TSTP Solution File: CSR122^1 by Duper---1.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : CSR122^1 : TPTP v8.1.2. Released v4.1.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n024.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Aug 30 21:11:55 EDT 2023

% Result   : Theorem 3.52s 3.68s
% Output   : Proof 3.52s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12  % Problem    : CSR122^1 : TPTP v8.1.2. Released v4.1.0.
% 0.07/0.14  % Command    : duper %s
% 0.14/0.35  % Computer : n024.cluster.edu
% 0.14/0.35  % Model    : x86_64 x86_64
% 0.14/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.35  % Memory   : 8042.1875MB
% 0.14/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.35  % CPULimit   : 300
% 0.14/0.35  % WCLimit    : 300
% 0.14/0.35  % DateTime   : Mon Aug 28 07:02:08 EDT 2023
% 0.14/0.35  % CPUTime    : 
% 3.52/3.68  SZS status Theorem for theBenchmark.p
% 3.52/3.68  SZS output start Proof for theBenchmark.p
% 3.52/3.68  Clause #0 (by assumption #[]): Eq (likes_THFTYPE_IiioI lSue_THFTYPE_i lBill_THFTYPE_i) True
% 3.52/3.68  Clause #1 (by assumption #[]): Eq (likes_THFTYPE_IiioI lMary_THFTYPE_i lBill_THFTYPE_i) True
% 3.52/3.68  Clause #2 (by assumption #[]): Eq (∀ (X : Iota), holdsDuring_THFTYPE_IiooI X True) True
% 3.52/3.68  Clause #3 (by assumption #[]): Eq
% 3.52/3.68    (Not
% 3.52/3.68      (holdsDuring_THFTYPE_IiooI (lYearFn_THFTYPE_IiiI n2009_THFTYPE_i)
% 3.52/3.68        (And (likes_THFTYPE_IiioI lMary_THFTYPE_i lBill_THFTYPE_i) (likes_THFTYPE_IiioI lSue_THFTYPE_i lBill_THFTYPE_i))))
% 3.52/3.68    True
% 3.52/3.68  Clause #4 (by clausification #[2]): ∀ (a : Iota), Eq (holdsDuring_THFTYPE_IiooI a True) True
% 3.52/3.68  Clause #5 (by clausification #[3]): Eq
% 3.52/3.68    (holdsDuring_THFTYPE_IiooI (lYearFn_THFTYPE_IiiI n2009_THFTYPE_i)
% 3.52/3.68      (And (likes_THFTYPE_IiioI lMary_THFTYPE_i lBill_THFTYPE_i) (likes_THFTYPE_IiioI lSue_THFTYPE_i lBill_THFTYPE_i)))
% 3.52/3.68    False
% 3.52/3.68  Clause #6 (by forward demodulation #[5, 0]): Eq
% 3.52/3.68    (holdsDuring_THFTYPE_IiooI (lYearFn_THFTYPE_IiiI n2009_THFTYPE_i)
% 3.52/3.68      (And (likes_THFTYPE_IiioI lMary_THFTYPE_i lBill_THFTYPE_i) True))
% 3.52/3.68    False
% 3.52/3.68  Clause #7 (by bool simp #[6]): Eq
% 3.52/3.68    (holdsDuring_THFTYPE_IiooI (lYearFn_THFTYPE_IiiI n2009_THFTYPE_i)
% 3.52/3.68      (likes_THFTYPE_IiioI lMary_THFTYPE_i lBill_THFTYPE_i))
% 3.52/3.68    False
% 3.52/3.68  Clause #8 (by forward demodulation #[7, 1]): Eq (holdsDuring_THFTYPE_IiooI (lYearFn_THFTYPE_IiiI n2009_THFTYPE_i) True) False
% 3.52/3.68  Clause #9 (by superposition #[8, 4]): Eq False True
% 3.52/3.68  Clause #10 (by clausification #[9]): False
% 3.52/3.68  SZS output end Proof for theBenchmark.p
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