TSTP Solution File: GEO081+1 by SPASS---3.9

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : GEO081+1 : TPTP v8.1.0. Released v2.4.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n025.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Sat Jul 16 06:22:09 EDT 2022

% Result   : Theorem 0.20s 0.49s
% Output   : Refutation 0.20s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    3
%            Number of leaves      :    6
% Syntax   : Number of clauses     :   12 (   8 unt;   0 nHn;  12 RR)
%            Number of literals    :   17 (   0 equ;   8 neg)
%            Maximal clause size   :    3 (   1 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    3 (   2 usr;   1 prp; 0-2 aty)
%            Number of functors    :    7 (   7 usr;   6 con; 0-2 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    part_of(skc5,skc3),
    file('GEO081+1.p',unknown),
    [] ).

cnf(2,axiom,
    part_of(skc3,skc4),
    file('GEO081+1.p',unknown),
    [] ).

cnf(3,axiom,
    ~ part_of(skc5,skc4),
    file('GEO081+1.p',unknown),
    [] ).

cnf(5,axiom,
    incident_c(skf12(u,v),v),
    file('GEO081+1.p',unknown),
    [] ).

cnf(16,axiom,
    ( ~ incident_c(skf12(u,v),u)
    | part_of(v,u) ),
    file('GEO081+1.p',unknown),
    [] ).

cnf(23,axiom,
    ( ~ incident_c(u,v)
    | ~ part_of(v,w)
    | incident_c(u,w) ),
    file('GEO081+1.p',unknown),
    [] ).

cnf(48,plain,
    ( ~ incident_c(u,skc3)
    | incident_c(u,skc4) ),
    inference(res,[status(thm),theory(equality)],[2,23]),
    [iquote('0:Res:2.0,23.0')] ).

cnf(55,plain,
    ( ~ incident_c(u,skc5)
    | incident_c(u,skc3) ),
    inference(res,[status(thm),theory(equality)],[1,23]),
    [iquote('0:Res:1.0,23.0')] ).

cnf(60,plain,
    ~ incident_c(skf12(skc4,skc5),skc4),
    inference(res,[status(thm),theory(equality)],[16,3]),
    [iquote('0:Res:16.1,3.0')] ).

cnf(155,plain,
    incident_c(skf12(u,skc5),skc3),
    inference(res,[status(thm),theory(equality)],[5,55]),
    [iquote('0:Res:5.0,55.0')] ).

cnf(157,plain,
    ~ incident_c(skf12(skc4,skc5),skc3),
    inference(res,[status(thm),theory(equality)],[48,60]),
    [iquote('0:Res:48.1,60.0')] ).

cnf(158,plain,
    $false,
    inference(mrr,[status(thm)],[157,155]),
    [iquote('0:MRR:157.0,155.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.11  % Problem  : GEO081+1 : TPTP v8.1.0. Released v2.4.0.
% 0.06/0.12  % Command  : run_spass %d %s
% 0.12/0.33  % Computer : n025.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 600
% 0.12/0.33  % DateTime : Sat Jun 18 01:08:42 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 0.20/0.49  
% 0.20/0.49  SPASS V 3.9 
% 0.20/0.49  SPASS beiseite: Proof found.
% 0.20/0.49  % SZS status Theorem
% 0.20/0.49  Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p 
% 0.20/0.49  SPASS derived 77 clauses, backtracked 29 clauses, performed 6 splits and kept 116 clauses.
% 0.20/0.49  SPASS allocated 98531 KBytes.
% 0.20/0.49  SPASS spent	0:00:00.15 on the problem.
% 0.20/0.49  		0:00:00.04 for the input.
% 0.20/0.49  		0:00:00.07 for the FLOTTER CNF translation.
% 0.20/0.49  		0:00:00.00 for inferences.
% 0.20/0.49  		0:00:00.00 for the backtracking.
% 0.20/0.49  		0:00:00.01 for the reduction.
% 0.20/0.49  
% 0.20/0.49  
% 0.20/0.49  Here is a proof with depth 2, length 12 :
% 0.20/0.49  % SZS output start Refutation
% See solution above
% 0.20/0.49  Formulae used in the proof : part_of_transitivity part_of_defn c3 inner_point_defn
% 0.20/0.49  
%------------------------------------------------------------------------------