TSTP Solution File: DAT053_1 by SPASS+T---2.2.22

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SPASS+T---2.2.22
% Problem  : DAT053_1 : TPTP v8.1.0. Released v5.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : spasst-tptp-script %s %d

% Computer : n005.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Sat Jul 16 01:31:59 EDT 2022

% Result   : Theorem 0.79s 1.08s
% Output   : Refutation 0.79s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.12  % Problem  : DAT053_1 : TPTP v8.1.0. Released v5.0.0.
% 0.11/0.13  % Command  : spasst-tptp-script %s %d
% 0.13/0.34  % Computer : n005.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % WCLimit  : 600
% 0.13/0.34  % DateTime : Fri Jul  1 17:47:22 EDT 2022
% 0.13/0.34  % CPUTime  : 
% 0.19/0.47  % Using integer theory
% 0.79/1.08  
% 0.79/1.08  
% 0.79/1.08  % SZS status Theorem for /tmp/SPASST_21646_n005.cluster.edu
% 0.79/1.08  
% 0.79/1.08  SPASS V 2.2.22  in combination with yices.
% 0.79/1.08  SPASS beiseite: Proof found by SPASS and SMT.
% 0.79/1.08  Problem: /tmp/SPASST_21646_n005.cluster.edu 
% 0.79/1.08  SPASS derived 221 clauses, backtracked 9 clauses and kept 146 clauses.
% 0.79/1.08  SPASS backtracked 2 times (1 times due to theory inconsistency).
% 0.79/1.08  SPASS allocated 6486 KBytes.
% 0.79/1.08  SPASS spent	0:00:00.03 on the problem.
% 0.79/1.08  		0:00:00.00 for the input.
% 0.79/1.08  		0:00:00.00 for the FLOTTER CNF translation.
% 0.79/1.08  		0:00:00.00 for inferences.
% 0.79/1.08  		0:00:00.00 for the backtracking.
% 0.79/1.08  		0:00:00.01 for the reduction.
% 0.79/1.08  		0:00:00.00 for interacting with the SMT procedure.
% 0.79/1.08  		
% 0.79/1.08  
% 0.79/1.08  % SZS output start CNFRefutation for /tmp/SPASST_21646_n005.cluster.edu
% 0.79/1.08  
% 0.79/1.08  % Here is a proof with depth 0, length 15 :
% 0.79/1.08  3[0:Inp] ||  -> record(b)*.
% 0.79/1.08  4[0:Inp] ||  -> record(a)*.
% 0.79/1.08  6[0:Inp] ||  -> isrecord(b)*.
% 0.79/1.08  7[0:Inp] ||  -> isrecord(next(b))*.
% 0.79/1.08  8[0:Inp] ||  -> equal(next(next(b)),a)**.
% 0.79/1.08  10[0:Inp] || record(U) -> record(split1(U))*.
% 0.79/1.08  11[0:Inp] || record(U) -> record(next(U))*.
% 0.79/1.08  13[0:Inp] || record(U) isrecord(U) -> isrecord(split1(U))*.
% 0.79/1.08  15[0:Inp] || record(U) -> isrecord(U) equal(length(U),0)**.
% 0.79/1.08  16[0:Inp] || equal(times(2,length(split1(b))),length(b))** -> .
% 0.79/1.08  19[0:Inp] || equal(times(2,length(split1(b))),plus(length(b),1))** -> .
% 0.79/1.08  23[0:Inp] || record(U) isrecord(U) -> equal(plus(length(next(U)),1),length(U))**.
% 0.79/1.08  26(e)[0:Inp] || record(U) isrecord(U) isrecord(next(U)) -> equal(split1(next(next(U))),next(split1(U)))**.
% 0.79/1.08  27(e)[0:Inp] ||  -> equal(times(2,length(split1(a))),length(a)) equal(times(2,length(split1(a))),plus(length(a),1))**.
% 0.79/1.08  436(e)[0:ThR:27,26,23,19,16,15,13,11,10,8,7,6,4,3] ||  -> .
% 0.79/1.08  
% 0.79/1.08  % SZS output end CNFRefutation for /tmp/SPASST_21646_n005.cluster.edu
% 0.79/1.08  
% 0.79/1.08  Formulae used in the proof : fof_length_type fof_b_type fof_record_type fof_co1 fof_split2_type fof_split1_type fof_ax9 fof_ax4 fof_ax1 fof_ax2 fof_ax7 fof_ax13 fof_ax8
% 0.79/1.08  
% 0.79/1.08  SPASS+T ended
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