TSTP Solution File: GEO256+1 by SnakeForV-SAT---1.0
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%------------------------------------------------------------------------------
% File : SnakeForV-SAT---1.0
% Problem : GEO256+1 : TPTP v8.1.0. Bugfixed v6.4.0.
% Transfm : none
% Format : tptp:raw
% Command : vampire --input_syntax tptp --proof tptp --output_axiom_names on --mode portfolio --schedule snake_tptp_sat --cores 0 -t %d %s
% Computer : n018.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Wed Aug 31 16:12:29 EDT 2022
% Result : Theorem 0.19s 0.44s
% Output : Refutation 0.19s
% Verified :
% SZS Type : Refutation
% Derivation depth : 8
% Number of leaves : 3
% Syntax : Number of formulae : 14 ( 3 unt; 0 def)
% Number of atoms : 72 ( 0 equ)
% Maximal formula atoms : 14 ( 5 avg)
% Number of connectives : 87 ( 29 ~; 4 |; 47 &)
% ( 0 <=>; 7 =>; 0 <=; 0 <~>)
% Maximal formula depth : 14 ( 8 avg)
% Maximal term depth : 2 ( 1 avg)
% Number of predicates : 5 ( 4 usr; 1 prp; 0-3 aty)
% Number of functors : 6 ( 6 usr; 5 con; 0-1 aty)
% Number of variables : 43 ( 23 !; 20 ?)
% Comments :
%------------------------------------------------------------------------------
fof(f190,plain,
$false,
inference(subsumption_resolution,[],[f159,f132]) ).
fof(f132,plain,
! [X0,X1] : ~ left_apart_point(X1,X0),
inference(cnf_transformation,[],[f110]) ).
fof(f110,plain,
! [X0,X1] :
( ~ left_apart_point(X1,reverse_line(X0))
& ~ left_apart_point(X1,X0) ),
inference(rectify,[],[f101]) ).
fof(f101,plain,
! [X1,X0] :
( ~ left_apart_point(X0,reverse_line(X1))
& ~ left_apart_point(X0,X1) ),
inference(ennf_transformation,[],[f15]) ).
fof(f15,axiom,
! [X1,X0] :
~ ( left_apart_point(X0,reverse_line(X1))
| left_apart_point(X0,X1) ),
file('/export/starexec/sandbox/benchmark/theBenchmark.p',oag10) ).
fof(f159,plain,
left_apart_point(sK2,sK1),
inference(cnf_transformation,[],[f119]) ).
fof(f119,plain,
( ~ before_on_line(sK1,sK0,sK4)
& distinct_points(sK0,sK4)
& left_apart_point(sK2,sK1)
& distinct_points(sK3,sK4)
& ~ before_on_line(sK1,sK4,sK3)
& ~ apart_point_and_line(sK4,sK1)
& before_on_line(sK1,sK0,sK3) ),
inference(skolemisation,[status(esa),new_symbols(skolem,[sK0,sK1,sK2,sK3,sK4])],[f117,f118]) ).
fof(f118,plain,
( ? [X0,X1,X2,X3,X4] :
( ~ before_on_line(X1,X0,X4)
& distinct_points(X0,X4)
& left_apart_point(X2,X1)
& distinct_points(X3,X4)
& ~ before_on_line(X1,X4,X3)
& ~ apart_point_and_line(X4,X1)
& before_on_line(X1,X0,X3) )
=> ( ~ before_on_line(sK1,sK0,sK4)
& distinct_points(sK0,sK4)
& left_apart_point(sK2,sK1)
& distinct_points(sK3,sK4)
& ~ before_on_line(sK1,sK4,sK3)
& ~ apart_point_and_line(sK4,sK1)
& before_on_line(sK1,sK0,sK3) ) ),
introduced(choice_axiom,[]) ).
fof(f117,plain,
? [X0,X1,X2,X3,X4] :
( ~ before_on_line(X1,X0,X4)
& distinct_points(X0,X4)
& left_apart_point(X2,X1)
& distinct_points(X3,X4)
& ~ before_on_line(X1,X4,X3)
& ~ apart_point_and_line(X4,X1)
& before_on_line(X1,X0,X3) ),
inference(rectify,[],[f87]) ).
fof(f87,plain,
? [X0,X2,X3,X1,X4] :
( ~ before_on_line(X2,X0,X4)
& distinct_points(X0,X4)
& left_apart_point(X3,X2)
& distinct_points(X1,X4)
& ~ before_on_line(X2,X4,X1)
& ~ apart_point_and_line(X4,X2)
& before_on_line(X2,X0,X1) ),
inference(flattening,[],[f86]) ).
