TSTP Solution File: ANA017-2 by SOS---2.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SOS---2.0
% Problem  : ANA017-2 : TPTP v8.1.0. Released v3.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : sos-script %s

% Computer : n026.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Thu Jul 14 19:27:44 EDT 2022

% Result   : Unsatisfiable 0.50s 0.72s
% Output   : Refutation 0.50s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.11  % Problem  : ANA017-2 : TPTP v8.1.0. Released v3.2.0.
% 0.03/0.12  % Command  : sos-script %s
% 0.12/0.33  % Computer : n026.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 600
% 0.12/0.33  % DateTime : Fri Jul  8 04:12:54 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 0.12/0.35  ----- Otter 3.2, August 2001 -----
% 0.12/0.35  The process was started by sandbox on n026.cluster.edu,
% 0.12/0.35  Fri Jul  8 04:12:54 2022
% 0.12/0.35  The command was "./sos".  The process ID is 4813.
% 0.12/0.35  
% 0.12/0.35  set(prolog_style_variables).
% 0.12/0.35  set(auto).
% 0.12/0.35     dependent: set(auto1).
% 0.12/0.35     dependent: set(process_input).
% 0.12/0.35     dependent: clear(print_kept).
% 0.12/0.35     dependent: clear(print_new_demod).
% 0.12/0.35     dependent: clear(print_back_demod).
% 0.12/0.35     dependent: clear(print_back_sub).
% 0.12/0.35     dependent: set(control_memory).
% 0.12/0.35     dependent: assign(max_mem, 12000).
% 0.12/0.35     dependent: assign(pick_given_ratio, 4).
% 0.12/0.35     dependent: assign(stats_level, 1).
% 0.12/0.35     dependent: assign(pick_semantic_ratio, 3).
% 0.12/0.35     dependent: assign(sos_limit, 5000).
% 0.12/0.35     dependent: assign(max_weight, 60).
% 0.12/0.35  clear(print_given).
% 0.12/0.35  
% 0.12/0.35  list(usable).
% 0.12/0.35  
% 0.12/0.35  SCAN INPUT: prop=0, horn=1, equality=1, symmetry=0, max_lits=4.
% 0.12/0.35  
% 0.12/0.35  This is a Horn set with equality.  The strategy will be
% 0.12/0.35  Knuth-Bendix and hyper_res, with positive clauses in
% 0.12/0.35  sos and nonpositive clauses in usable.
% 0.12/0.35  
% 0.12/0.35     dependent: set(knuth_bendix).
% 0.12/0.35     dependent: set(para_from).
% 0.12/0.35     dependent: set(para_into).
% 0.12/0.35     dependent: clear(para_from_right).
% 0.12/0.35     dependent: clear(para_into_right).
% 0.12/0.35     dependent: set(para_from_vars).
% 0.12/0.35     dependent: set(eq_units_both_ways).
% 0.12/0.35     dependent: set(dynamic_demod_all).
% 0.12/0.35     dependent: set(dynamic_demod).
% 0.12/0.35     dependent: set(order_eq).
% 0.12/0.35     dependent: set(back_demod).
% 0.12/0.35     dependent: set(lrpo).
% 0.12/0.35     dependent: set(hyper_res).
% 0.12/0.35     dependent: clear(order_hyper).
% 0.12/0.35  
% 0.12/0.35  ------------> process usable:
% 0.12/0.35  
% 0.12/0.35  ------------> process sos:
% 0.12/0.35    Following clause subsumed by 11 during input processing: 0 [copy,11,flip.1] {-} A=A.
% 0.12/0.35  
% 0.12/0.35  ======= end of input processing =======
% 0.19/0.38  
% 0.19/0.38  Model 1 (0.00 seconds, 0 Inserts)
% 0.19/0.38  
% 0.19/0.38  Stopped by limit on number of solutions
% 0.19/0.38  
% 0.19/0.38  
% 0.19/0.38  -------------- Softie stats --------------
% 0.19/0.38  
% 0.19/0.38  UPDATE_STOP: 300
% 0.19/0.38  SFINDER_TIME_LIMIT: 2
% 0.19/0.38  SHORT_CLAUSE_CUTOFF: 4
% 0.19/0.38  number of clauses in intial UL: 8
% 0.19/0.38  number of clauses initially in problem: 11
% 0.19/0.38  percentage of clauses intially in UL: 72
% 0.19/0.38  percentage of distinct symbols occuring in initial UL: 93
% 0.19/0.38  percent of all initial clauses that are short: 90
% 0.19/0.38  absolute distinct symbol count: 15
% 0.19/0.38     distinct predicate count: 6
% 0.19/0.38     distinct function count: 5
% 0.19/0.38     distinct constant count: 4
% 0.19/0.38  
% 0.19/0.38  ---------- no more Softie stats ----------
% 0.19/0.38  
% 0.19/0.38  
% 0.19/0.38  
% 0.19/0.38  =========== start of search ===========
% 0.50/0.72  
% 0.50/0.72  -------- PROOF -------- 
% 0.50/0.72  % SZS status Unsatisfiable
% 0.50/0.72  % SZS output start Refutation
% 0.50/0.72  
% 0.50/0.72  Stopped by limit on insertions
% 0.50/0.72  
% 0.50/0.72  Stopped by limit on insertions
% 0.50/0.72  
% 0.50/0.72  ----> UNIT CONFLICT at   0.34 sec ----> 34 [binary,33.1,23.1] {-} $F.
% 0.50/0.72  
% 0.50/0.72  Length of proof is 9.  Level of proof is 3.
