TSTP Solution File: GEO015-2 by SOS---2.0
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- Process Solution
%------------------------------------------------------------------------------
% File : SOS---2.0
% Problem : GEO015-2 : TPTP v8.1.0. Released v1.0.0.
% Transfm : none
% Format : tptp:raw
% Command : sos-script %s
% Computer : n014.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Sat Jul 16 06:17:25 EDT 2022
% Result : Unsatisfiable 0.20s 0.50s
% Output : Refutation 0.20s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.04/0.13 % Problem : GEO015-2 : TPTP v8.1.0. Released v1.0.0.
% 0.12/0.13 % Command : sos-script %s
% 0.13/0.34 % Computer : n014.cluster.edu
% 0.13/0.34 % Model : x86_64 x86_64
% 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34 % Memory : 8042.1875MB
% 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34 % CPULimit : 300
% 0.13/0.34 % WCLimit : 600
% 0.13/0.34 % DateTime : Fri Jun 17 18:53:34 EDT 2022
% 0.13/0.35 % CPUTime :
% 0.20/0.37 ----- Otter 3.2, August 2001 -----
% 0.20/0.37 The process was started by sandbox on n014.cluster.edu,
% 0.20/0.37 Fri Jun 17 18:53:34 2022
% 0.20/0.37 The command was "./sos". The process ID is 10083.
% 0.20/0.37
% 0.20/0.37 set(prolog_style_variables).
% 0.20/0.37 set(auto).
% 0.20/0.37 dependent: set(auto1).
% 0.20/0.37 dependent: set(process_input).
% 0.20/0.37 dependent: clear(print_kept).
% 0.20/0.37 dependent: clear(print_new_demod).
% 0.20/0.37 dependent: clear(print_back_demod).
% 0.20/0.37 dependent: clear(print_back_sub).
% 0.20/0.37 dependent: set(control_memory).
% 0.20/0.37 dependent: assign(max_mem, 12000).
% 0.20/0.37 dependent: assign(pick_given_ratio, 4).
% 0.20/0.37 dependent: assign(stats_level, 1).
% 0.20/0.37 dependent: assign(pick_semantic_ratio, 3).
% 0.20/0.37 dependent: assign(sos_limit, 5000).
% 0.20/0.37 dependent: assign(max_weight, 60).
% 0.20/0.37 clear(print_given).
% 0.20/0.37
% 0.20/0.37 list(usable).
% 0.20/0.37
% 0.20/0.37 SCAN INPUT: prop=0, horn=0, equality=1, symmetry=0, max_lits=8.
% 0.20/0.37
% 0.20/0.37 This ia a non-Horn set with equality. The strategy will be
% 0.20/0.37 Knuth-Bendix, ordered hyper_res, ur_res, factoring, and
% 0.20/0.37 unit deletion, with positive clauses in sos and nonpositive
% 0.20/0.37 clauses in usable.
% 0.20/0.37
% 0.20/0.37 dependent: set(knuth_bendix).
% 0.20/0.37 dependent: set(para_from).
% 0.20/0.37 dependent: set(para_into).
% 0.20/0.37 dependent: clear(para_from_right).
% 0.20/0.37 dependent: clear(para_into_right).
% 0.20/0.37 dependent: set(para_from_vars).
% 0.20/0.37 dependent: set(eq_units_both_ways).
% 0.20/0.37 dependent: set(dynamic_demod_all).
% 0.20/0.37 dependent: set(dynamic_demod).
% 0.20/0.37 dependent: set(order_eq).
% 0.20/0.37 dependent: set(back_demod).
% 0.20/0.37 dependent: set(lrpo).
% 0.20/0.37 dependent: set(hyper_res).
% 0.20/0.37 dependent: set(unit_deletion).
% 0.20/0.37 dependent: set(factor).
% 0.20/0.37
% 0.20/0.37 ------------> process usable:
% 0.20/0.37
% 0.20/0.37 ------------> process sos:
% 0.20/0.37 35 back subsumes 32.
% 0.20/0.37 Following clause subsumed by 39 during input processing: 0 [copy,39,flip.1] {-} A=A.
