TSTP Solution File: COL015-1 by Bliksem---1.12

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Bliksem---1.12
% Problem  : COL015-1 : TPTP v8.1.0. Released v1.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : bliksem %s

% Computer : n024.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 0s
% DateTime : Fri Jul 15 00:12:23 EDT 2022

% Result   : Unsatisfiable 0.69s 1.10s
% Output   : Refutation 0.69s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.12/0.12  % Problem  : COL015-1 : TPTP v8.1.0. Released v1.0.0.
% 0.12/0.13  % Command  : bliksem %s
% 0.12/0.34  % Computer : n024.cluster.edu
% 0.12/0.34  % Model    : x86_64 x86_64
% 0.12/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34  % Memory   : 8042.1875MB
% 0.12/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34  % CPULimit : 300
% 0.12/0.34  % DateTime : Tue May 31 04:12:06 EDT 2022
% 0.12/0.34  % CPUTime  : 
% 0.69/1.10  *** allocated 10000 integers for termspace/termends
% 0.69/1.10  *** allocated 10000 integers for clauses
% 0.69/1.10  *** allocated 10000 integers for justifications
% 0.69/1.10  Bliksem 1.12
% 0.69/1.10  
% 0.69/1.10  
% 0.69/1.10  Automatic Strategy Selection
% 0.69/1.10  
% 0.69/1.10  Clauses:
% 0.69/1.10  [
% 0.69/1.10     [ =( apply( m, X ), apply( X, X ) ) ],
% 0.69/1.10     [ =( apply( apply( apply( q, X ), Y ), Z ), apply( Y, apply( X, Z ) ) )
% 0.69/1.10     ],
% 0.69/1.10     [ ~( =( X, apply( combinator, X ) ) ) ]
% 0.69/1.10  ] .
% 0.69/1.10  
% 0.69/1.10  
% 0.69/1.10  percentage equality = 1.000000, percentage horn = 1.000000
% 0.69/1.10  This is a pure equality problem
% 0.69/1.10  
% 0.69/1.10  
% 0.69/1.10  
% 0.69/1.10  Options Used:
% 0.69/1.10  
% 0.69/1.10  useres =            1
% 0.69/1.10  useparamod =        1
% 0.69/1.10  useeqrefl =         1
% 0.69/1.10  useeqfact =         1
% 0.69/1.10  usefactor =         1
% 0.69/1.10  usesimpsplitting =  0
% 0.69/1.10  usesimpdemod =      5
% 0.69/1.10  usesimpres =        3
% 0.69/1.10  
% 0.69/1.10  resimpinuse      =  1000
% 0.69/1.10  resimpclauses =     20000
% 0.69/1.10  substype =          eqrewr
% 0.69/1.10  backwardsubs =      1
% 0.69/1.10  selectoldest =      5
% 0.69/1.10  
% 0.69/1.10  litorderings [0] =  split
% 0.69/1.10  litorderings [1] =  extend the termordering, first sorting on arguments
% 0.69/1.10  
% 0.69/1.10  termordering =      kbo
% 0.69/1.10  
% 0.69/1.10  litapriori =        0
% 0.69/1.10  termapriori =       1
% 0.69/1.10  litaposteriori =    0
% 0.69/1.10  termaposteriori =   0
% 0.69/1.10  demodaposteriori =  0
% 0.69/1.10  ordereqreflfact =   0
% 0.69/1.10  
% 0.69/1.10  litselect =         negord
% 0.69/1.10  
% 0.69/1.10  maxweight =         15
% 0.69/1.10  maxdepth =          30000
% 0.69/1.10  maxlength =         115
% 0.69/1.10  maxnrvars =         195
% 0.69/1.10  excuselevel =       1
% 0.69/1.10  increasemaxweight = 1
% 0.69/1.10  
% 0.69/1.10  maxselected =       10000000
% 0.69/1.10  maxnrclauses =      10000000
% 0.69/1.10  
% 0.69/1.10  showgenerated =    0
% 0.69/1.10  showkept =         0
% 0.69/1.10  showselected =     0
% 0.69/1.10  showdeleted =      0
% 0.69/1.10  showresimp =       1
% 0.69/1.10  showstatus =       2000
% 0.69/1.10  
% 0.69/1.10  prologoutput =     1
% 0.69/1.10  nrgoals =          5000000
% 0.69/1.10  totalproof =       1
% 0.69/1.10  
% 0.69/1.10  Symbols occurring in the translation:
% 0.69/1.10  
% 0.69/1.10  {}  [0, 0]      (w:1, o:2, a:1, s:1, b:0), 
% 0.69/1.10  .  [1, 2]      (w:1, o:20, a:1, s:1, b:0), 
% 0.69/1.10  !  [4, 1]      (w:0, o:15, a:1, s:1, b:0), 
% 0.69/1.10  =  [13, 2]      (w:1, o:0, a:0, s:1, b:0), 
% 0.69/1.10  ==>  [14, 2]      (w:1, o:0, a:0, s:1, b:0), 
% 0.69/1.10  m  [39, 0]      (w:1, o:9, a:1, s:1, b:0), 
% 0.69/1.10  apply  [41, 2]      (w:1, o:45, a:1, s:1, b:0), 
% 0.69/1.10  q  [42, 0]      (w:1, o:11, a:1, s:1, b:0), 
% 0.69/1.10  combinator  [45, 0]      (w:1, o:14, a:1, s:1, b:0).
