TSTP Solution File: DAT011_1 by SPASS+T---2.2.22
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% File : SPASS+T---2.2.22
% Problem : DAT011_1 : TPTP v8.1.0. Released v5.0.0.
% Transfm : none
% Format : tptp:raw
% Command : spasst-tptp-script %s %d
% Computer : n014.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Sat Jul 16 01:31:45 EDT 2022
% Result : Theorem 0.70s 1.02s
% Output : Refutation 0.70s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12 % Problem : DAT011_1 : TPTP v8.1.0. Released v5.0.0.
% 0.07/0.12 % Command : spasst-tptp-script %s %d
% 0.12/0.33 % Computer : n014.cluster.edu
% 0.12/0.33 % Model : x86_64 x86_64
% 0.12/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33 % Memory : 8042.1875MB
% 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33 % CPULimit : 300
% 0.12/0.33 % WCLimit : 600
% 0.12/0.33 % DateTime : Fri Jul 1 18:25:40 EDT 2022
% 0.12/0.33 % CPUTime :
% 0.18/0.46 % Using integer theory
% 0.70/1.02
% 0.70/1.02
% 0.70/1.02 % SZS status Theorem for /tmp/SPASST_7691_n014.cluster.edu
% 0.70/1.02
% 0.70/1.02 SPASS V 2.2.22 in combination with yices.
% 0.70/1.02 SPASS beiseite: Proof found by SPASS and SMT.
% 0.70/1.02 Problem: /tmp/SPASST_7691_n014.cluster.edu
% 0.70/1.02 SPASS derived 155 clauses, backtracked 7 clauses and kept 114 clauses.
% 0.70/1.02 SPASS backtracked 3 times (1 times due to theory inconsistency).
% 0.70/1.02 SPASS allocated 6359 KBytes.
% 0.70/1.02 SPASS spent 0:00:00.02 on the problem.
% 0.70/1.02 0:00:00.00 for the input.
% 0.70/1.02 0:00:00.00 for the FLOTTER CNF translation.
% 0.70/1.02 0:00:00.00 for inferences.
% 0.70/1.02 0:00:00.00 for the backtracking.
% 0.70/1.02 0:00:00.01 for the reduction.
% 0.70/1.02 0:00:00.00 for interacting with the SMT procedure.
% 0.70/1.02
% 0.70/1.02
% 0.70/1.02 % SZS output start CNFRefutation for /tmp/SPASST_7691_n014.cluster.edu
% 0.70/1.02
% 0.70/1.02 % Here is a proof with depth 0, length 8 :
% 0.70/1.02 3[0:Inp] || -> array(skc5)*.
% 0.70/1.02 4[0:Inp] || -> lesseq(skc7,skc8)*.
% 0.70/1.02 5[0:Inp] || -> lesseq(skc8,plus(skc6,1))*.
% 0.70/1.02 8[0:Inp] || array(U) -> equal(read(write(U,V,W),V),W)**.
% 0.70/1.02 9[0:Inp] || greater(read(write(skc5,plus(skc6,1),3),skc8),0)* -> .
% 0.70/1.02 10[0:Inp] || lesseq(U,skc6) lesseq(skc7,U) -> greater(read(skc5,U),0)*.
% 0.70/1.02 11[0:Inp] || array(U) -> equal(V,W) equal(read(write(U,V,X),W),read(U,W))**.
% 0.70/1.02 261(e)[0:ThR:11,10,9,8,5,4,3] || -> .
% 0.70/1.02
% 0.70/1.02 % SZS output end CNFRefutation for /tmp/SPASST_7691_n014.cluster.edu
% 0.70/1.02
% 0.70/1.02 Formulae used in the proof : fof_array_type fof_co1 fof_write_type fof_ax1
% 0.70/1.02
% 0.70/1.02 SPASS+T ended
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