TSTP Solution File: CSR103+1 by Etableau---0.67
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%------------------------------------------------------------------------------
% File : Etableau---0.67
% Problem : CSR103+1 : TPTP v8.1.0. Bugfixed v7.3.0.
% Transfm : none
% Format : tptp:raw
% Command : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s
% Computer : n018.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Fri Jul 15 03:17:34 EDT 2022
% Result : Theorem 0.78s 0.93s
% Output : CNFRefutation 0.78s
% Verified :
% SZS Type : Refutation
% Derivation depth : 4
% Number of leaves : 2
% Syntax : Number of formulae : 8 ( 8 unt; 0 def)
% Number of atoms : 8 ( 0 equ)
% Maximal formula atoms : 1 ( 1 avg)
% Number of connectives : 3 ( 3 ~; 0 |; 0 &)
% ( 0 <=>; 0 =>; 0 <=; 0 <~>)
% Maximal formula depth : 3 ( 2 avg)
% Maximal term depth : 1 ( 1 avg)
% Number of predicates : 2 ( 1 usr; 1 prp; 0-2 aty)
% Number of functors : 2 ( 2 usr; 2 con; 0-0 aty)
% Number of variables : 5 ( 1 sgn 4 !; 0 ?)
% Comments :
%------------------------------------------------------------------------------
fof(prove_from_SUMO,conjecture,
! [X591] : s__instance(X591,s__Entity),
file('/export/starexec/sandbox/benchmark/theBenchmark.p',prove_from_SUMO) ).
fof(kb_SUMO_502,axiom,
! [X26] : s__instance(X26,s__Entity),
file('/export/starexec/sandbox/benchmark/Axioms/CSR003+0.ax',kb_SUMO_502) ).
fof(c_0_2,negated_conjecture,
~ ! [X591] : s__instance(X591,s__Entity),
inference(assume_negation,[status(cth)],[prove_from_SUMO]) ).
fof(c_0_3,negated_conjecture,
~ s__instance(esk1_0,s__Entity),
inference(skolemize,[status(esa)],[inference(variable_rename,[status(thm)],[inference(fof_nnf,[status(thm)],[c_0_2])])]) ).
fof(c_0_4,plain,
! [X593] : s__instance(X593,s__Entity),
inference(variable_rename,[status(thm)],[kb_SUMO_502]) ).
cnf(c_0_5,negated_conjecture,
~ s__instance(esk1_0,s__Entity),
inference(split_conjunct,[status(thm)],[c_0_3]) ).
cnf(c_0_6,plain,
s__instance(X1,s__Entity),
inference(split_conjunct,[status(thm)],[c_0_4]) ).
cnf(c_0_7,negated_conjecture,
$false,
inference(cn,[status(thm)],[inference(rw,[status(thm)],[c_0_5,c_0_6])]),
[proof] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12 % Problem : CSR103+1 : TPTP v8.1.0. Bugfixed v7.3.0.
% 0.03/0.12 % Command : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s
% 0.12/0.33 % Computer : n018.cluster.edu
% 0.12/0.33 % Model : x86_64 x86_64
% 0.12/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33 % Memory : 8042.1875MB
% 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33 % CPULimit : 300
% 0.12/0.33 % WCLimit : 600
% 0.12/0.33 % DateTime : Sat Jun 11 14:46:10 EDT 2022
% 0.12/0.33 % CPUTime :
% 0.78/0.93 # SinE strategy is gf200_h_gu_RUU_F100_L20000
% 0.78/0.93 # Auto-Mode selected heuristic C07_19_nc_SAT001_MinMin_rr
% 0.78/0.93 # and selection function SelectMaxLComplexAvoidPosPred.
% 0.78/0.93 #
% 0.78/0.93 # Presaturation interreduction done
% 0.78/0.93
% 0.78/0.93 # Proof found!
% 0.78/0.93 # SZS status Theorem
% 0.78/0.93 # SZS output start CNFRefutation
% See solution above
% 0.78/0.93 # Training examples: 0 positive, 0 negative
%------------------------------------------------------------------------------