% 0.69/1.10  
% 0.69/1.10  
% 0.69/1.10  Starting Search:
% 0.69/1.10  
% 0.69/1.10  
% 0.69/1.10  Bliksems!, er is een bewijs:
% 0.69/1.10  % SZS status Unsatisfiable
% 0.69/1.10  % SZS output start Refutation
% 0.69/1.10  
% 0.69/1.10  clause( 0, [ =( apply( m, X ), apply( X, X ) ) ] )
% 0.69/1.10  .
% 0.69/1.10  clause( 1, [ =( apply( apply( apply( q, X ), Y ), Z ), apply( Y, apply( X, 
% 0.69/1.10    Z ) ) ) ] )
% 0.69/1.10  .
% 0.69/1.10  clause( 2, [ ~( =( apply( combinator, X ), X ) ) ] )
% 0.69/1.10  .
% 0.69/1.10  clause( 4, [ =( apply( Y, apply( X, apply( apply( q, X ), Y ) ) ), apply( m
% 0.69/1.10    , apply( apply( q, X ), Y ) ) ) ] )
% 0.69/1.10  .
% 0.69/1.10  clause( 8, [] )
% 0.69/1.10  .
% 0.69/1.10  
% 0.69/1.10  
% 0.69/1.10  % SZS output end Refutation
% 0.69/1.10  found a proof!
% 0.69/1.10  
% 0.69/1.10  % ABCDEFGHIJKLMNOPQRSTUVWXYZ
% 0.69/1.10  
% 0.69/1.10  initialclauses(
% 0.69/1.10  [ clause( 10, [ =( apply( m, X ), apply( X, X ) ) ] )
% 0.69/1.10  , clause( 11, [ =( apply( apply( apply( q, X ), Y ), Z ), apply( Y, apply( 
% 0.69/1.10    X, Z ) ) ) ] )
% 0.69/1.10  , clause( 12, [ ~( =( X, apply( combinator, X ) ) ) ] )
% 0.69/1.10  ] ).
% 0.69/1.10  
% 0.69/1.10  
% 0.69/1.10  
% 0.69/1.10  subsumption(
% 0.69/1.10  clause( 0, [ =( apply( m, X ), apply( X, X ) ) ] )
% 0.69/1.10  , clause( 10, [ =( apply( m, X ), apply( X, X ) ) ] )
% 0.69/1.10  , substitution( 0, [ :=( X, X )] ), permutation( 0, [ ==>( 0, 0 )] ) ).
% 0.69/1.10  
% 0.69/1.10  
% 0.69/1.10  subsumption(
% 0.69/1.10  clause( 1, [ =( apply( apply( apply( q, X ), Y ), Z ), apply( Y, apply( X, 
% 0.69/1.10    Z ) ) ) ] )
% 0.69/1.10  , clause( 11, [ =( apply( apply( apply( q, X ), Y ), Z ), apply( Y, apply( 
% 0.69/1.10    X, Z ) ) ) ] )
% 0.69/1.10  , substitution( 0, [ :=( X, X ), :=( Y, Y ), :=( Z, Z )] ), 
% 0.69/1.10    permutation( 0, [ ==>( 0, 0 )] ) ).
% 0.69/1.10  
% 0.69/1.10  
% 0.69/1.10  eqswap(
% 0.69/1.10  clause( 18, [ ~( =( apply( combinator, X ), X ) ) ] )
% 0.69/1.10  , clause( 12, [ ~( =( X, apply( combinator, X ) ) ) ] )
% 0.69/1.10  , 0, substitution( 0, [ :=( X, X )] )).
% 0.69/1.10  
% 0.69/1.10  
% 0.69/1.10  subsumption(
% 0.69/1.10  clause( 2, [ ~( =( apply( combinator, X ), X ) ) ] )
% 0.69/1.10  , clause( 18, [ ~( =( apply( combinator, X ), X ) ) ] )
% 0.69/1.10  , substitution( 0, [ :=( X, X )] ), permutation( 0, [ ==>( 0, 0 )] ) ).
% 0.69/1.10  
% 0.69/1.10  
% 0.69/1.10  eqswap(
% 0.69/1.10  clause( 19, [ =( apply( Y, apply( X, Z ) ), apply( apply( apply( q, X ), Y
% 0.69/1.10     ), Z ) ) ] )
% 0.69/1.10  , clause( 1, [ =( apply( apply( apply( q, X ), Y ), Z ), apply( Y, apply( X
% 0.69/1.10    , Z ) ) ) ] )
% 0.69/1.10  , 0, substitution( 0, [ :=( X, X ), :=( Y, Y ), :=( Z, Z )] )).