% 0.50/0.72  
% 0.50/0.72  ---------------- PROOF ----------------
% 0.50/0.72  % SZS status Unsatisfiable
% 0.50/0.72  % SZS output start Refutation
% 0.50/0.72  
% 0.50/0.72  1 [] {+} -c_lessequals(c_HOL_Oabs(c_times(v_c,v_b(v_x(A)),t_b),t_b),c_times(A,c_HOL_Oabs(v_f(v_x(A)),t_b),t_b),t_b).
% 0.50/0.72  2 [] {+} -class_OrderedGroup_Olordered__ab__group__abs(A)|c_lessequals(c_0,c_HOL_Oabs(B,A),A).
% 0.50/0.72  3 [] {+} -class_OrderedGroup_Osemigroup__mult(A)|c_times(c_times(B,C,A),D,A)=c_times(B,c_times(C,D,A),A).
% 0.50/0.72  4 [] {+} -class_Ring__and__Field_Oordered__idom(A)|c_HOL_Oabs(c_times(B,C,A),A)=c_times(c_HOL_Oabs(B,A),c_HOL_Oabs(C,A),A).
% 0.50/0.72  5 [] {+} -class_Ring__and__Field_Opordered__semiring(A)| -c_lessequals(B,C,A)| -c_lessequals(c_0,D,A)|c_lessequals(c_times(D,B,A),c_times(D,C,A),A).
% 0.50/0.72  6 [] {+} -class_Ring__and__Field_Oordered__idom(A)|class_OrderedGroup_Osemigroup__mult(A).
% 0.50/0.72  7 [] {+} -class_Ring__and__Field_Oordered__idom(A)|class_Ring__and__Field_Opordered__semiring(A).
% 0.50/0.72  8 [] {+} -class_Ring__and__Field_Oordered__idom(A)|class_OrderedGroup_Olordered__ab__group__abs(A).
% 0.50/0.72  9 [] {-} c_lessequals(c_HOL_Oabs(v_b(A),t_b),c_times(v_ca,c_HOL_Oabs(v_f(A),t_b),t_b),t_b).
% 0.50/0.72  10 [] {-} class_Ring__and__Field_Oordered__idom(t_b).
% 0.50/0.72  12 [hyper,10,8] {+} class_OrderedGroup_Olordered__ab__group__abs(t_b).
% 0.50/0.72  13 [hyper,10,7] {+} class_Ring__and__Field_Opordered__semiring(t_b).
% 0.50/0.72  14 [hyper,10,6] {-} class_OrderedGroup_Osemigroup__mult(t_b).
% 0.50/0.72  16,15 [hyper,10,4] {+} c_HOL_Oabs(c_times(A,B,t_b),t_b)=c_times(c_HOL_Oabs(A,t_b),c_HOL_Oabs(B,t_b),t_b).
% 0.50/0.72  17 [back_demod,1,demod,16] {+} -c_lessequals(c_times(c_HOL_Oabs(v_c,t_b),c_HOL_Oabs(v_b(v_x(A)),t_b),t_b),c_times(A,c_HOL_Oabs(v_f(v_x(A)),t_b),t_b),t_b).
% 0.50/0.72  18 [hyper,14,3] {-} c_times(c_times(A,B,t_b),C,t_b)=c_times(A,c_times(B,C,t_b),t_b).
% 0.50/0.72  21 [hyper,12,2] {+} c_lessequals(c_0,c_HOL_Oabs(A,t_b),t_b).
% 0.50/0.72  23 [hyper,21,5,13,9] {-} c_lessequals(c_times(c_HOL_Oabs(A,t_b),c_HOL_Oabs(v_b(B),t_b),t_b),c_times(c_HOL_Oabs(A,t_b),c_times(v_ca,c_HOL_Oabs(v_f(B),t_b),t_b),t_b),t_b).
% 0.50/0.72  33 [para_into,17.1.2,18.1.1] {-} -c_lessequals(c_times(c_HOL_Oabs(v_c,t_b),c_HOL_Oabs(v_b(v_x(c_times(A,B,t_b))),t_b),t_b),c_times(A,c_times(B,c_HOL_Oabs(v_f(v_x(c_times(A,B,t_b))),t_b),t_b),t_b),t_b).
% 0.50/0.72  34 [binary,33.1,23.1] {-} $F.
% 0.50/0.72  
% 0.50/0.72  % SZS output end Refutation
% 0.50/0.72  ------------ end of proof -------------
% 0.50/0.72  
% 0.50/0.72  
% 0.50/0.72  Search stopped by max_proofs option.
% 0.50/0.72  
% 0.50/0.72  
% 0.50/0.72  Search stopped by max_proofs option.
% 0.50/0.72  
% 0.50/0.72  ============ end of search ============
% 0.50/0.72  
% 0.50/0.72  ----------- soft-scott stats ----------
% 0.50/0.72  
% 0.50/0.72  true clauses given           8      (50.0%)
% 0.50/0.72  false clauses given          8
% 0.50/0.72  
% 0.50/0.72        FALSE     TRUE
% 0.50/0.72    16  0         2
% 0.50/0.72    21  0         1
% 0.50/0.72    26  0         1
% 0.50/0.72    29  0         1
% 0.50/0.72    31  0         1
% 0.50/0.72  tot:  0         6      (100.0% true)
% 0.50/0.72  
% 0.50/0.72  
% 0.50/0.72  Model 1 (0.00 seconds, 0 Inserts)
% 0.50/0.72  
% 0.50/0.72  That finishes the proof of the theorem.
% 0.50/0.72  
% 0.50/0.72  Process 4813 finished Fri Jul  8 04:12:55 2022
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