TSTP Solution File: DAT100_1 by SPASS+T---2.2.22
View Problem
- Process Solution
%------------------------------------------------------------------------------
% File : SPASS+T---2.2.22
% Problem : DAT100_1 : TPTP v8.1.0. Released v6.1.0.
% Transfm : none
% Format : tptp:raw
% Command : spasst-tptp-script %s %d
% Computer : n021.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Sat Jul 16 01:32:13 EDT 2022
% Result : Theorem 0.45s 1.06s
% Output : Refutation 0.45s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.12/0.12 % Problem : DAT100_1 : TPTP v8.1.0. Released v6.1.0.
% 0.12/0.13 % Command : spasst-tptp-script %s %d
% 0.12/0.34 % Computer : n021.cluster.edu
% 0.12/0.34 % Model : x86_64 x86_64
% 0.12/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34 % Memory : 8042.1875MB
% 0.12/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34 % CPULimit : 300
% 0.12/0.34 % WCLimit : 600
% 0.12/0.34 % DateTime : Fri Jul 1 17:46:29 EDT 2022
% 0.12/0.34 % CPUTime :
% 0.19/0.48 % Using integer theory
% 0.45/1.06
% 0.45/1.06
% 0.45/1.06 % SZS status Theorem for /tmp/SPASST_7065_n021.cluster.edu
% 0.45/1.06
% 0.45/1.06 SPASS V 2.2.22 in combination with yices.
% 0.45/1.06 SPASS beiseite: Proof found by SMT.
% 0.45/1.06 Problem: /tmp/SPASST_7065_n021.cluster.edu
% 0.45/1.06 SPASS derived 79 clauses, backtracked 0 clauses and kept 76 clauses.
% 0.45/1.06 SPASS backtracked 1 times (1 times due to theory inconsistency).
% 0.45/1.06 SPASS allocated 6362 KBytes.
% 0.45/1.06 SPASS spent 0:00:00.02 on the problem.
% 0.45/1.06 0:00:00.00 for the input.
% 0.45/1.06 0:00:00.01 for the FLOTTER CNF translation.
% 0.45/1.06 0:00:00.00 for inferences.
% 0.45/1.06 0:00:00.00 for the backtracking.
% 0.45/1.06 0:00:00.01 for the reduction.
% 0.45/1.06 0:00:00.00 for interacting with the SMT procedure.
% 0.45/1.06
% 0.45/1.06
% 0.45/1.06 % SZS output start CNFRefutation for /tmp/SPASST_7065_n021.cluster.edu
% 0.45/1.06
% 0.45/1.06 % Here is a proof with depth 0, length 11 :
% 0.45/1.06 2[0:Inp] || -> list(nil)*.
% 0.45/1.06 5[0:Inp] || -> inRange(U,skf2(U,V))*.
% 0.45/1.06 7[0:Inp] || list(U) -> list(cons(V,U))*.
% 0.45/1.06 8[0:Inp] || list(U) equal(cons(V,U),nil)** -> .
% 0.45/1.06 9[0:Inp] || list(U) -> equal(tail(cons(V,U)),U)**.
% 0.45/1.06 10[0:Inp] || list(U) -> equal(head(cons(V,U)),V)**.
% 0.45/1.06 11[0:Inp] || -> inRange(4,cons(1,cons(5,cons(2,nil))))*.
% 0.45/1.06 14[0:Inp] || list(U) inRange(V,U) -> list(skf2(V,U))* equal(U,nil).
% 0.45/1.06 15[0:Inp] || list(U) inRange(V,U) -> equal(U,nil) less(skf3(V,U),V)*.
% 0.45/1.06 16[0:Inp] || list(U) inRange(V,U) -> equal(U,nil) equal(cons(skf3(V,U),skf2(V,U)),U)**.
% 0.45/1.06 156(e)[0:ThR:16,15,14,11,10,9,8,7,5,2] || -> .
% 0.45/1.06
% 0.45/1.06 % SZS output end CNFRefutation for /tmp/SPASST_7065_n021.cluster.edu
% 0.45/1.06
% 0.45/1.06 Formulae used in the proof : fof_head_type fof_inRange fof_nil_type fof_cons_type fof_tail_type fof_l2 fof_l4 fof_l1 fof_l3
% 0.45/1.06
% 0.45/1.06 SPASS+T ended
%------------------------------------------------------------------------------