TSTP Solution File: COL070-1 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : COL070-1 : TPTP v8.1.0. Released v1.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n025.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 12:48:10 EDT 2022

% Result   : Unsatisfiable 1.78s 2.02s
% Output   : Refutation 1.78s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    4
%            Number of leaves      :    3
% Syntax   : Number of clauses     :    8 (   8 unt;   0 nHn;   3 RR)
%            Number of literals    :    8 (   7 equ;   2 neg)
%            Maximal clause size   :    1 (   1 avg)
%            Maximal term depth    :    6 (   2 avg)
%            Number of predicates  :    2 (   0 usr;   1 prp; 0-2 aty)
%            Number of functors    :    4 (   4 usr;   3 con; 0-2 aty)
%            Number of variables   :   17 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    A != apply(combinator,A),
    file('COL070-1.p',unknown),
    [] ).

cnf(2,plain,
    apply(combinator,A) != A,
    inference(flip,[status(thm),theory(equality)],[inference(copy,[status(thm)],[1])]),
    [iquote('copy,1,flip.1')] ).

cnf(4,axiom,
    apply(apply(apply(n1,A),B),C) = apply(apply(apply(A,B),B),C),
    file('COL070-1.p',unknown),
    [] ).

cnf(5,axiom,
    apply(apply(apply(b,A),B),C) = apply(A,apply(B,C)),
    file('COL070-1.p',unknown),
    [] ).

cnf(7,plain,
    apply(apply(apply(A,B),B),C) = apply(apply(apply(n1,A),B),C),
    inference(flip,[status(thm),theory(equality)],[inference(copy,[status(thm)],[4])]),
    [iquote('copy,4,flip.1')] ).

cnf(15,plain,
    apply(apply(A,apply(B,B)),C) = apply(apply(apply(n1,apply(b,A)),B),C),
    inference(para_into,[status(thm),theory(equality)],[7,5]),
    [iquote('para_into,7.1.1.1,5.1.1')] ).

cnf(96,plain,
    apply(A,apply(apply(B,B),C)) = apply(apply(apply(n1,apply(b,apply(b,A))),B),C),
    inference(para_into,[status(thm),theory(equality)],[15,5]),
    [iquote('para_into,15.1.1,5.1.1')] ).

