TSTP Solution File: DAT068_1 by SPASS+T---2.2.22

View Problem - Process Solution

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% File     : SPASS+T---2.2.22
% Problem  : DAT068_1 : TPTP v8.1.0. Released v5.5.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : spasst-tptp-script %s %d

% Computer : n011.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Sat Jul 16 01:32:03 EDT 2022

% Result   : Theorem 0.80s 1.08s
% Output   : Refutation 0.80s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.12  % Problem  : DAT068_1 : TPTP v8.1.0. Released v5.5.0.
% 0.06/0.12  % Command  : spasst-tptp-script %s %d
% 0.12/0.33  % Computer : n011.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 600
% 0.12/0.33  % DateTime : Fri Jul  1 17:12:04 EDT 2022
% 0.12/0.34  % CPUTime  : 
% 0.18/0.46  % Using integer theory
% 0.80/1.08  
% 0.80/1.08  
% 0.80/1.08  % SZS status Theorem for /tmp/SPASST_24186_n011.cluster.edu
% 0.80/1.08  
% 0.80/1.08  SPASS V 2.2.22  in combination with yices.
% 0.80/1.08  SPASS beiseite: Proof found by SPASS.
% 0.80/1.08  Problem: /tmp/SPASST_24186_n011.cluster.edu 
% 0.80/1.08  SPASS derived 100 clauses, backtracked 33 clauses and kept 158 clauses.
% 0.80/1.08  SPASS backtracked 2 times (0 times due to theory inconsistency).
% 0.80/1.08  SPASS allocated 6357 KBytes.
% 0.80/1.08  SPASS spent	0:00:00.02 on the problem.
% 0.80/1.08  		0:00:00.00 for the input.
% 0.80/1.08  		0:00:00.00 for the FLOTTER CNF translation.
% 0.80/1.08  		0:00:00.00 for inferences.
% 0.80/1.08  		0:00:00.00 for the backtracking.
% 0.80/1.08  		0:00:00.01 for the reduction.
% 0.80/1.08  		0:00:00.00 for interacting with the SMT procedure.
% 0.80/1.08  		
% 0.80/1.08  
% 0.80/1.08  % SZS output start CNFRefutation for /tmp/SPASST_24186_n011.cluster.edu
% 0.80/1.08  
% 0.80/1.08  % Here is a proof with depth 2, length 13 :
% 0.80/1.08  6[0:Inp] ||  -> heap(skc4)*.
% 0.80/1.08  8[0:Inp] ||  -> less(skc5,length(skc4))*.
% 0.80/1.08  17(e)[0:Inp] || equal(sel(app(skc4,skc6),skc5),sel(skc4,skc5))** -> .
% 0.80/1.08  26[0:Inp] || heap(U) -> equal(V,plus(1,length(U))) equal(sel(app(U,W),V),sel(U,V))**.
% 0.80/1.08  33[0:ThA] ||  -> equal(plus(plus(U,V),uminus(V)),U)**.
% 0.80/1.08  40[0:ThA] ||  -> less(plus(U,-1),U)*.
% 0.80/1.08  62(e)[0:ArS:26.1] || heap(U) -> equal(V,plus(length(U),1)) equal(sel(app(U,W),V),sel(U,V))**.
% 0.80/1.08  91[0:Res:62.2,17.0] || heap(skc4) -> equal(plus(length(skc4),1),skc5)**.
% 0.80/1.08  96[0:MRR:91.0,6.0] ||  -> equal(plus(length(skc4),1),skc5)**.
% 0.80/1.08  184[0:SpR:96.0,33.0] ||  -> equal(length(skc4),plus(skc5,uminus(1)))**.
% 0.80/1.08  190(e)[0:ArS:184.0] ||  -> equal(length(skc4),plus(skc5,-1))**.
% 0.80/1.08  191[0:Rew:190.0,8.0] ||  -> less(skc5,plus(skc5,-1))*.
% 0.80/1.08  200(e)[0:OCE:191.0,40.0] ||  -> .
% 0.80/1.08  
% 0.80/1.08  % SZS output end CNFRefutation for /tmp/SPASST_24186_n011.cluster.edu
% 0.80/1.08  
% 0.80/1.08  Formulae used in the proof : fof_heap_type fof_ax_25 fof_ax_20 fof_ax_30
% 0.80/1.10  
% 0.80/1.10  SPASS+T ended
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