TSTP Solution File: COM149+1 by SPASS---3.9
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%------------------------------------------------------------------------------
% File : SPASS---3.9
% Problem : COM149+1 : TPTP v8.1.0. Released v6.4.0.
% Transfm : none
% Format : tptp
% Command : run_spass %d %s
% Computer : n032.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Fri Jul 15 01:44:46 EDT 2022
% Result : Theorem 3.25s 3.48s
% Output : Refutation 3.25s
% Verified :
% SZS Type : Refutation
% Derivation depth : 5
% Number of leaves : 8
% Syntax : Number of clauses : 16 ( 8 unt; 2 nHn; 16 RR)
% Number of literals : 29 ( 0 equ; 16 neg)
% Maximal clause size : 4 ( 1 avg)
% Maximal term depth : 3 ( 1 avg)
% Number of predicates : 5 ( 4 usr; 1 prp; 0-3 aty)
% Number of functors : 19 ( 19 usr; 8 con; 0-3 aty)
% Number of variables : 0 ( 0 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(12,axiom,
vtcheck(vempty,vvar(skc2),skc3),
file('COM149+1.p',unknown),
[] ).
cnf(15,axiom,
~ equal(vsomeType(u),vnoType),
file('COM149+1.p',unknown),
[] ).
cnf(17,axiom,
equal(vlookup(u,vempty),vnoType),
file('COM149+1.p',unknown),
[] ).
cnf(23,axiom,
~ equal(vvar(u),vapp(v,w)),
file('COM149+1.p',unknown),
[] ).
cnf(34,axiom,
~ equal(vvar(u),vabs(v,w,x)),
file('COM149+1.p',unknown),
[] ).
cnf(87,axiom,
( ~ skP13(u,v,w)
| equal(vlookup(skf101(w,u,v),v),vsomeType(u)) ),
file('COM149+1.p',unknown),
[] ).
cnf(111,axiom,
( ~ skP14(u,v,w)
| equal(vabs(skf104(w,u,v),skf103(v,u,w),skf105(w,u,v)),w) ),
file('COM149+1.p',unknown),
[] ).
cnf(119,axiom,
( ~ vtcheck(u,v,w)
| equal(vapp(skf100(v,w,u),skf98(w,u,v)),v)
| skP14(u,w,v)
| skP13(w,u,v) ),
file('COM149+1.p',unknown),
[] ).
cnf(960,plain,
( ~ skP13(u,vempty,v)
| equal(vsomeType(u),vnoType) ),
inference(spr,[status(thm),theory(equality)],[87,17]),
[iquote('0:SpR:87.1,17.0')] ).
cnf(967,plain,
~ skP13(u,vempty,v),
inference(mrr,[status(thm)],[960,15]),
[iquote('0:MRR:960.1,15.0')] ).
cnf(2594,plain,
( ~ skP14(u,v,w)
| ~ equal(vvar(x),w) ),
inference(spl,[status(thm),theory(equality)],[111,34]),
[iquote('0:SpL:111.1,34.0')] ).
cnf(3144,plain,
( ~ vtcheck(u,v,w)
| ~ equal(vvar(x),v)
| skP14(u,w,v)
| skP13(w,u,v) ),
inference(spl,[status(thm),theory(equality)],[119,23]),
[iquote('0:SpL:119.1,23.0')] ).
cnf(3185,plain,
( ~ vtcheck(u,v,w)
| ~ equal(vvar(x),v)
| skP13(w,u,v) ),
inference(mrr,[status(thm)],[3144,2594]),
[iquote('0:MRR:3144.2,2594.0')] ).
cnf(8968,plain,
( ~ equal(vvar(u),vvar(skc2))
| skP13(skc3,vempty,vvar(skc2)) ),
inference(res,[status(thm),theory(equality)],[12,3185]),
[iquote('0:Res:12.0,3185.0')] ).
cnf(8982,plain,
~ equal(vvar(u),vvar(skc2)),
inference(mrr,[status(thm)],[8968,967]),
[iquote('0:MRR:8968.1,967.0')] ).
cnf(8985,plain,
$false,
inference(eqr,[status(thm),theory(equality)],[8982]),
[iquote('0:EqR:8982.0')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.08 % Problem : COM149+1 : TPTP v8.1.0. Released v6.4.0.
% 0.06/0.08 % Command : run_spass %d %s
% 0.08/0.27 % Computer : n032.cluster.edu
% 0.08/0.27 % Model : x86_64 x86_64
% 0.08/0.27 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.08/0.27 % Memory : 8042.1875MB
% 0.08/0.27 % OS : Linux 3.10.0-693.el7.x86_64
% 0.08/0.27 % CPULimit : 300
% 0.08/0.27 % WCLimit : 600
% 0.08/0.27 % DateTime : Thu Jun 16 20:07:30 EDT 2022
% 0.08/0.27 % CPUTime :
% 3.25/3.48
% 3.25/3.48 SPASS V 3.9
% 3.25/3.48 SPASS beiseite: Proof found.
% 3.25/3.48 % SZS status Theorem
% 3.25/3.48 Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p
% 3.25/3.48 SPASS derived 7305 clauses, backtracked 0 clauses, performed 1 splits and kept 3336 clauses.
% 3.25/3.48 SPASS allocated 107730 KBytes.
% 3.25/3.48 SPASS spent 0:00:03.11 on the problem.
% 3.25/3.48 0:00:00.03 for the input.
% 3.25/3.48 0:00:00.25 for the FLOTTER CNF translation.
% 3.25/3.48 0:00:00.12 for inferences.
% 3.25/3.48 0:00:00.00 for the backtracking.
% 3.25/3.48 0:00:02.64 for the reduction.
% 3.25/3.48
% 3.25/3.48
% 3.25/3.48 Here is a proof with depth 3, length 16 :
% 3.25/3.48 % SZS output start Refutation
% See solution above
% 3.25/3.48 Formulae used in the proof : T_a45_Progress_a45_T_a45_var DIFF_a45_noType_a45_someType lookup0 DIFF_a45_var_a45_app DIFF_a45_var_a45_abs T_a45_inv lookup1 T_a45_var T_a45_abs
% 3.25/3.48
%------------------------------------------------------------------------------