fof(f86,plain,
? [X4,X2,X1,X0,X3] :
( ~ before_on_line(X2,X4,X1)
& ~ before_on_line(X2,X0,X4)
& before_on_line(X2,X0,X1)
& ~ apart_point_and_line(X4,X2)
& distinct_points(X1,X4)
& distinct_points(X0,X4)
& left_apart_point(X3,X2) ),
inference(ennf_transformation,[],[f51]) ).
fof(f51,plain,
~ ! [X4,X2,X1,X0,X3] :
( ( ~ apart_point_and_line(X4,X2)
& distinct_points(X1,X4)
& distinct_points(X0,X4)
& left_apart_point(X3,X2) )
=> ( before_on_line(X2,X0,X1)
=> ( before_on_line(X2,X4,X1)
| before_on_line(X2,X0,X4) ) ) ),
inference(rectify,[],[f33]) ).
fof(f33,negated_conjecture,
~ ! [X0,X3,X1,X6,X4] :
( ( ~ apart_point_and_line(X4,X1)
& distinct_points(X0,X4)
& distinct_points(X3,X4)
& left_apart_point(X6,X1) )
=> ( before_on_line(X1,X0,X3)
=> ( before_on_line(X1,X0,X4)
| before_on_line(X1,X4,X3) ) ) ),
inference(negated_conjecture,[],[f32]) ).
fof(f32,conjecture,
! [X0,X3,X1,X6,X4] :
( ( ~ apart_point_and_line(X4,X1)
& distinct_points(X0,X4)
& distinct_points(X3,X4)
& left_apart_point(X6,X1) )
=> ( before_on_line(X1,X0,X3)
=> ( before_on_line(X1,X0,X4)
| before_on_line(X1,X4,X3) ) ) ),
file('/export/starexec/sandbox/benchmark/theBenchmark.p',con) ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12 % Problem : GEO256+1 : TPTP v8.1.0. Bugfixed v6.4.0.
% 0.07/0.13 % Command : vampire --input_syntax tptp --proof tptp --output_axiom_names on --mode portfolio --schedule snake_tptp_sat --cores 0 -t %d %s
% 0.13/0.33 % Computer : n018.cluster.edu
% 0.13/0.33 % Model : x86_64 x86_64
% 0.13/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.33 % Memory : 8042.1875MB
% 0.13/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.33 % CPULimit : 300
% 0.13/0.33 % WCLimit : 300
% 0.13/0.33 % DateTime : Mon Aug 29 21:42:09 EDT 2022
% 0.13/0.34 % CPUTime :
% 0.19/0.43 % (2527)ott+11_1:1_drc=off:nwc=5.0:slsq=on:slsqc=1:spb=goal_then_units:to=lpo:i=467:si=on:rawr=on:rtra=on_0 on theBenchmark for (2999ds/467Mi)
% 0.19/0.44 % (2519)ott+11_2:3_av=off:fde=unused:nwc=5.0:tgt=ground:i=75:si=on:rawr=on:rtra=on_0 on theBenchmark for (2999ds/75Mi)
% 0.19/0.44 % (2527)First to succeed.
% 0.19/0.44 % (2519)Also succeeded, but the first one will report.
% 0.19/0.44 % (2527)Refutation found. Thanks to Tanya!
% 0.19/0.44 % SZS status Theorem for theBenchmark
% 0.19/0.44 % SZS output start Proof for theBenchmark
% See solution above
% 0.19/0.44 % (2527)------------------------------
% 0.19/0.44 % (2527)Version: Vampire 4.7 (commit 807e37dd9 on 2022-08-23 09:55:27 +0200)
% 0.19/0.44 % (2527)Linked with Z3 4.8.13.0 f03d756e086f81f2596157241e0decfb1c982299 z3-4.8.4-5390-gf03d756e0
% 0.19/0.44 % (2527)Termination reason: Refutation
% 0.19/0.44
% 0.19/0.44 % (2527)Memory used [KB]: 5500
% 0.19/0.44 % (2527)Time elapsed: 0.007 s
% 0.19/0.44 % (2527)Instructions burned: 3 (million)
% 0.19/0.44 % (2527)------------------------------
% 0.19/0.44 % (2527)------------------------------
% 0.19/0.44 % (2499)Success in time 0.098 s
%------------------------------------------------------------------------------