% 0.69/1.10  
% 0.69/1.10  
% 0.69/1.10  eqswap(
% 0.69/1.10  clause( 20, [ =( apply( X, X ), apply( m, X ) ) ] )
% 0.69/1.10  , clause( 0, [ =( apply( m, X ), apply( X, X ) ) ] )
% 0.69/1.10  , 0, substitution( 0, [ :=( X, X )] )).
% 0.69/1.10  
% 0.69/1.10  
% 0.69/1.10  paramod(
% 0.69/1.10  clause( 23, [ =( apply( X, apply( Y, apply( apply( q, Y ), X ) ) ), apply( 
% 0.69/1.10    m, apply( apply( q, Y ), X ) ) ) ] )
% 0.69/1.10  , clause( 20, [ =( apply( X, X ), apply( m, X ) ) ] )
% 0.69/1.10  , 0, clause( 19, [ =( apply( Y, apply( X, Z ) ), apply( apply( apply( q, X
% 0.69/1.10     ), Y ), Z ) ) ] )
% 0.69/1.10  , 0, 10, substitution( 0, [ :=( X, apply( apply( q, Y ), X ) )] ), 
% 0.69/1.10    substitution( 1, [ :=( X, Y ), :=( Y, X ), :=( Z, apply( apply( q, Y ), X
% 0.69/1.10     ) )] )).
% 0.69/1.10  
% 0.69/1.10  
% 0.69/1.10  subsumption(
% 0.69/1.10  clause( 4, [ =( apply( Y, apply( X, apply( apply( q, X ), Y ) ) ), apply( m
% 0.69/1.10    , apply( apply( q, X ), Y ) ) ) ] )
% 0.69/1.10  , clause( 23, [ =( apply( X, apply( Y, apply( apply( q, Y ), X ) ) ), apply( 
% 0.69/1.10    m, apply( apply( q, Y ), X ) ) ) ] )
% 0.69/1.10  , substitution( 0, [ :=( X, Y ), :=( Y, X )] ), permutation( 0, [ ==>( 0, 0
% 0.69/1.10     )] ) ).
% 0.69/1.10  
% 0.69/1.10  
% 0.69/1.10  eqswap(
% 0.69/1.10  clause( 31, [ =( apply( m, apply( apply( q, Y ), X ) ), apply( X, apply( Y
% 0.69/1.10    , apply( apply( q, Y ), X ) ) ) ) ] )
% 0.69/1.10  , clause( 4, [ =( apply( Y, apply( X, apply( apply( q, X ), Y ) ) ), apply( 
% 0.69/1.10    m, apply( apply( q, X ), Y ) ) ) ] )
% 0.69/1.10  , 0, substitution( 0, [ :=( X, Y ), :=( Y, X )] )).
% 0.69/1.10  
% 0.69/1.10  
% 0.69/1.10  eqswap(
% 0.69/1.10  clause( 32, [ ~( =( X, apply( combinator, X ) ) ) ] )
% 0.69/1.10  , clause( 2, [ ~( =( apply( combinator, X ), X ) ) ] )
% 0.69/1.10  , 0, substitution( 0, [ :=( X, X )] )).
% 0.69/1.10  
% 0.69/1.10  
% 0.69/1.10  resolution(
% 0.69/1.10  clause( 33, [] )
% 0.69/1.10  , clause( 32, [ ~( =( X, apply( combinator, X ) ) ) ] )
% 0.69/1.10  , 0, clause( 31, [ =( apply( m, apply( apply( q, Y ), X ) ), apply( X, 
% 0.69/1.10    apply( Y, apply( apply( q, Y ), X ) ) ) ) ] )
% 0.69/1.10  , 0, substitution( 0, [ :=( X, apply( m, apply( apply( q, m ), combinator )
% 0.69/1.10     ) )] ), substitution( 1, [ :=( X, combinator ), :=( Y, m )] )).
% 0.69/1.10  
% 0.69/1.10  
% 0.69/1.10  subsumption(
% 0.69/1.10  clause( 8, [] )
% 0.69/1.10  , clause( 33, [] )
% 0.69/1.10  , substitution( 0, [] ), permutation( 0, [] ) ).
% 0.69/1.10  
% 0.69/1.10  
% 0.69/1.10  end.
% 0.69/1.10  
% 0.69/1.10  % ABCDEFGHIJKLMNOPQRSTUVWXYZ
% 0.69/1.10  
% 0.69/1.10  Memory use:
% 0.69/1.10  
% 0.69/1.10  space for terms:        163
% 0.69/1.10  space for clauses:      1048
% 0.69/1.10  
% 0.69/1.10  
% 0.69/1.10  clauses generated:      26
% 0.69/1.10  clauses kept:           9
% 0.69/1.10  clauses selected:       6
% 0.69/1.10  clauses deleted:        0
% 0.69/1.10  clauses inuse deleted:  0
% 0.69/1.10  
% 0.69/1.10  subsentry:          114
% 0.69/1.10  literals s-matched: 28
% 0.69/1.10  literals matched:   28
% 0.69/1.10  full subsumption:   0
% 0.69/1.10  
% 0.69/1.10  checksum:           1136837580
% 0.69/1.10  
% 0.69/1.10  
% 0.69/1.10  Bliksem ended
%------------------------------------------------------------------------------