axiom 37 (ruleD42b): fresh102(eqangle(X, Y, X, Z, W, Y, W, Z), true, Y, Z, X, W) = fresh101(coll(X, W, Z), true, Y, Z, X, W).
% 11.93/1.91 Axiom 38 (ruleD43): fresh182(eqangle(X, Y, X, Z, W, V, W, U), true, Y, Z, X, V, U, W) = fresh184(cyclic(Y, Z, X, W), true, Y, Z, X, V, U).
% 11.93/1.91 Axiom 39 (ruleD19): fresh134(eqangle(X, Y, Z, W, V, U, T, S), true, X, Y, Z, W, V, U, T, S) = eqangle(Z, W, X, Y, T, S, V, U).
% 11.93/1.91 Axiom 40 (ruleD21): fresh131(eqangle(X, Y, Z, W, V, U, T, S), true, X, Y, Z, W, V, U, T, S) = eqangle(X, Y, V, U, Z, W, T, S).
% 11.93/1.91 Axiom 41 (ruleD73): fresh58(eqangle(X, Y, Z, W, V, U, T, S), true, X, Y, Z, W, V, U, T, S) = fresh57(para(V, U, T, S), true, X, Y, Z, W).
% 11.93/1.91
% 11.93/1.91 Lemma 42: para(X, Y, X, Y) = true.
% 11.93/1.91 Proof:
% 11.93/1.91 para(X, Y, X, Y)
% 11.93/1.91 = { by axiom 34 (ruleD73) R->L }
% 11.93/1.91 fresh58(true, true, X, Y, X, Y, a, c, g, f)
% 11.93/1.91 = { by axiom 33 (ruleD21) R->L }
% 11.93/1.91 fresh58(fresh131(true, true, X, Y, a, c, X, Y, g, f), true, X, Y, X, Y, a, c, g, f)
% 11.93/1.91 = { by axiom 32 (ruleD19) R->L }
% 11.93/1.91 fresh58(fresh131(fresh134(true, true, a, c, X, Y, g, f, X, Y), true, X, Y, a, c, X, Y, g, f), true, X, Y, X, Y, a, c, g, f)
% 11.93/1.91 = { by axiom 21 (ruleD40) R->L }
% 11.93/1.91 fresh58(fresh131(fresh134(fresh104(true, true, a, c, g, f, X, Y), true, a, c, X, Y, g, f, X, Y), true, X, Y, a, c, X, Y, g, f), true, X, Y, X, Y, a, c, g, f)
% 11.93/1.91 = { by axiom 1 (exemplo6GDDFULLmoreE0156) R->L }
% 11.93/1.92 fresh58(fresh131(fresh134(fresh104(para(a, c, g, f), true, a, c, g, f, X, Y), true, a, c, X, Y, g, f, X, Y), true, X, Y, a, c, X, Y, g, f), true, X, Y, X, Y, a, c, g, f)
% 11.93/1.92 = { by axiom 35 (ruleD40) }
% 11.93/1.92 fresh58(fresh131(fresh134(eqangle(a, c, X, Y, g, f, X, Y), true, a, c, X, Y, g, f, X, Y), true, X, Y, a, c, X, Y, g, f), true, X, Y, X, Y, a, c, g, f)
% 11.93/1.92 = { by axiom 39 (ruleD19) }
% 11.93/1.92 fresh58(fresh131(eqangle(X, Y, a, c, X, Y, g, f), true, X, Y, a, c, X, Y, g, f), true, X, Y, X, Y, a, c, g, f)
% 11.93/1.92 = { by axiom 40 (ruleD21) }
% 11.93/1.92 fresh58(eqangle(X, Y, X, Y, a, c, g, f), true, X, Y, X, Y, a, c, g, f)
% 11.93/1.92 = { by axiom 41 (ruleD73) }
% 11.93/1.92 fresh57(para(a, c, g, f), true, X, Y, X, Y)
% 11.93/1.92 = { by axiom 1 (exemplo6GDDFULLmoreE0156) }
% 11.93/1.92 fresh57(true, true, X, Y, X, Y)
% 11.93/1.92 = { by axiom 14 (ruleD73) }
% 11.93/1.92 true
% 11.93/1.92
% 11.93/1.92 Lemma 43: eqangle(X, Y, Z, W, X, Y, Z, W) = true.
% 11.93/1.92 Proof:
% 11.93/1.92 eqangle(X, Y, Z, W, X, Y, Z, W)
% 11.93/1.92 = { by axiom 35 (ruleD40) R->L }
% 11.93/1.92 fresh104(para(X, Y, X, Y), true, X, Y, X, Y, Z, W)
% 11.93/1.92 = { by lemma 42 }
% 11.93/1.92 fresh104(true, true, X, Y, X, Y, Z, W)
% 11.93/1.92 = { by axiom 21 (ruleD40) }
% 11.93/1.92 true
% 11.93/1.92
% 11.93/1.92 Lemma 44: cyclic(X, Y, X, Z) = true.
