TSTP Solution File: ALG200+1 by Etableau---0.67
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%------------------------------------------------------------------------------
% File : Etableau---0.67
% Problem : ALG200+1 : TPTP v8.1.0. Released v2.7.0.
% Transfm : none
% Format : tptp:raw
% Command : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s
% Computer : n029.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Thu Jul 14 16:51:56 EDT 2022
% Result : Theorem 0.14s 0.40s
% Output : CNFRefutation 0.14s
% Verified :
% SZS Type : Refutation
% Derivation depth : 4
% Number of leaves : 1
% Syntax : Number of formulae : 12 ( 8 unt; 0 def)
% Number of atoms : 78 ( 77 equ)
% Maximal formula atoms : 21 ( 6 avg)
% Number of connectives : 97 ( 31 ~; 42 |; 24 &)
% ( 0 <=>; 0 =>; 0 <=; 0 <~>)
% Maximal formula depth : 18 ( 6 avg)
% Maximal term depth : 2 ( 1 avg)
% Number of predicates : 2 ( 0 usr; 1 prp; 0-2 aty)
% Number of functors : 8 ( 8 usr; 7 con; 0-2 aty)
% Number of variables : 0 ( 0 sgn 0 !; 0 ?)
% Comments :
%------------------------------------------------------------------------------
fof(co1,conjecture,
~ ( op(e0,e0) = e0
& op(e1,e1) = e1
& op(e2,e2) = e2
& op(e3,e3) = e3
& op(e4,e4) = e4
& op(e5,e5) = e5
& op(e6,e6) = e6
& ( op(e0,e0) = e0
| op(e1,e1) = e1
| op(e2,e2) = e2
| op(e3,e3) = e3
| op(e4,e4) = e4
| op(e5,e5) = e5
| op(e6,e6) = e6 )
& ( op(e0,e0) != e0
| op(e1,e1) != e1
| op(e2,e2) != e2
| op(e3,e3) != e3
| op(e4,e4) != e4
| op(e5,e5) != e5
| op(e6,e6) != e6 ) ),
file('/export/starexec/sandbox/benchmark/theBenchmark.p',co1) ).
fof(c_0_1,negated_conjecture,
~ ~ ( op(e0,e0) = e0
& op(e1,e1) = e1
& op(e2,e2) = e2
& op(e3,e3) = e3
& op(e4,e4) = e4
& op(e5,e5) = e5
& op(e6,e6) = e6
& ( op(e0,e0) = e0
| op(e1,e1) = e1
| op(e2,e2) = e2
| op(e3,e3) = e3
| op(e4,e4) = e4
| op(e5,e5) = e5
| op(e6,e6) = e6 )
& ( op(e0,e0) != e0
| op(e1,e1) != e1
| op(e2,e2) != e2
| op(e3,e3) != e3
| op(e4,e4) != e4
| op(e5,e5) != e5
| op(e6,e6) != e6 ) ),
inference(assume_negation,[status(cth)],[co1]) ).
fof(c_0_2,negated_conjecture,
( op(e0,e0) = e0
& op(e1,e1) = e1
& op(e2,e2) = e2
& op(e3,e3) = e3
& op(e4,e4) = e4
& op(e5,e5) = e5
& op(e6,e6) = e6
& ( op(e0,e0) = e0
| op(e1,e1) = e1
| op(e2,e2) = e2
| op(e3,e3) = e3
| op(e4,e4) = e4
| op(e5,e5) = e5
| op(e6,e6) = e6 )
& ( op(e0,e0) != e0
| op(e1,e1) != e1
| op(e2,e2) != e2
| op(e3,e3) != e3
| op(e4,e4) != e4
| op(e5,e5) != e5
| op(e6,e6) != e6 ) ),
inference(fof_nnf,[status(thm)],[c_0_1]) ).
cnf(c_0_3,negated_conjecture,
( op(e0,e0) != e0
| op(e1,e1) != e1
| op(e2,e2) != e2
| op(e3,e3) != e3
| op(e4,e4) != e4
| op(e5,e5) != e5
| op(e6,e6) != e6 ),
inference(split_conjunct,[status(thm)],[c_0_2]) ).
cnf(c_0_4,negated_conjecture,
op(e0,e0) = e0,
inference(split_conjunct,[status(thm)],[c_0_2]) ).
cnf(c_0_5,negated_conjecture,
op(e1,e1) = e1,
inference(split_conjunct,[status(thm)],[c_0_2]) ).
cnf(c_0_6,negated_conjecture,
op(e2,e2) = e2,
inference(split_conjunct,[status(thm)],[c_0_2]) ).
cnf(c_0_7,negated_conjecture,
op(e3,e3) = e3,
inference(split_conjunct,[status(thm)],[c_0_2]) ).
cnf(c_0_8,negated_conjecture,
op(e4,e4) = e4,
inference(split_conjunct,[status(thm)],[c_0_2]) ).
cnf(c_0_9,negated_conjecture,
op(e5,e5) = e5,
inference(split_conjunct,[status(thm)],[c_0_2]) ).
cnf(c_0_10,negated_conjecture,
op(e6,e6) = e6,
inference(split_conjunct,[status(thm)],[c_0_2]) ).
cnf(c_0_11,negated_conjecture,
$false,
inference(cn,[status(thm)],[inference(rw,[status(thm)],[inference(rw,[status(thm)],[inference(rw,[status(thm)],[inference(rw,[status(thm)],[inference(rw,[status(thm)],[inference(rw,[status(thm)],[inference(rw,[status(thm)],[c_0_3,c_0_4]),c_0_5]),c_0_6]),c_0_7]),c_0_8]),c_0_9]),c_0_10])]),
[proof] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.13 % Problem : ALG200+1 : TPTP v8.1.0. Released v2.7.0.
% 0.07/0.13 % Command : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s
% 0.14/0.35 % Computer : n029.cluster.edu
% 0.14/0.35 % Model : x86_64 x86_64
% 0.14/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.35 % Memory : 8042.1875MB
% 0.14/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.14/0.35 % CPULimit : 300
% 0.14/0.35 % WCLimit : 600
% 0.14/0.35 % DateTime : Wed Jun 8 05:45:21 EDT 2022
% 0.14/0.35 % CPUTime :
% 0.14/0.40 # No SInE strategy applied
% 0.14/0.40 # Auto-Mode selected heuristic G_E___208_C18_F1_SE_CS_SP_PS_S5PRR_RG_S04AN
% 0.14/0.40 # and selection function SelectComplexExceptUniqMaxHorn.
% 0.14/0.40 #
% 0.14/0.40 # Presaturation interreduction done
% 0.14/0.40
% 0.14/0.40 # Proof found!
% 0.14/0.40 # SZS status Theorem
% 0.14/0.40 # SZS output start CNFRefutation
% See solution above
% 0.14/0.40 # Training examples: 0 positive, 0 negative
%------------------------------------------------------------------------------