TSTP Solution File: GEO250+1 by Etableau---0.67

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Etableau---0.67
% Problem  : GEO250+1 : TPTP v8.1.0. Bugfixed v6.4.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s

% Computer : n027.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Sat Jul 16 04:09:07 EDT 2022

% Result   : Theorem 0.15s 0.40s
% Output   : CNFRefutation 0.15s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    4
%            Number of leaves      :    2
% Syntax   : Number of formulae    :    8 (   3 unt;   0 def)
%            Number of atoms       :   13 (   0 equ)
%            Maximal formula atoms :    2 (   1 avg)
%            Number of connectives :   11 (   6   ~;   1   |;   2   &)
%                                         (   0 <=>;   2  =>;   0  <=;   0 <~>)
%            Maximal formula depth :    6 (   4 avg)
%            Maximal term depth    :    3 (   1 avg)
%            Number of predicates  :    2 (   1 usr;   1 prp; 0-2 aty)
%            Number of functors    :    5 (   5 usr;   3 con; 0-2 aty)
%            Number of variables   :   12 (   2 sgn  10   !;   0   ?)

% Comments : 
%------------------------------------------------------------------------------
fof(con,conjecture,
    ! [X1,X4,X2] :
      ( left_apart_point(X4,parallel_through_point(X2,X1))
     => left_apart_point(X1,reverse_line(parallel_through_point(X2,X4))) ),
    file('/export/starexec/sandbox2/benchmark/theBenchmark.p',con) ).

fof(oag10,axiom,
    ! [X1,X2] :
      ~ ( left_apart_point(X1,X2)
        | left_apart_point(X1,reverse_line(X2)) ),
    file('/export/starexec/sandbox2/benchmark/Axioms/GEO007+0.ax',oag10) ).

fof(c_0_2,negated_conjecture,
    ~ ! [X1,X4,X2] :
        ( left_apart_point(X4,parallel_through_point(X2,X1))
       => left_apart_point(X1,reverse_line(parallel_through_point(X2,X4))) ),
    inference(assume_negation,[status(cth)],[con]) ).

fof(c_0_3,negated_conjecture,
    ( left_apart_point(esk2_0,parallel_through_point(esk3_0,esk1_0))
    & ~ left_apart_point(esk1_0,reverse_line(parallel_through_point(esk3_0,esk2_0))) ),
    inference(skolemize,[status(esa)],[inference(variable_rename,[status(thm)],[inference(fof_nnf,[status(thm)],[c_0_2])])]) ).

fof(c_0_4,plain,
    ! [X40,X41] :
      ( ~ left_apart_point(X40,X41)
      & ~ left_apart_point(X40,reverse_line(X41)) ),
    inference(variable_rename,[status(thm)],[inference(fof_nnf,[status(thm)],[oag10])]) ).

cnf(c_0_5,negated_conjecture,
    left_apart_point(esk2_0,parallel_through_point(esk3_0,esk1_0)),
    inference(split_conjunct,[status(thm)],[c_0_3]) ).

cnf(c_0_6,plain,
    ~ left_apart_point(X1,X2),
    inference(split_conjunct,[status(thm)],[c_0_4]) ).

cnf(c_0_7,negated_conjecture,
    $false,
    inference(sr,[status(thm)],[c_0_5,c_0_6]),
    [proof] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.04/0.14  % Problem  : GEO250+1 : TPTP v8.1.0. Bugfixed v6.4.0.
% 0.15/0.15  % Command  : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s
% 0.15/0.37  % Computer : n027.cluster.edu
% 0.15/0.37  % Model    : x86_64 x86_64
% 0.15/0.37  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.15/0.37  % Memory   : 8042.1875MB
% 0.15/0.37  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.15/0.37  % CPULimit : 300
% 0.15/0.37  % WCLimit  : 600
% 0.15/0.37  % DateTime : Sat Jun 18 01:28:52 EDT 2022
% 0.15/0.37  % CPUTime  : 
% 0.15/0.40  # No SInE strategy applied
% 0.15/0.40  # Auto-Mode selected heuristic G_E___207_C18_F1_SE_CS_SP_PI_PS_S5PRR_S2SI
% 0.15/0.40  # and selection function SelectNewComplexAHP.
% 0.15/0.40  #
% 0.15/0.40  # Presaturation interreduction done
% 0.15/0.40  
% 0.15/0.40  # Proof found!
% 0.15/0.40  # SZS status Theorem
% 0.15/0.40  # SZS output start CNFRefutation
% See solution above
% 0.15/0.40  # Training examples: 0 positive, 0 negative
%------------------------------------------------------------------------------