TSTP Solution File: GEO182+1 by SPASS---3.9

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%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : GEO182+1 : TPTP v8.1.0. Released v3.3.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n018.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Sat Jul 16 06:23:03 EDT 2022

% Result   : Theorem 0.19s 0.45s
% Output   : Refutation 0.19s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    8
%            Number of leaves      :    9
% Syntax   : Number of clauses     :   22 (  11 unt;   7 nHn;  22 RR)
%            Number of literals    :   44 (   0 equ;  16 neg)
%            Maximal clause size   :    6 (   2 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    4 (   3 usr;   1 prp; 0-2 aty)
%            Number of functors    :    8 (   8 usr;   7 con; 0-2 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    distinct_points(skc3,skc4),
    file('GEO182+1.p',unknown),
    [] ).

cnf(2,axiom,
    ~ distinct_points(u,u),
    file('GEO182+1.p',unknown),
    [] ).

cnf(5,axiom,
    apart_point_and_line(skc5,line_connecting(skc3,skc4)),
    file('GEO182+1.p',unknown),
    [] ).

cnf(6,axiom,
    ~ apart_point_and_line(skc5,line_connecting(skc4,skc3)),
    file('GEO182+1.p',unknown),
    [] ).

cnf(7,axiom,
    ( ~ distinct_points(u,v)
    | distinct_points(v,w)
    | distinct_points(u,w) ),
    file('GEO182+1.p',unknown),
    [] ).

cnf(10,axiom,
    ( ~ distinct_points(u,v)
    | ~ apart_point_and_line(u,line_connecting(u,v)) ),
    file('GEO182+1.p',unknown),
    [] ).

cnf(11,axiom,
    ( ~ distinct_points(u,v)
    | ~ apart_point_and_line(v,line_connecting(u,v)) ),
    file('GEO182+1.p',unknown),
    [] ).

cnf(15,axiom,
    ( ~ apart_point_and_line(u,v)
    | distinct_lines(v,w)
    | apart_point_and_line(u,w) ),
    file('GEO182+1.p',unknown),
    [] ).

cnf(17,axiom,
    ( ~ distinct_lines(u,v)
    | ~ distinct_points(w,x)
    | apart_point_and_line(x,u)
    | apart_point_and_line(x,v)
    | apart_point_and_line(w,v)
    | apart_point_and_line(w,u) ),
    file('GEO182+1.p',unknown),
    [] ).

cnf(18,plain,
    ( ~ distinct_lines(u,v)
    | apart_point_and_line(skc4,u)
    | apart_point_and_line(skc4,v)
    | apart_point_and_line(skc3,v)
    | apart_point_and_line(skc3,u) ),
    inference(res,[status(thm),theory(equality)],[1,17]),
    [iquote('0:Res:1.0,17.0')] ).

cnf(19,plain,
    ( distinct_points(skc4,u)
    | distinct_points(skc3,u) ),
    inference(res,[status(thm),theory(equality)],[1,7]),
    [iquote('0:Res:1.0,7.0')] ).

cnf(20,plain,
    ~ apart_point_and_line(skc3,line_connecting(skc3,skc4)),
    inference(res,[status(thm),theory(equality)],[1,10]),
    [iquote('0:Res:1.0,10.0')] ).

cnf(21,plain,
    ~ apart_point_and_line(skc4,line_connecting(skc3,skc4)),
    inference(res,[status(thm),theory(equality)],[1,11]),
    [iquote('0:Res:1.0,11.0')] ).

cnf(25,plain,
    ( ~ apart_point_and_line(skc5,u)
    | distinct_lines(u,line_connecting(skc4,skc3)) ),
    inference(res,[status(thm),theory(equality)],[15,6]),
    [iquote('0:Res:15.1,6.0')] ).

cnf(30,plain,
    distinct_lines(line_connecting(skc3,skc4),line_connecting(skc4,skc3)),
    inference(res,[status(thm),theory(equality)],[5,25]),
    [iquote('0:Res:5.0,25.0')] ).

cnf(56,plain,
    distinct_points(skc4,skc3),
    inference(res,[status(thm),theory(equality)],[19,2]),
    [iquote('0:Res:19.1,2.0')] ).

cnf(156,plain,
    ( apart_point_and_line(skc4,line_connecting(skc3,skc4))
    | apart_point_and_line(skc4,line_connecting(skc4,skc3))
    | apart_point_and_line(skc3,line_connecting(skc4,skc3))
    | apart_point_and_line(skc3,line_connecting(skc3,skc4)) ),
    inference(res,[status(thm),theory(equality)],[30,18]),
    [iquote('0:Res:30.0,18.0')] ).

cnf(159,plain,
    ( apart_point_and_line(skc4,line_connecting(skc4,skc3))
    | apart_point_and_line(skc3,line_connecting(skc4,skc3)) ),
    inference(mrr,[status(thm)],[156,21,20]),
    [iquote('0:MRR:156.0,156.3,21.0,20.0')] ).

cnf(232,plain,
    ( ~ distinct_points(skc4,skc3)
    | apart_point_and_line(skc4,line_connecting(skc4,skc3)) ),
    inference(res,[status(thm),theory(equality)],[159,11]),
    [iquote('0:Res:159.1,11.1')] ).

cnf(235,plain,
    apart_point_and_line(skc4,line_connecting(skc4,skc3)),
    inference(mrr,[status(thm)],[232,56]),
    [iquote('0:MRR:232.0,56.0')] ).

cnf(237,plain,
    ~ distinct_points(skc4,skc3),
    inference(res,[status(thm),theory(equality)],[235,10]),
    [iquote('0:Res:235.0,10.1')] ).

cnf(240,plain,
    $false,
    inference(mrr,[status(thm)],[237,56]),
    [iquote('0:MRR:237.0,56.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.12  % Problem  : GEO182+1 : TPTP v8.1.0. Released v3.3.0.
% 0.06/0.12  % Command  : run_spass %d %s
% 0.12/0.33  % Computer : n018.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 600
% 0.12/0.33  % DateTime : Sat Jun 18 02:36:32 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 0.19/0.45  
% 0.19/0.45  SPASS V 3.9 
% 0.19/0.45  SPASS beiseite: Proof found.
% 0.19/0.45  % SZS status Theorem
% 0.19/0.45  Problem: /export/starexec/sandbox/benchmark/theBenchmark.p 
% 0.19/0.45  SPASS derived 189 clauses, backtracked 0 clauses, performed 0 splits and kept 102 clauses.
% 0.19/0.45  SPASS allocated 85218 KBytes.
% 0.19/0.45  SPASS spent	0:00:00.10 on the problem.
% 0.19/0.45  		0:00:00.03 for the input.
% 0.19/0.45  		0:00:00.03 for the FLOTTER CNF translation.
% 0.19/0.45  		0:00:00.00 for inferences.
% 0.19/0.45  		0:00:00.00 for the backtracking.
% 0.19/0.45  		0:00:00.01 for the reduction.
% 0.19/0.45  
% 0.19/0.45  
% 0.19/0.45  Here is a proof with depth 5, length 22 :
% 0.19/0.45  % SZS output start Refutation
% See solution above
% 0.19/0.45  Formulae used in the proof : con apart1 apart4 ci1 ci2 ceq2 cu1
% 0.19/0.45  
%------------------------------------------------------------------------------