TSTP Solution File: COM043_5 by Duper---1.0
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% File : Duper---1.0
% Problem : COM043_5 : TPTP v8.1.2. Released v6.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n018.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Wed Aug 30 18:38:13 EDT 2023
% Result : Theorem 4.30s 4.50s
% Output : Proof 4.30s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : COM043_5 : TPTP v8.1.2. Released v6.0.0.
% 0.00/0.14 % Command : duper %s
% 0.13/0.35 % Computer : n018.cluster.edu
% 0.13/0.35 % Model : x86_64 x86_64
% 0.13/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35 % Memory : 8042.1875MB
% 0.13/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35 % CPULimit : 300
% 0.13/0.35 % WCLimit : 300
% 0.13/0.35 % DateTime : Tue Aug 29 13:34:33 EDT 2023
% 0.13/0.35 % CPUTime :
% 4.30/4.50 SZS status Theorem for theBenchmark.p
% 4.30/4.50 SZS output start Proof for theBenchmark.p
% 4.30/4.50 Clause #0 (by assumption #[]): Eq (Eq a (nDvd d l ks)) True
% 4.30/4.50 Clause #1 (by assumption #[]): Eq (Eq (div_mod int i (divisor a)) (div_mod int j (divisor a))) True
% 4.30/4.50 Clause #63 (by assumption #[]): Eq (∀ (Ks1 : list int) (I D : int), Eq (divisor (nDvd D I Ks1)) D) True
% 4.30/4.50 Clause #134 (by assumption #[]): Eq (Not (Eq (div_mod int i d) (div_mod int j d))) True
% 4.30/4.50 Clause #135 (by clausification #[0]): Eq a (nDvd d l ks)
% 4.30/4.50 Clause #136 (by clausification #[1]): Eq (div_mod int i (divisor a)) (div_mod int j (divisor a))
% 4.30/4.50 Clause #286 (by clausification #[134]): Eq (Eq (div_mod int i d) (div_mod int j d)) False
% 4.30/4.50 Clause #287 (by clausification #[286]): Ne (div_mod int i d) (div_mod int j d)
% 4.30/4.50 Clause #491 (by clausification #[63]): ∀ (a : list int), Eq (∀ (I D : int), Eq (divisor (nDvd D I a)) D) True
% 4.30/4.50 Clause #492 (by clausification #[491]): ∀ (a : int) (a_1 : list int), Eq (∀ (D : int), Eq (divisor (nDvd D a a_1)) D) True
% 4.30/4.50 Clause #493 (by clausification #[492]): ∀ (a a_1 : int) (a_2 : list int), Eq (Eq (divisor (nDvd a a_1 a_2)) a) True
% 4.30/4.50 Clause #494 (by clausification #[493]): ∀ (a a_1 : int) (a_2 : list int), Eq (divisor (nDvd a a_1 a_2)) a
% 4.30/4.50 Clause #495 (by superposition #[494, 135]): Eq (divisor a) d
% 4.30/4.50 Clause #496 (by backward demodulation #[495, 136]): Eq (div_mod int i d) (div_mod int j (divisor a))
% 4.30/4.50 Clause #510 (by forward demodulation #[496, 495]): Eq (div_mod int i d) (div_mod int j d)
% 4.30/4.50 Clause #511 (by forward contextual literal cutting #[510, 287]): False
% 4.30/4.50 SZS output end Proof for theBenchmark.p
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