% 11.93/1.92 Proof:
% 11.93/1.92 cyclic(X, Y, X, Z)
% 11.93/1.92 = { by axiom 27 (ruleD16) R->L }
% 11.93/1.92 fresh138(cyclic(Y, X, X, Z), true, Y, X, X, Z)
% 11.93/1.92 = { by axiom 25 (ruleD14) R->L }
% 11.93/1.92 fresh138(fresh140(cyclic(Y, X, Z, X), true, Y, X, Z, X), true, Y, X, X, Z)
% 11.93/1.92 = { by axiom 26 (ruleD15) R->L }
% 11.93/1.92 fresh138(fresh140(fresh139(cyclic(Y, Z, X, X), true, Y, Z, X, X), true, Y, X, Z, X), true, Y, X, X, Z)
% 11.93/1.92 = { by axiom 10 (ruleD42b) R->L }
% 11.93/1.92 fresh138(fresh140(fresh139(fresh102(true, true, Y, Z, X, X), true, Y, Z, X, X), true, Y, X, Z, X), true, Y, X, X, Z)
% 11.93/1.92 = { by lemma 43 R->L }
% 11.93/1.92 fresh138(fresh140(fresh139(fresh102(eqangle(X, Y, X, Z, X, Y, X, Z), true, Y, Z, X, X), true, Y, Z, X, X), true, Y, X, Z, X), true, Y, X, X, Z)
% 11.93/1.92 = { by axiom 37 (ruleD42b) }
% 11.93/1.92 fresh138(fresh140(fresh139(fresh101(coll(X, X, Z), true, Y, Z, X, X), true, Y, Z, X, X), true, Y, X, Z, X), true, Y, X, X, Z)
% 11.93/1.92 = { by axiom 18 (ruleD1) R->L }
% 11.93/1.92 fresh138(fresh140(fresh139(fresh101(fresh146(coll(X, Z, X), true, X, Z, X), true, Y, Z, X, X), true, Y, Z, X, X), true, Y, X, Z, X), true, Y, X, X, Z)
% 11.93/1.92 = { by axiom 20 (ruleD2) R->L }
% 11.93/1.92 fresh138(fresh140(fresh139(fresh101(fresh146(fresh133(coll(Z, X, X), true, Z, X, X), true, X, Z, X), true, Y, Z, X, X), true, Y, Z, X, X), true, Y, X, Z, X), true, Y, X, X, Z)
% 11.93/1.92 = { by axiom 22 (ruleD66) R->L }
% 11.93/1.92 fresh138(fresh140(fresh139(fresh101(fresh146(fresh133(fresh66(para(Z, X, Z, X), true, Z, X, X), true, Z, X, X), true, X, Z, X), true, Y, Z, X, X), true, Y, Z, X, X), true, Y, X, Z, X), true, Y, X, X, Z)
% 11.93/1.92 = { by lemma 42 }
% 11.93/1.92 fresh138(fresh140(fresh139(fresh101(fresh146(fresh133(fresh66(true, true, Z, X, X), true, Z, X, X), true, X, Z, X), true, Y, Z, X, X), true, Y, Z, X, X), true, Y, X, Z, X), true, Y, X, X, Z)
% 11.93/1.92 = { by axiom 4 (ruleD66) }
% 11.93/1.92 fresh138(fresh140(fresh139(fresh101(fresh146(fresh133(true, true, Z, X, X), true, X, Z, X), true, Y, Z, X, X), true, Y, Z, X, X), true, Y, X, Z, X), true, Y, X, X, Z)
% 11.93/1.92 = { by axiom 3 (ruleD2) }
% 11.93/1.92 fresh138(fresh140(fresh139(fresh101(fresh146(true, true, X, Z, X), true, Y, Z, X, X), true, Y, Z, X, X), true, Y, X, Z, X), true, Y, X, X, Z)
% 11.93/1.92 = { by axiom 2 (ruleD1) }
% 11.93/1.92 fresh138(fresh140(fresh139(fresh101(true, true, Y, Z, X, X), true, Y, Z, X, X), true, Y, X, Z, X), true, Y, X, X, Z)
% 11.93/1.92 = { by axiom 11 (ruleD42b) }
% 11.93/1.92 fresh138(fresh140(fresh139(true, true, Y, Z, X, X), true, Y, X, Z, X), true, Y, X, X, Z)
% 11.93/1.92 = { by axiom 7 (ruleD15) }
% 11.93/1.92 fresh138(fresh140(true, true, Y, X, Z, X), true, Y, X, X, Z)
% 11.93/1.92 = { by axiom 6 (ruleD14) }
% 11.93/1.92 fresh138(true, true, Y, X, X, Z)
% 11.93/1.92 = { by axiom 8 (ruleD16) }
% 11.93/1.92 true
% 11.93/1.92
% 11.93/1.92 Lemma 45: cyclic(X, Y, Z, W) = true.
