TSTP Solution File: CSR142^1 by Duper---1.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : CSR142^1 : TPTP v8.1.2. Released v4.1.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n008.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Aug 30 21:12:04 EDT 2023

% Result   : Theorem 3.87s 4.13s
% Output   : Proof 3.87s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem    : CSR142^1 : TPTP v8.1.2. Released v4.1.0.
% 0.00/0.13  % Command    : duper %s
% 0.13/0.34  % Computer : n008.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit   : 300
% 0.13/0.34  % WCLimit    : 300
% 0.13/0.34  % DateTime   : Mon Aug 28 13:18:47 EDT 2023
% 0.13/0.34  % CPUTime    : 
% 3.87/4.13  SZS status Theorem for theBenchmark.p
% 3.87/4.13  SZS output start Proof for theBenchmark.p
% 3.87/4.13  Clause #0 (by assumption #[]): Eq (inverse_THFTYPE_IIiioIIiioIoI husband_THFTYPE_IiioI wife_THFTYPE_IiioI) True
% 3.87/4.13  Clause #1 (by assumption #[]): Eq
% 3.87/4.13    (∀ (REL2 REL1 : Iota → Iota → Prop),
% 3.87/4.13      inverse_THFTYPE_IIiioIIiioIoI REL1 REL2 → ∀ (INST1 INST2 : Iota), Iff (REL1 INST1 INST2) (REL2 INST2 INST1))
% 3.87/4.13    True
% 3.87/4.13  Clause #2 (by assumption #[]): Eq (wife_THFTYPE_IiioI lCorina_THFTYPE_i lChris_THFTYPE_i) True
% 3.87/4.13  Clause #3 (by assumption #[]): Eq (Not (Exists fun X => husband_THFTYPE_IiioI X lCorina_THFTYPE_i)) True
% 3.87/4.13  Clause #4 (by clausification #[3]): Eq (Exists fun X => husband_THFTYPE_IiioI X lCorina_THFTYPE_i) False
% 3.87/4.13  Clause #5 (by clausification #[4]): ∀ (a : Iota), Eq (husband_THFTYPE_IiioI a lCorina_THFTYPE_i) False
% 3.87/4.13  Clause #6 (by clausification #[1]): ∀ (a : Iota → Iota → Prop),
% 3.87/4.13    Eq
% 3.87/4.13      (∀ (REL1 : Iota → Iota → Prop),
% 3.87/4.13        inverse_THFTYPE_IIiioIIiioIoI REL1 a → ∀ (INST1 INST2 : Iota), Iff (REL1 INST1 INST2) (a INST2 INST1))
% 3.87/4.13      True
% 3.87/4.13  Clause #7 (by clausification #[6]): ∀ (a a_1 : Iota → Iota → Prop),
% 3.87/4.13    Eq (inverse_THFTYPE_IIiioIIiioIoI a a_1 → ∀ (INST1 INST2 : Iota), Iff (a INST1 INST2) (a_1 INST2 INST1)) True
% 3.87/4.13  Clause #8 (by clausification #[7]): ∀ (a a_1 : Iota → Iota → Prop),
% 3.87/4.13    Or (Eq (inverse_THFTYPE_IIiioIIiioIoI a a_1) False)
% 3.87/4.13      (Eq (∀ (INST1 INST2 : Iota), Iff (a INST1 INST2) (a_1 INST2 INST1)) True)
% 3.87/4.13  Clause #9 (by clausification #[8]): ∀ (a a_1 : Iota → Iota → Prop) (a_2 : Iota),
% 3.87/4.13    Or (Eq (inverse_THFTYPE_IIiioIIiioIoI a a_1) False) (Eq (∀ (INST2 : Iota), Iff (a a_2 INST2) (a_1 INST2 a_2)) True)
% 3.87/4.13  Clause #10 (by clausification #[9]): ∀ (a a_1 : Iota → Iota → Prop) (a_2 a_3 : Iota),
% 3.87/4.13    Or (Eq (inverse_THFTYPE_IIiioIIiioIoI a a_1) False) (Eq (Iff (a a_2 a_3) (a_1 a_3 a_2)) True)
% 3.87/4.13  Clause #11 (by clausification #[10]): ∀ (a a_1 : Iota → Iota → Prop) (a_2 a_3 : Iota),
% 3.87/4.13    Or (Eq (inverse_THFTYPE_IIiioIIiioIoI a a_1) False) (Or (Eq (a a_2 a_3) True) (Eq (a_1 a_3 a_2) False))
% 3.87/4.13  Clause #13 (by superposition #[11, 0]): ∀ (a a_1 : Iota),
% 3.87/4.13    Or (Eq ((fun x x_1 => husband_THFTYPE_IiioI x x_1) a a_1) True)
% 3.87/4.13      (Or (Eq ((fun x x_1 => wife_THFTYPE_IiioI x x_1) a_1 a) False) (Eq False True))
% 3.87/4.13  Clause #15 (by betaEtaReduce #[13]): ∀ (a a_1 : Iota), Or (Eq (husband_THFTYPE_IiioI a a_1) True) (Or (Eq (wife_THFTYPE_IiioI a_1 a) False) (Eq False True))
% 3.87/4.13  Clause #16 (by clausification #[15]): ∀ (a a_1 : Iota), Or (Eq (husband_THFTYPE_IiioI a a_1) True) (Eq (wife_THFTYPE_IiioI a_1 a) False)
% 3.87/4.13  Clause #17 (by superposition #[16, 2]): Or (Eq (husband_THFTYPE_IiioI lChris_THFTYPE_i lCorina_THFTYPE_i) True) (Eq False True)
% 3.87/4.13  Clause #18 (by clausification #[17]): Eq (husband_THFTYPE_IiioI lChris_THFTYPE_i lCorina_THFTYPE_i) True
% 3.87/4.13  Clause #19 (by superposition #[18, 5]): Eq True False
% 3.87/4.13  Clause #20 (by clausification #[19]): False
% 3.87/4.13  SZS output end Proof for theBenchmark.p
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