% 0.20/0.37
% 0.20/0.37 ======= end of input processing =======
% 0.20/0.48
% 0.20/0.48 Model 1 (0.00 seconds, 0 Inserts)
% 0.20/0.48
% 0.20/0.48 Stopped by limit on number of solutions
% 0.20/0.48
% 0.20/0.48
% 0.20/0.48 -------------- Softie stats --------------
% 0.20/0.48
% 0.20/0.48 UPDATE_STOP: 300
% 0.20/0.48 SFINDER_TIME_LIMIT: 2
% 0.20/0.48 SHORT_CLAUSE_CUTOFF: 4
% 0.20/0.48 number of clauses in intial UL: 33
% 0.20/0.48 number of clauses initially in problem: 38
% 0.20/0.48 percentage of clauses intially in UL: 86
% 0.20/0.48 percentage of distinct symbols occuring in initial UL: 93
% 0.20/0.48 percent of all initial clauses that are short: 100
% 0.20/0.48 absolute distinct symbol count: 15
% 0.20/0.48 distinct predicate count: 3
% 0.20/0.48 distinct function count: 5
% 0.20/0.48 distinct constant count: 7
% 0.20/0.48
% 0.20/0.48 ---------- no more Softie stats ----------
% 0.20/0.48
% 0.20/0.48
% 0.20/0.48
% 0.20/0.48 Model 2 (0.00 seconds, 0 Inserts)
% 0.20/0.48
% 0.20/0.48 Stopped by limit on number of solutions
% 0.20/0.48
% 0.20/0.48 =========== start of search ===========
% 0.20/0.50
% 0.20/0.50 -------- PROOF --------
% 0.20/0.50 % SZS status Unsatisfiable
% 0.20/0.50 % SZS output start Refutation
% 0.20/0.50
% 0.20/0.50 ----> UNIT CONFLICT at 0.11 sec ----> 112 [binary,111.1,16.1] {-} $F.
% 0.20/0.50
% 0.20/0.50 Length of proof is 2. Level of proof is 2.
% 0.20/0.50
% 0.20/0.50 ---------------- PROOF ----------------
% 0.20/0.50 % SZS status Unsatisfiable
% 0.20/0.50 % SZS output start Refutation
% 0.20/0.50
% 0.20/0.50 1 [] {+} -equidistant(A,B,C,D)| -equidistant(A,B,E,F)|equidistant(C,D,E,F).
% 0.20/0.50 16 [] {+} -equidistant(w,x,u,v).
% 0.20/0.50 35 [] {+} equidistant(A,B,B,A).
% 0.20/0.50 38 [] {-} equidistant(u,v,w,x).
% 0.20/0.50 41 [hyper,38,1,35] {-} equidistant(v,u,w,x).
% 0.20/0.50 111 [hyper,41,1,35] {-} equidistant(w,x,u,v).
% 0.20/0.50 112 [binary,111.1,16.1] {-} $F.
% 0.20/0.50
% 0.20/0.50 % SZS output end Refutation
% 0.20/0.50 ------------ end of proof -------------
% 0.20/0.50
% 0.20/0.50
% 0.20/0.50 Search stopped by max_proofs option.
% 0.20/0.50
% 0.20/0.50
% 0.20/0.50 Search stopped by max_proofs option.
% 0.20/0.50
% 0.20/0.50 ============ end of search ============
% 0.20/0.50
% 0.20/0.50 ----------- soft-scott stats ----------
% 0.20/0.50
% 0.20/0.50 true clauses given 0 (0.0%)
% 0.20/0.50 false clauses given 3
% 0.20/0.50
% 0.20/0.50 FALSE TRUE
% 0.20/0.50 3 0 1
% 0.20/0.50 5 1 1
% 0.20/0.50 8 1 0
% 0.20/0.50 9 2 3
% 0.20/0.50 10 4 0
% 0.20/0.50 14 4 0
% 0.20/0.50 18 1 7
% 0.20/0.50 22 2 6
% 0.20/0.50 23 1 4
% 0.20/0.50 24 0 4
% 0.20/0.50 27 5 3
% 0.20/0.50 28 0 3
% 0.20/0.50 32 4 0
% 0.20/0.50 33 0 12
% 0.20/0.50 38 0 4
% 0.20/0.50 tot: 25 48 (65.8% true)
% 0.20/0.50
% 0.20/0.50
% 0.20/0.50 Model 2 (0.00 seconds, 0 Inserts)
% 0.20/0.50
% 0.20/0.50 That finishes the proof of the theorem.
% 0.20/0.50
% 0.20/0.50 Process 10083 finished Fri Jun 17 18:53:34 2022
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