%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : GEO225+3 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n029.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Sat Jul 16 06:23:41 EDT 2022

% Result   : Theorem 0.20s 0.45s
% Output   : Refutation 0.20s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    4
%            Number of leaves      :    5
% Syntax   : Number of clauses     :   11 (   7 unt;   1 nHn;  11 RR)
%            Number of literals    :   15 (   0 equ;   9 neg)
%            Maximal clause size   :    2 (   1 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    4 (   3 usr;   1 prp; 0-2 aty)
%            Number of functors    :    5 (   5 usr;   4 con; 0-2 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(4,axiom,
    distinct_points(skc3,skc2),
    file('GEO225+3.p',unknown),
    [] ).

cnf(19,axiom,
    ( incident_point_and_line(u,v)
    | apart_point_and_line(u,v) ),
    file('GEO225+3.p',unknown),
    [] ).

cnf(24,axiom,
    ( ~ incident_point_and_line(skc2,u)
    | ~ incident_point_and_line(skc3,u) ),
    file('GEO225+3.p',unknown),
    [] ).

cnf(33,axiom,
    ( ~ distinct_points(u,v)
    | ~ apart_point_and_line(u,line_connecting(u,v)) ),
    file('GEO225+3.p',unknown),
    [] ).

cnf(34,axiom,
    ( ~ distinct_points(u,v)
    | ~ apart_point_and_line(v,line_connecting(u,v)) ),
    file('GEO225+3.p',unknown),
    [] ).

cnf(55,plain,
    ~ apart_point_and_line(skc3,line_connecting(skc3,skc2)),
    inference(res,[status(thm),theory(equality)],[4,33]),
    [iquote('0:Res:4.0,33.0')] ).

cnf(56,plain,
    ~ apart_point_and_line(skc2,line_connecting(skc3,skc2)),
    inference(res,[status(thm),theory(equality)],[4,34]),
    [iquote('0:Res:4.0,34.0')] ).

cnf(72,plain,
    incident_point_and_line(skc2,line_connecting(skc3,skc2)),
    inference(res,[status(thm),theory(equality)],[19,56]),
    [iquote('0:Res:19.1,56.0')] ).

cnf(73,plain,
    incident_point_and_line(skc3,line_connecting(skc3,skc2)),
    inference(res,[status(thm),theory(equality)],[19,55]),
    [iquote('0:Res:19.1,55.0')] ).

cnf(80,plain,
    ~ incident_point_and_line(skc3,line_connecting(skc3,skc2)),
    inference(res,[status(thm),theory(equality)],[72,24]),
    [iquote('0:Res:72.0,24.0')] ).

cnf(81,plain,
    $false,
    inference(mrr,[status(thm)],[80,73]),
    [iquote('0:MRR:80.0,73.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.13  % Problem  : GEO225+3 : TPTP v8.1.0. Released v4.0.0.
% 0.07/0.13  % Command  : run_spass %d %s
% 0.13/0.35  % Computer : n029.cluster.edu
% 0.13/0.35  % Model    : x86_64 x86_64
% 0.13/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35  % Memory   : 8042.1875MB
% 0.13/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35  % CPULimit : 300
% 0.13/0.35  % WCLimit  : 600
% 0.13/0.35  % DateTime : Sat Jun 18 10:46:44 EDT 2022
% 0.13/0.35  % CPUTime  : 
% 0.20/0.45  
% 0.20/0.45  SPASS V 3.9 
% 0.20/0.45  SPASS beiseite: Proof found.
% 0.20/0.45  % SZS status Theorem
% 0.20/0.45  Problem: /export/starexec/sandbox/benchmark/theBenchmark.p 
% 0.20/0.45  SPASS derived 24 clauses, backtracked 0 clauses, performed 0 splits and kept 68 clauses.
% 0.20/0.45  SPASS allocated 97746 KBytes.
% 0.20/0.45  SPASS spent	0:00:00.09 on the problem.
% 0.20/0.45  		0:00:00.04 for the input.
% 0.20/0.45  		0:00:00.03 for the FLOTTER CNF translation.
% 0.20/0.45  		0:00:00.00 for inferences.
% 0.20/0.45  		0:00:00.00 for the backtracking.
% 0.20/0.45  		0:00:00.00 for the reduction.
% 0.20/0.45  
% 0.20/0.45  
% 0.20/0.45  Here is a proof with depth 3, length 11 :
% 0.20/0.45  % SZS output start Refutation
% See solution above
% 0.20/0.45  Formulae used in the proof : con a4 ci1 ci2
% 0.20/0.45  
%------------------------------------------------------------------------------