TSTP Solution File: DAT009_1 by SPASS+T---2.2.22
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% File : SPASS+T---2.2.22
% Problem : DAT009_1 : TPTP v8.1.0. Released v5.0.0.
% Transfm : none
% Format : tptp:raw
% Command : spasst-tptp-script %s %d
% Computer : n010.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Sat Jul 16 01:31:44 EDT 2022
% Result : Theorem 0.43s 1.01s
% Output : Refutation 0.43s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.12 % Problem : DAT009_1 : TPTP v8.1.0. Released v5.0.0.
% 0.06/0.12 % Command : spasst-tptp-script %s %d
% 0.12/0.33 % Computer : n010.cluster.edu
% 0.12/0.33 % Model : x86_64 x86_64
% 0.12/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33 % Memory : 8042.1875MB
% 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33 % CPULimit : 300
% 0.12/0.33 % WCLimit : 600
% 0.12/0.33 % DateTime : Fri Jul 1 19:56:18 EDT 2022
% 0.12/0.33 % CPUTime :
% 0.18/0.46 % Using integer theory
% 0.43/1.01
% 0.43/1.01
% 0.43/1.01 % SZS status Theorem for /tmp/SPASST_18875_n010.cluster.edu
% 0.43/1.01
% 0.43/1.01 SPASS V 2.2.22 in combination with yices.
% 0.43/1.01 SPASS beiseite: Proof found by SPASS.
% 0.43/1.01 Problem: /tmp/SPASST_18875_n010.cluster.edu
% 0.43/1.01 SPASS derived 26 clauses, backtracked 3 clauses and kept 58 clauses.
% 0.43/1.01 SPASS backtracked 2 times (0 times due to theory inconsistency).
% 0.43/1.01 SPASS allocated 6252 KBytes.
% 0.43/1.01 SPASS spent 0:00:00.01 on the problem.
% 0.43/1.01 0:00:00.00 for the input.
% 0.43/1.01 0:00:00.00 for the FLOTTER CNF translation.
% 0.43/1.01 0:00:00.00 for inferences.
% 0.43/1.01 0:00:00.00 for the backtracking.
% 0.43/1.01 0:00:00.00 for the reduction.
% 0.43/1.01 0:00:00.00 for interacting with the SMT procedure.
% 0.43/1.01
% 0.43/1.01
% 0.43/1.01 % SZS output start CNFRefutation for /tmp/SPASST_18875_n010.cluster.edu
% 0.43/1.01
% 0.43/1.01 % Here is a proof with depth 3, length 22 :
% 0.43/1.01 3[0:Inp] || -> array(skc4)*.
% 0.43/1.01 4[0:Inp] || -> greater(read(skc4,U),U)*.
% 0.43/1.01 7[0:Inp] || array(U) -> equal(read(write(U,V,W),V),W)**.
% 0.43/1.01 8[0:Inp] || greater(read(write(skc4,skc5,plus(skc5,3)),skc6),skc6)* -> .
% 0.43/1.01 9[0:Inp] || array(U) -> equal(V,W) equal(read(write(U,V,X),W),read(U,W))**.
% 0.43/1.01 20[0:ThA] || -> less(U,plus(U,1))*.
% 0.43/1.01 24[0:ThA] || -> lesseq(U,V) less(plus(W,V),plus(W,U))*.
% 0.43/1.01 41[0:ArS:4.0] || -> less(U,read(skc4,U))*.
% 0.43/1.01 42[0:ArS:8.0] || less(skc6,read(write(skc4,skc5,plus(skc5,3)),skc6))* -> .
% 0.43/1.01 43(e)[0:TOC:42.0] || -> lesseq(read(write(skc4,skc5,plus(skc5,3)),skc6),skc6)*.
% 0.43/1.01 45[0:Res:3.0,7.0] || -> equal(read(write(skc4,U,V),U),V)**.
% 0.43/1.01 56[0:SpR:9.2,43.0] || array(skc4) -> equal(skc6,skc5) lesseq(read(skc4,skc6),skc6)*.
% 0.43/1.01 60(e)[0:MRR:56.0,3.0] || -> equal(skc6,skc5) lesseq(read(skc4,skc6),skc6)*.
% 0.43/1.01 63[1:Spt:60.0] || -> equal(skc6,skc5)**.
% 0.43/1.01 64[1:Rew:63.0,43.0] || -> lesseq(read(write(skc4,skc5,plus(skc5,3)),skc5),skc5)*.
% 0.43/1.01 65[1:Rew:45.0,64.0] || -> lesseq(plus(skc5,3),skc5)*.
% 0.43/1.01 67[1:OCh:65.0,24.1] || -> lesseq(3,U) less(plus(skc5,U),skc5)*.
% 0.43/1.01 72[1:OCE:67.1,20.0] || -> lesseq(3,1)*.
% 0.43/1.01 76(e)[1:ArS:72.0] || -> .
% 0.43/1.01 80(e)[1:Spt:76.0,60.0,63.0] || equal(skc6,skc5)** -> .
% 0.43/1.01 81[1:Spt:76.0,60.1] || -> lesseq(read(skc4,skc6),skc6)*.
% 0.43/1.01 82(e)[1:OCE:81.0,41.0] || -> .
% 0.43/1.01
% 0.43/1.01 % SZS output end CNFRefutation for /tmp/SPASST_18875_n010.cluster.edu
% 0.43/1.01
% 0.43/1.01 Formulae used in the proof : fof_array_type fof_co1 fof_write_type fof_ax1
% 0.43/1.03
% 0.43/1.03 SPASS+T ended
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