%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : GEO183+1 : TPTP v8.1.0. Released v3.3.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n016.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Sat Jul 16 06:23:04 EDT 2022

% Result   : Theorem 0.20s 0.45s
% Output   : Refutation 0.20s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    4
%            Number of leaves      :    6
% Syntax   : Number of clauses     :   13 (   8 unt;   2 nHn;  13 RR)
%            Number of literals    :   19 (   0 equ;  11 neg)
%            Maximal clause size   :    3 (   1 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    4 (   3 usr;   1 prp; 0-2 aty)
%            Number of functors    :    7 (   7 usr;   6 con; 0-2 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    distinct_points(skc7,skc6),
    file('GEO183+1.p',unknown),
    [] ).

cnf(6,axiom,
    ~ distinct_lines(skc4,line_connecting(skc7,skc6)),
    file('GEO183+1.p',unknown),
    [] ).

cnf(7,axiom,
    ( apart_point_and_line(skc6,skc4)
    | apart_point_and_line(skc7,skc4) ),
    file('GEO183+1.p',unknown),
    [] ).

cnf(11,axiom,
    ( ~ distinct_points(u,v)
    | ~ apart_point_and_line(u,line_connecting(u,v)) ),
    file('GEO183+1.p',unknown),
    [] ).

cnf(12,axiom,
    ( ~ distinct_points(u,v)
    | ~ apart_point_and_line(v,line_connecting(u,v)) ),
    file('GEO183+1.p',unknown),
    [] ).

cnf(16,axiom,
    ( ~ apart_point_and_line(u,v)
    | distinct_lines(v,w)
    | apart_point_and_line(u,w) ),
    file('GEO183+1.p',unknown),
    [] ).

cnf(25,plain,
    ~ apart_point_and_line(skc7,line_connecting(skc7,skc6)),
    inference(res,[status(thm),theory(equality)],[1,11]),
    [iquote('0:Res:1.0,11.0')] ).

cnf(26,plain,
    ~ apart_point_and_line(skc6,line_connecting(skc7,skc6)),
    inference(res,[status(thm),theory(equality)],[1,12]),
    [iquote('0:Res:1.0,12.0')] ).

cnf(29,plain,
    ( ~ apart_point_and_line(u,skc4)
    | apart_point_and_line(u,line_connecting(skc7,skc6)) ),
    inference(res,[status(thm),theory(equality)],[16,6]),
    [iquote('0:Res:16.2,6.0')] ).

cnf(43,plain,
    ~ apart_point_and_line(skc6,skc4),
    inference(res,[status(thm),theory(equality)],[29,26]),
    [iquote('0:Res:29.1,26.0')] ).

cnf(44,plain,
    ~ apart_point_and_line(skc7,skc4),
    inference(res,[status(thm),theory(equality)],[29,25]),
    [iquote('0:Res:29.1,25.0')] ).

cnf(46,plain,
    apart_point_and_line(skc7,skc4),
    inference(mrr,[status(thm)],[7,43]),
    [iquote('0:MRR:7.0,43.0')] ).

cnf(47,plain,
    $false,
    inference(mrr,[status(thm)],[44,46]),
    [iquote('0:MRR:44.0,46.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.04/0.12  % Problem  : GEO183+1 : TPTP v8.1.0. Released v3.3.0.
% 0.04/0.13  % Command  : run_spass %d %s
% 0.13/0.34  % Computer : n016.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % WCLimit  : 600
% 0.13/0.34  % DateTime : Sat Jun 18 11:15:22 EDT 2022
% 0.13/0.35  % CPUTime  : 
% 0.20/0.45  
% 0.20/0.45  SPASS V 3.9 
% 0.20/0.45  SPASS beiseite: Proof found.
% 0.20/0.45  % SZS status Theorem
% 0.20/0.45  Problem: /export/starexec/sandbox/benchmark/theBenchmark.p 
% 0.20/0.45  SPASS derived 28 clauses, backtracked 0 clauses, performed 0 splits and kept 38 clauses.
% 0.20/0.45  SPASS allocated 85161 KBytes.
% 0.20/0.45  SPASS spent	0:00:00.09 on the problem.
% 0.20/0.45  		0:00:00.04 for the input.
% 0.20/0.45  		0:00:00.03 for the FLOTTER CNF translation.
% 0.20/0.45  		0:00:00.00 for inferences.
% 0.20/0.45  		0:00:00.00 for the backtracking.
% 0.20/0.45  		0:00:00.00 for the reduction.
% 0.20/0.45  
% 0.20/0.45  
% 0.20/0.45  Here is a proof with depth 2, length 13 :
% 0.20/0.45  % SZS output start Refutation
% See solution above
% 0.20/0.45  Formulae used in the proof : con ci1 ci2 ceq2
% 0.20/0.45  
%------------------------------------------------------------------------------