cnf(97,plain,
    $false,
    inference(binary,[status(thm)],[96,2]),
    [iquote('binary,96.1,2.1')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.09/0.11  % Problem  : COL070-1 : TPTP v8.1.0. Released v1.2.0.
% 0.09/0.12  % Command  : otter-tptp-script %s
% 0.12/0.33  % Computer : n025.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 300
% 0.12/0.33  % DateTime : Wed Jul 27 02:34:00 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 1.78/2.02  ----- Otter 3.3f, August 2004 -----
% 1.78/2.02  The process was started by sandbox on n025.cluster.edu,
% 1.78/2.02  Wed Jul 27 02:34:00 2022
% 1.78/2.02  The command was "./otter".  The process ID is 25048.
% 1.78/2.02  
% 1.78/2.02  set(prolog_style_variables).
% 1.78/2.02  set(auto).
% 1.78/2.02     dependent: set(auto1).
% 1.78/2.02     dependent: set(process_input).
% 1.78/2.02     dependent: clear(print_kept).
% 1.78/2.02     dependent: clear(print_new_demod).
% 1.78/2.02     dependent: clear(print_back_demod).
% 1.78/2.02     dependent: clear(print_back_sub).
% 1.78/2.02     dependent: set(control_memory).
% 1.78/2.02     dependent: assign(max_mem, 12000).
% 1.78/2.02     dependent: assign(pick_given_ratio, 4).
% 1.78/2.02     dependent: assign(stats_level, 1).
% 1.78/2.02     dependent: assign(max_seconds, 10800).
% 1.78/2.02  clear(print_given).
% 1.78/2.02  
% 1.78/2.02  list(usable).
% 1.78/2.02  0 [] A=A.
% 1.78/2.02  0 [] apply(apply(apply(n1,X),Y),Z)=apply(apply(apply(X,Y),Y),Z).
% 1.78/2.02  0 [] apply(apply(apply(b,X),Y),Z)=apply(X,apply(Y,Z)).
% 1.78/2.02  0 [] Y!=apply(combinator,Y).
% 1.78/2.02  end_of_list.
% 1.78/2.02  
% 1.78/2.02  SCAN INPUT: prop=0, horn=1, equality=1, symmetry=0, max_lits=1.
% 1.78/2.02  
% 1.78/2.02  All clauses are units, and equality is present; the
% 1.78/2.02  strategy will be Knuth-Bendix with positive clauses in sos.
% 1.78/2.02  
% 1.78/2.02     dependent: set(knuth_bendix).
% 1.78/2.02     dependent: set(anl_eq).
% 1.78/2.02     dependent: set(para_from).
% 1.78/2.02     dependent: set(para_into).
% 1.78/2.02     dependent: clear(para_from_right).
% 1.78/2.02     dependent: clear(para_into_right).
% 1.78/2.02     dependent: set(para_from_vars).
% 1.78/2.02     dependent: set(eq_units_both_ways).
% 1.78/2.02     dependent: set(dynamic_demod_all).
% 1.78/2.02     dependent: set(dynamic_demod).
% 1.78/2.02     dependent: set(order_eq).
% 1.78/2.02     dependent: set(back_demod).
% 1.78/2.02     dependent: set(lrpo).
% 1.78/2.02  
% 1.78/2.02  ------------> process usable:
% 1.78/2.02  ** KEPT (pick-wt=5): 2 [copy,1,flip.1] apply(combinator,A)!=A.
% 1.78/2.02  
% 1.78/2.02  ------------> process sos:
% 1.78/2.02  ** KEPT (pick-wt=3): 3 [] A=A.
% 1.78/2.02  ** KEPT (pick-wt=15): 4 [] apply(apply(apply(n1,A),B),C)=apply(apply(apply(A,B),B),C).
% 1.78/2.02  ** KEPT (pick-wt=13): 5 [] apply(apply(apply(b,A),B),C)=apply(A,apply(B,C)).
% 1.78/2.02  ---> New Demodulator: 6 [new_demod,5] apply(apply(apply(b,A),B),C)=apply(A,apply(B,C)).
% 1.78/2.02    Following clause subsumed by 3 during input processing: 0 [copy,3,flip.1] A=A.
% 1.78/2.02  ** KEPT (pick-wt=15): 7 [copy,4,flip.1] apply(apply(apply(A,B),B),C)=apply(apply(apply(n1,A),B),C).
% 1.78/2.02  >>>> Starting back demodulation with 6.
% 1.78/2.02    Following clause subsumed by 4 during input processing: 0 [copy,7,flip.1] apply(apply(apply(n1,A),B),C)=apply(apply(apply(A,B),B),C).
% 1.78/2.02  
% 1.78/2.02  ======= end of input processing =======
% 1.78/2.02  
% 1.78/2.02  =========== start of search ===========
% 1.78/2.02  
% 1.78/2.02  -------- PROOF -------- 
% 1.78/2.02  
% 1.78/2.02  ----> UNIT CONFLICT at   0.00 sec ----> 97 [binary,96.1,2.1] $F.
% 1.78/2.02  
% 1.78/2.02  Length of proof is 4.  Level of proof is 3.
% 1.78/2.02  
% 1.78/2.02  ---------------- PROOF ----------------
% 1.78/2.02  % SZS status Unsatisfiable
% 1.78/2.02  % SZS output start Refutation
% See solution above
% 1.78/2.02  ------------ end of proof -------------
% 1.78/2.02  
% 1.78/2.02  
% 1.78/2.02  Search stopped by max_proofs option.
% 1.78/2.02  
% 1.78/2.02  
% 1.78/2.02  Search stopped by max_proofs option.
% 1.78/2.02  
% 1.78/2.02  ============ end of search ============
% 1.78/2.02  
% 1.78/2.02  -------------- statistics -------------
% 1.78/2.02  clauses given                 10
% 1.78/2.02  clauses generated            108
% 1.78/2.02  clauses kept                  71
% 1.78/2.02  clauses forward subsumed      68
% 1.78/2.02  clauses back subsumed          2
% 1.78/2.02  Kbytes malloced             1953
% 1.78/2.02  
% 1.78/2.02  ----------- times (seconds) -----------
% 1.78/2.02  user CPU time          0.00          (0 hr, 0 min, 0 sec)
% 1.78/2.02  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.78/2.02  wall-clock time        2             (0 hr, 0 min, 2 sec)
% 1.78/2.02  
% 1.78/2.02  That finishes the proof of the theorem.
% 1.78/2.02  
% 1.78/2.02  Process 25048 finished Wed Jul 27 02:34:02 2022
% 1.78/2.02  Otter interrupted
% 1.78/2.02  PROOF FOUND
%------------------------------------------------------------------------------