TSTP Solution File: GEO257+1 by Etableau---0.67
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%------------------------------------------------------------------------------
% File : Etableau---0.67
% Problem : GEO257+1 : TPTP v8.1.0. Bugfixed v6.4.0.
% Transfm : none
% Format : tptp:raw
% Command : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s
% Computer : n009.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Sat Jul 16 04:09:10 EDT 2022
% Result : Theorem 0.15s 0.38s
% Output : CNFRefutation 0.15s
% Verified :
% SZS Type : Refutation
% Derivation depth : 4
% Number of leaves : 2
% Syntax : Number of formulae : 8 ( 3 unt; 0 def)
% Number of atoms : 28 ( 0 equ)
% Maximal formula atoms : 7 ( 3 avg)
% Number of connectives : 29 ( 9 ~; 1 |; 15 &)
% ( 0 <=>; 4 =>; 0 <=; 0 <~>)
% Maximal formula depth : 12 ( 6 avg)
% Maximal term depth : 2 ( 1 avg)
% Number of predicates : 5 ( 4 usr; 1 prp; 0-3 aty)
% Number of functors : 6 ( 6 usr; 5 con; 0-1 aty)
% Number of variables : 16 ( 2 sgn 14 !; 0 ?)
% Comments :
%------------------------------------------------------------------------------
fof(con,conjecture,
! [X2,X1,X4,X5,X7] :
( ( distinct_points(X1,X5)
& distinct_points(X4,X5)
& ~ apart_point_and_line(X5,X2)
& left_apart_point(X7,X2) )
=> ( ( before_on_line(X2,X1,X4)
& before_on_line(X2,X4,X5) )
=> before_on_line(X2,X1,X5) ) ),
file('/export/starexec/sandbox/benchmark/theBenchmark.p',con) ).
fof(oag10,axiom,
! [X1,X2] :
~ ( left_apart_point(X1,X2)
| left_apart_point(X1,reverse_line(X2)) ),
file('/export/starexec/sandbox/benchmark/Axioms/GEO007+0.ax',oag10) ).
fof(c_0_2,negated_conjecture,
~ ! [X2,X1,X4,X5,X7] :
( ( distinct_points(X1,X5)
& distinct_points(X4,X5)
& ~ apart_point_and_line(X5,X2)
& left_apart_point(X7,X2) )
=> ( ( before_on_line(X2,X1,X4)
& before_on_line(X2,X4,X5) )
=> before_on_line(X2,X1,X5) ) ),
inference(assume_negation,[status(cth)],[con]) ).
fof(c_0_3,negated_conjecture,
( distinct_points(esk2_0,esk4_0)
& distinct_points(esk3_0,esk4_0)
& ~ apart_point_and_line(esk4_0,esk1_0)
& left_apart_point(esk5_0,esk1_0)
& before_on_line(esk1_0,esk2_0,esk3_0)
& before_on_line(esk1_0,esk3_0,esk4_0)
& ~ before_on_line(esk1_0,esk2_0,esk4_0) ),
inference(skolemize,[status(esa)],[inference(variable_rename,[status(thm)],[inference(fof_nnf,[status(thm)],[inference(fof_simplification,[status(thm)],[c_0_2])])])]) ).
fof(c_0_4,plain,
! [X41,X42] :
( ~ left_apart_point(X41,X42)
& ~ left_apart_point(X41,reverse_line(X42)) ),
inference(variable_rename,[status(thm)],[inference(fof_nnf,[status(thm)],[oag10])]) ).
cnf(c_0_5,negated_conjecture,
left_apart_point(esk5_0,esk1_0),
inference(split_conjunct,[status(thm)],[c_0_3]) ).
cnf(c_0_6,plain,
~ left_apart_point(X1,X2),
inference(split_conjunct,[status(thm)],[c_0_4]) ).
cnf(c_0_7,negated_conjecture,
$false,
inference(sr,[status(thm)],[c_0_5,c_0_6]),
[proof] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.08/0.13 % Problem : GEO257+1 : TPTP v8.1.0. Bugfixed v6.4.0.
% 0.08/0.14 % Command : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s
% 0.15/0.35 % Computer : n009.cluster.edu
% 0.15/0.35 % Model : x86_64 x86_64
% 0.15/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.15/0.35 % Memory : 8042.1875MB
% 0.15/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.15/0.35 % CPULimit : 300
% 0.15/0.35 % WCLimit : 600
% 0.15/0.35 % DateTime : Fri Jun 17 20:40:52 EDT 2022
% 0.15/0.35 % CPUTime :
% 0.15/0.38 # No SInE strategy applied
% 0.15/0.38 # Auto-Mode selected heuristic G_E___208_C18_F1_SE_CS_SP_PS_S5PRR_RG_S04AN
% 0.15/0.38 # and selection function SelectComplexExceptUniqMaxHorn.
% 0.15/0.38 #
% 0.15/0.38 # Presaturation interreduction done
% 0.15/0.38
% 0.15/0.38 # Proof found!
% 0.15/0.38 # SZS status Theorem
% 0.15/0.38 # SZS output start CNFRefutation
% See solution above
% 0.15/0.38 # Training examples: 0 positive, 0 negative
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