TSTP Solution File: GEO235+3 by Duper---1.0

View Problem - Process Solution

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% File     : Duper---1.0
% Problem  : GEO235+3 : TPTP v8.1.2. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n009.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Aug 30 22:55:50 EDT 2023

% Result   : Theorem 4.07s 4.24s
% Output   : Proof 4.07s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.08/0.12  % Problem    : GEO235+3 : TPTP v8.1.2. Released v4.0.0.
% 0.08/0.13  % Command    : duper %s
% 0.13/0.35  % Computer : n009.cluster.edu
% 0.13/0.35  % Model    : x86_64 x86_64
% 0.13/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35  % Memory   : 8042.1875MB
% 0.13/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35  % CPULimit   : 300
% 0.13/0.35  % WCLimit    : 300
% 0.13/0.35  % DateTime   : Tue Aug 29 21:01:50 EDT 2023
% 0.13/0.35  % CPUTime    : 
% 4.07/4.24  SZS status Theorem for theBenchmark.p
% 4.07/4.24  SZS output start Proof for theBenchmark.p
% 4.07/4.24  Clause #19 (by assumption #[]): Eq (∀ (A L : Iota), Not (Or (left_apart_point A L) (left_apart_point A (reverse_line L)))) True
% 4.07/4.24  Clause #36 (by assumption #[]): Eq (Not (∀ (A B L : Iota), And (left_apart_point A L) (right_apart_point B L) → distinct_points A B)) True
% 4.07/4.24  Clause #74 (by clausification #[36]): Eq (∀ (A B L : Iota), And (left_apart_point A L) (right_apart_point B L) → distinct_points A B) False
% 4.07/4.24  Clause #75 (by clausification #[74]): ∀ (a : Iota),
% 4.07/4.24    Eq
% 4.07/4.24      (Not (∀ (B L : Iota), And (left_apart_point (skS.0 0 a) L) (right_apart_point B L) → distinct_points (skS.0 0 a) B))
% 4.07/4.24      True
% 4.07/4.24  Clause #76 (by clausification #[75]): ∀ (a : Iota),
% 4.07/4.24    Eq (∀ (B L : Iota), And (left_apart_point (skS.0 0 a) L) (right_apart_point B L) → distinct_points (skS.0 0 a) B)
% 4.07/4.24      False
% 4.07/4.24  Clause #77 (by clausification #[76]): ∀ (a a_1 : Iota),
% 4.07/4.24    Eq
% 4.07/4.24      (Not
% 4.07/4.24        (∀ (L : Iota),
% 4.07/4.24          And (left_apart_point (skS.0 0 a) L) (right_apart_point (skS.0 1 a a_1) L) →
% 4.07/4.24            distinct_points (skS.0 0 a) (skS.0 1 a a_1)))
% 4.07/4.24      True
% 4.07/4.24  Clause #78 (by clausification #[77]): ∀ (a a_1 : Iota),
% 4.07/4.24    Eq
% 4.07/4.24      (∀ (L : Iota),
% 4.07/4.24        And (left_apart_point (skS.0 0 a) L) (right_apart_point (skS.0 1 a a_1) L) →
% 4.07/4.24          distinct_points (skS.0 0 a) (skS.0 1 a a_1))
% 4.07/4.24      False
% 4.07/4.24  Clause #79 (by clausification #[78]): ∀ (a a_1 a_2 : Iota),
% 4.07/4.24    Eq
% 4.07/4.24      (Not
% 4.07/4.24        (And (left_apart_point (skS.0 0 a) (skS.0 2 a a_1 a_2)) (right_apart_point (skS.0 1 a a_1) (skS.0 2 a a_1 a_2)) →
% 4.07/4.24          distinct_points (skS.0 0 a) (skS.0 1 a a_1)))
% 4.07/4.24      True
% 4.07/4.24  Clause #80 (by clausification #[79]): ∀ (a a_1 a_2 : Iota),
% 4.07/4.24    Eq
% 4.07/4.24      (And (left_apart_point (skS.0 0 a) (skS.0 2 a a_1 a_2)) (right_apart_point (skS.0 1 a a_1) (skS.0 2 a a_1 a_2)) →
% 4.07/4.24        distinct_points (skS.0 0 a) (skS.0 1 a a_1))
% 4.07/4.24      False
% 4.07/4.24  Clause #81 (by clausification #[80]): ∀ (a a_1 a_2 : Iota),
% 4.07/4.24    Eq (And (left_apart_point (skS.0 0 a) (skS.0 2 a a_1 a_2)) (right_apart_point (skS.0 1 a a_1) (skS.0 2 a a_1 a_2)))
% 4.07/4.24      True
% 4.07/4.24  Clause #84 (by clausification #[81]): ∀ (a a_1 a_2 : Iota), Eq (left_apart_point (skS.0 0 a) (skS.0 2 a a_1 a_2)) True
% 4.07/4.24  Clause #184 (by clausification #[19]): ∀ (a : Iota), Eq (∀ (L : Iota), Not (Or (left_apart_point a L) (left_apart_point a (reverse_line L)))) True
% 4.07/4.24  Clause #185 (by clausification #[184]): ∀ (a a_1 : Iota), Eq (Not (Or (left_apart_point a a_1) (left_apart_point a (reverse_line a_1)))) True
% 4.07/4.24  Clause #186 (by clausification #[185]): ∀ (a a_1 : Iota), Eq (Or (left_apart_point a a_1) (left_apart_point a (reverse_line a_1))) False
% 4.07/4.24  Clause #188 (by clausification #[186]): ∀ (a a_1 : Iota), Eq (left_apart_point a a_1) False
% 4.07/4.24  Clause #391 (by superposition #[84, 188]): Eq False True
% 4.07/4.24  Clause #392 (by clausification #[391]): False
% 4.07/4.24  SZS output end Proof for theBenchmark.p
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