TSTP Solution File: DAT092_1 by SPASS+T---2.2.22
View Problem
- Process Solution
%------------------------------------------------------------------------------
% File : SPASS+T---2.2.22
% Problem : DAT092_1 : TPTP v8.1.0. Released v6.1.0.
% Transfm : none
% Format : tptp:raw
% Command : spasst-tptp-script %s %d
% Computer : n020.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Sat Jul 16 01:32:11 EDT 2022
% Result : Theorem 0.75s 1.03s
% Output : Refutation 0.75s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12 % Problem : DAT092_1 : TPTP v8.1.0. Released v6.1.0.
% 0.03/0.12 % Command : spasst-tptp-script %s %d
% 0.13/0.33 % Computer : n020.cluster.edu
% 0.13/0.33 % Model : x86_64 x86_64
% 0.13/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.33 % Memory : 8042.1875MB
% 0.13/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.33 % CPULimit : 300
% 0.13/0.33 % WCLimit : 600
% 0.13/0.33 % DateTime : Fri Jul 1 20:50:00 EDT 2022
% 0.13/0.33 % CPUTime :
% 0.18/0.46 % Using integer theory
% 0.75/1.03
% 0.75/1.03
% 0.75/1.03 % SZS status Theorem for /tmp/SPASST_13533_n020.cluster.edu
% 0.75/1.03
% 0.75/1.03 SPASS V 2.2.22 in combination with yices.
% 0.75/1.03 SPASS beiseite: Proof found by SPASS.
% 0.75/1.03 Problem: /tmp/SPASST_13533_n020.cluster.edu
% 0.75/1.03 SPASS derived 20 clauses, backtracked 0 clauses and kept 74 clauses.
% 0.75/1.03 SPASS backtracked 0 times (0 times due to theory inconsistency).
% 0.75/1.03 SPASS allocated 6491 KBytes.
% 0.75/1.03 SPASS spent 0:00:00.02 on the problem.
% 0.75/1.03 0:00:00.00 for the input.
% 0.75/1.03 0:00:00.01 for the FLOTTER CNF translation.
% 0.75/1.03 0:00:00.00 for inferences.
% 0.75/1.03 0:00:00.00 for the backtracking.
% 0.75/1.03 0:00:00.00 for the reduction.
% 0.75/1.03 0:00:00.00 for interacting with the SMT procedure.
% 0.75/1.03
% 0.75/1.03
% 0.75/1.03 % SZS output start CNFRefutation for /tmp/SPASST_13533_n020.cluster.edu
% 0.75/1.03
% 0.75/1.03 % Here is a proof with depth 2, length 16 :
% 0.75/1.03 4[0:Inp] || -> list(nil)*.
% 0.75/1.03 6[0:Inp] || -> equal(length(nil),0)**.
% 0.75/1.03 7[0:Inp] || -> list(skf6(U,V))*.
% 0.75/1.03 13[0:Inp] || list(U) -> list(cons(V,U))*.
% 0.75/1.03 14[0:Inp] || list(U) -> equal(append(nil,U),U)**.
% 0.75/1.03 22[0:Inp] || list(U) -> equal(length(cons(V,U)),plus(1,length(U)))**.
% 0.75/1.03 24[0:Inp] || list(U) list(V) -> equal(length(append(V,U)),length(V))**.
% 0.75/1.03 67[0:ArS:22.1] || list(U) -> equal(length(cons(V,U)),plus(length(U),1))**.
% 0.75/1.03 77[0:Res:4.0,24.1] || list(U) -> equal(length(append(nil,U)),length(nil))**.
% 0.75/1.03 80[0:Rew:14.1,77.1,6.0,77.1] || list(U) -> equal(length(U),0)**.
% 0.75/1.03 82[0:Rew:80.1,67.1] || list(U) -> equal(length(cons(V,U)),plus(0,1))**.
% 0.75/1.03 85[0:ArS:82.1] || list(U) -> equal(length(cons(V,U)),1)**.
% 0.75/1.03 102[0:SpR:85.1,80.1] || list(U) list(cons(V,U))* -> equal(1,0).
% 0.75/1.03 105[0:ArS:102.2] || list(U) list(cons(V,U))* -> .
% 0.75/1.03 106[0:MRR:105.1,13.1] || list(U)* -> .
% 0.75/1.03 107(e)[0:UnC:106.0,7.0] || -> .
% 0.75/1.03
% 0.75/1.03 % SZS output end CNFRefutation for /tmp/SPASST_13533_n020.cluster.edu
% 0.75/1.03
% 0.75/1.03 Formulae used in the proof : fof_head_type fof_list_type fof_l fof_tail_type fof_cons_type fof_a_8 fof_l3
% 0.75/1.05
% 0.75/1.06 SPASS+T ended
%------------------------------------------------------------------------------