% 11.93/1.92 Proof:
% 11.93/1.92 cyclic(X, Y, Z, W)
% 11.93/1.92 = { by axiom 19 (ruleD17) R->L }
% 11.93/1.92 fresh137(true, true, Y, X, Y, Z, W)
% 11.93/1.92 = { by lemma 44 R->L }
% 11.93/1.92 fresh137(cyclic(Y, X, Y, W), true, Y, X, Y, Z, W)
% 11.93/1.92 = { by axiom 31 (ruleD17) }
% 11.93/1.92 fresh136(cyclic(Y, X, Y, Z), true, X, Y, Z, W)
% 11.93/1.92 = { by lemma 44 }
% 11.93/1.92 fresh136(true, true, X, Y, Z, W)
% 11.93/1.92 = { by axiom 9 (ruleD17) }
% 11.93/1.92 true
% 11.93/1.92
% 11.93/1.92 Lemma 46: cong(X, Y, X, Y) = true.
% 11.93/1.92 Proof:
% 11.93/1.92 cong(X, Y, X, Y)
% 11.93/1.92 = { by axiom 17 (ruleD43) R->L }
% 11.93/1.92 fresh183(true, true, X, Y, Z, X, Y)
% 11.93/1.92 = { by lemma 45 R->L }
% 11.93/1.92 fresh183(cyclic(X, Y, Z, Y), true, X, Y, Z, X, Y)
% 11.93/1.92 = { by axiom 30 (ruleD43) R->L }
% 11.93/1.92 fresh182(true, true, X, Y, Z, X, Y, Z)
% 11.93/1.92 = { by lemma 43 R->L }
% 11.93/1.92 fresh182(eqangle(Z, X, Z, Y, Z, X, Z, Y), true, X, Y, Z, X, Y, Z)
% 11.93/1.92 = { by axiom 38 (ruleD43) }
% 11.93/1.92 fresh184(cyclic(X, Y, Z, Z), true, X, Y, Z, X, Y)
% 11.93/1.92 = { by lemma 45 }
% 11.93/1.92 fresh184(true, true, X, Y, Z, X, Y)
% 11.93/1.92 = { by axiom 24 (ruleD43) }
% 11.93/1.92 fresh185(cyclic(X, Y, Z, X), true, X, Y, X, Y)
% 11.93/1.92 = { by lemma 45 }
% 11.93/1.92 fresh185(true, true, X, Y, X, Y)
% 11.93/1.92 = { by axiom 5 (ruleD43) }
% 11.93/1.92 true
% 11.93/1.92
% 11.93/1.92 Lemma 47: perp(X, X, Y, Z) = true.
% 11.93/1.92 Proof:
% 11.93/1.92 perp(X, X, Y, Z)
% 11.93/1.92 = { by axiom 12 (ruleD56) R->L }
% 11.93/1.92 fresh80(true, true, X, X, Y, Z)
% 11.93/1.92 = { by lemma 46 R->L }
% 11.93/1.92 fresh80(cong(X, Z, X, Z), true, X, X, Y, Z)
% 11.93/1.92 = { by axiom 28 (ruleD56) }
% 11.93/1.92 fresh79(cong(X, Y, X, Y), true, X, X, Y, Z)
% 11.93/1.92 = { by lemma 46 }
% 11.93/1.92 fresh79(true, true, X, X, Y, Z)
% 11.93/1.92 = { by axiom 13 (ruleD56) }
% 11.93/1.92 true
% 11.93/1.92
% 11.93/1.92 Goal 1 (exemplo6GDDFULLmoreE0156_5): para(c, e, g, b) = true.
% 11.93/1.92 Proof:
% 11.93/1.92 para(c, e, g, b)
% 11.93/1.92 = { by axiom 23 (ruleD9) R->L }
% 11.93/1.92 fresh51(true, true, c, e, X, X, g, b)
% 11.93/1.92 = { by lemma 47 R->L }
% 11.93/1.92 fresh51(perp(X, X, g, b), true, c, e, X, X, g, b)
% 11.93/1.92 = { by axiom 36 (ruleD9) }
% 11.93/1.92 fresh50(perp(c, e, X, X), true, c, e, g, b)
% 11.93/1.92 = { by axiom 29 (ruleD8) R->L }
% 11.93/1.92 fresh50(fresh52(perp(X, X, c, e), true, X, X, c, e), true, c, e, g, b)
% 11.93/1.92 = { by lemma 47 }
% 11.93/1.92 fresh50(fresh52(true, true, X, X, c, e), true, c, e, g, b)
% 11.93/1.92 = { by axiom 15 (ruleD8) }
% 11.93/1.92 fresh50(true, true, c, e, g, b)
% 11.93/1.92 = { by axiom 16 (ruleD9) }
% 11.93/1.92 true
% 11.93/1.92 % SZS output end Proof
% 11.93/1.92
% 11.93/1.92 RESULT: Theorem (the conjecture is true).
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