TSTP Solution File: CAT016-4 by Twee---2.4.2

View Problem - Process Solution

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% File     : Twee---2.4.2
% Problem  : CAT016-4 : TPTP v8.1.2. Released v1.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof

% Computer : n002.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Aug 30 18:18:58 EDT 2023

% Result   : Unsatisfiable 0.12s 0.39s
% Output   : Proof 0.12s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem  : CAT016-4 : TPTP v8.1.2. Released v1.0.0.
% 0.00/0.13  % Command  : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof
% 0.12/0.34  % Computer : n002.cluster.edu
% 0.12/0.34  % Model    : x86_64 x86_64
% 0.12/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34  % Memory   : 8042.1875MB
% 0.12/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34  % CPULimit : 300
% 0.12/0.34  % WCLimit  : 300
% 0.12/0.34  % DateTime : Sun Aug 27 01:08:03 EDT 2023
% 0.12/0.34  % CPUTime  : 
% 0.12/0.39  Command-line arguments: --no-flatten-goal
% 0.12/0.39  
% 0.12/0.39  % SZS status Unsatisfiable
% 0.12/0.39  
% 0.12/0.39  % SZS output start Proof
% 0.12/0.39  Take the following subset of the input axioms:
% 0.12/0.39    fof(assume_a_exists, hypothesis, there_exists(a)).
% 0.12/0.39    fof(compose_domain, axiom, ![X]: compose(X, domain(X))=X).
% 0.12/0.39    fof(composition_implies_domain, axiom, ![Y, X2]: (~there_exists(compose(X2, Y)) | there_exists(domain(X2)))).
% 0.12/0.39    fof(prove_domain_of_a_exists, negated_conjecture, ~there_exists(domain(a))).
% 0.12/0.39  
% 0.12/0.39  Now clausify the problem and encode Horn clauses using encoding 3 of
% 0.12/0.39  http://www.cse.chalmers.se/~nicsma/papers/horn.pdf.
% 0.12/0.40  We repeatedly replace C & s=t => u=v by the two clauses:
% 0.12/0.40    fresh(y, y, x1...xn) = u
% 0.12/0.40    C => fresh(s, t, x1...xn) = v
% 0.12/0.40  where fresh is a fresh function symbol and x1..xn are the free
% 0.12/0.40  variables of u and v.
% 0.12/0.40  A predicate p(X) is encoded as p(X)=true (this is sound, because the
% 0.12/0.40  input problem has no model of domain size 1).
% 0.12/0.40  
% 0.12/0.40  The encoding turns the above axioms into the following unit equations and goals:
% 0.12/0.40  
% 0.12/0.40  Axiom 1 (assume_a_exists): there_exists(a) = true.
% 0.12/0.40  Axiom 2 (composition_implies_domain): fresh9(X, X, Y) = true.
% 0.12/0.40  Axiom 3 (compose_domain): compose(X, domain(X)) = X.
% 0.12/0.40  Axiom 4 (composition_implies_domain): fresh9(there_exists(compose(X, Y)), true, X) = there_exists(domain(X)).
% 0.12/0.40  
% 0.12/0.40  Goal 1 (prove_domain_of_a_exists): there_exists(domain(a)) = true.
% 0.12/0.40  Proof:
% 0.12/0.40    there_exists(domain(a))
% 0.12/0.40  = { by axiom 4 (composition_implies_domain) R->L }
% 0.12/0.40    fresh9(there_exists(compose(a, domain(a))), true, a)
% 0.12/0.40  = { by axiom 3 (compose_domain) }
% 0.12/0.40    fresh9(there_exists(a), true, a)
% 0.12/0.40  = { by axiom 1 (assume_a_exists) }
% 0.12/0.40    fresh9(true, true, a)
% 0.12/0.40  = { by axiom 2 (composition_implies_domain) }
% 0.12/0.40    true
% 0.12/0.40  % SZS output end Proof
% 0.12/0.40  
% 0.12/0.40  RESULT: Unsatisfiable (the axioms are contradictory).
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