TSTP Solution File: DAT030_1 by SPASS+T---2.2.22
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% File : SPASS+T---2.2.22
% Problem : DAT030_1 : TPTP v8.1.0. Released v5.0.0.
% Transfm : none
% Format : tptp:raw
% Command : spasst-tptp-script %s %d
% Computer : n007.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Sat Jul 16 01:31:51 EDT 2022
% Result : Theorem 0.76s 1.05s
% Output : Refutation 0.76s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12 % Problem : DAT030_1 : TPTP v8.1.0. Released v5.0.0.
% 0.03/0.13 % Command : spasst-tptp-script %s %d
% 0.12/0.34 % Computer : n007.cluster.edu
% 0.12/0.34 % Model : x86_64 x86_64
% 0.12/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34 % Memory : 8042.1875MB
% 0.12/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34 % CPULimit : 300
% 0.12/0.34 % WCLimit : 600
% 0.12/0.34 % DateTime : Fri Jul 1 18:01:09 EDT 2022
% 0.12/0.34 % CPUTime :
% 0.19/0.47 % Using integer theory
% 0.76/1.05
% 0.76/1.05
% 0.76/1.05 % SZS status Theorem for /tmp/SPASST_30110_n007.cluster.edu
% 0.76/1.05
% 0.76/1.05 SPASS V 2.2.22 in combination with yices.
% 0.76/1.05 SPASS beiseite: Proof found by SPASS and SMT.
% 0.76/1.05 Problem: /tmp/SPASST_30110_n007.cluster.edu
% 0.76/1.05 SPASS derived 191 clauses, backtracked 4 clauses and kept 179 clauses.
% 0.76/1.05 SPASS backtracked 3 times (1 times due to theory inconsistency).
% 0.76/1.05 SPASS allocated 6436 KBytes.
% 0.76/1.05 SPASS spent 0:00:00.03 on the problem.
% 0.76/1.05 0:00:00.00 for the input.
% 0.76/1.05 0:00:00.01 for the FLOTTER CNF translation.
% 0.76/1.05 0:00:00.00 for inferences.
% 0.76/1.05 0:00:00.00 for the backtracking.
% 0.76/1.05 0:00:00.01 for the reduction.
% 0.76/1.05 0:00:00.00 for interacting with the SMT procedure.
% 0.76/1.05
% 0.76/1.05
% 0.76/1.05 % SZS output start CNFRefutation for /tmp/SPASST_30110_n007.cluster.edu
% 0.76/1.05
% 0.76/1.05 % Here is a proof with depth 0, length 7 :
% 0.76/1.05 5[0:Inp] || -> in(skc8,skc5)*.
% 0.76/1.05 7[0:Inp] || greater(skc8,1)* -> .
% 0.76/1.05 10[0:Inp] || in(U,skc4)* -> greater(U,0).
% 0.76/1.05 12[0:Inp] || in(U,skc5)* -> in(skf2(V),skc4)*.
% 0.76/1.05 13[0:Inp] || in(U,skc5)* -> in(skf3(V),skc4)*.
% 0.76/1.05 15[0:Inp] || in(U,skc5) -> equal(plus(skf3(U),skf2(U)),U)**.
% 0.76/1.05 327(e)[0:ThR:15,13,12,10,7,5] || -> .
% 0.76/1.05
% 0.76/1.05 % SZS output end CNFRefutation for /tmp/SPASST_30110_n007.cluster.edu
% 0.76/1.05
% 0.76/1.05 Formulae used in the proof : fof_co1 fof_ax1 fof_add_type fof_ax2 fof_ax3
% 0.76/1.05
% 0.76/1.05 SPASS+T ended
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