TSTP Solution File: AGT038^1 by Satallax---3.5

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Satallax---3.5
% Problem  : AGT038^1 : TPTP v8.1.0. Bugfixed v5.4.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : satallax -E eprover-ho -P picomus -M modes -p tstp -t %d %s

% Computer : n024.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Thu Jul 14 12:03:42 EDT 2022

% Result   : Theorem 5.55s 5.75s
% Output   : Proof 5.55s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.04/0.12  % Problem  : AGT038^1 : TPTP v8.1.0. Bugfixed v5.4.0.
% 0.04/0.13  % Command  : satallax -E eprover-ho -P picomus -M modes -p tstp -t %d %s
% 0.13/0.34  % Computer : n024.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % WCLimit  : 600
% 0.13/0.34  % DateTime : Sat Jun  4 05:10:20 EDT 2022
% 0.13/0.34  % CPUTime  : 
% 5.55/5.75  % SZS status Theorem
% 5.55/5.75  % Mode: mode485:USE_SINE=true:SINE_TOLERANCE=1.2:SINE_GENERALITY_THRESHOLD=4:SINE_RANK_LIMIT=4.:SINE_DEPTH=0
% 5.55/5.75  % Inferences: 5733
% 5.55/5.75  % SZS output start Proof
% 5.55/5.75  thf(ty_mu, type, mu : $tType).
% 5.55/5.75  thf(ty_a3, type, a3 : ($i>$i>$o)).
% 5.55/5.75  thf(ty_eigen__0, type, eigen__0 : $i).
% 5.55/5.75  thf(ty_possibly_likes, type, possibly_likes : (mu>mu>$i>$o)).
% 5.55/5.75  thf(ty_likes, type, likes : (mu>mu>$i>$o)).
% 5.55/5.75  thf(ty_piotr, type, piotr : mu).
% 5.55/5.75  thf(ty_pepsi, type, pepsi : mu).
% 5.55/5.75  thf(h0, assumption, (![X1:$i>$o]:(![X2:$i]:((X1 @ X2) => (X1 @ (eps__0 @ X1))))),introduced(assumption,[])).
% 5.55/5.75  thf(eigendef_eigen__0, definition, eigen__0 = (eps__0 @ (^[X1:$i]:(~((((possibly_likes @ piotr) @ pepsi) @ X1))))), introduced(definition,[new_symbols(definition,[eigen__0])])).
% 5.55/5.75  thf(sP1,plain,sP1 <=> ((~((![X1:$i]:(((a3 @ eigen__0) @ X1) => (~((((likes @ piotr) @ pepsi) @ X1))))))) => (((possibly_likes @ piotr) @ pepsi) @ eigen__0)),introduced(definition,[new_symbols(definition,[sP1])])).
% 5.55/5.75  thf(sP2,plain,sP2 <=> (![X1:mu]:(![X2:mu]:((~((![X3:$i]:(((a3 @ eigen__0) @ X3) => (~((((likes @ X1) @ X2) @ X3))))))) => (((possibly_likes @ X1) @ X2) @ eigen__0)))),introduced(definition,[new_symbols(definition,[sP2])])).
% 5.55/5.75  thf(sP3,plain,sP3 <=> (![X1:mu]:((~((![X2:$i]:(((a3 @ eigen__0) @ X2) => (~((((likes @ piotr) @ X1) @ X2))))))) => (((possibly_likes @ piotr) @ X1) @ eigen__0))),introduced(definition,[new_symbols(definition,[sP3])])).
% 5.55/5.75  thf(sP4,plain,sP4 <=> (![X1:$i]:(![X2:mu]:(![X3:mu]:((~((![X4:$i]:(((a3 @ X1) @ X4) => (~((((likes @ X2) @ X3) @ X4))))))) => (((possibly_likes @ X2) @ X3) @ X1))))),introduced(definition,[new_symbols(definition,[sP4])])).
% 5.55/5.75  thf(sP5,plain,sP5 <=> (![X1:$i]:(~((![X2:$i]:(((a3 @ X1) @ X2) => (~((((likes @ piotr) @ pepsi) @ X2)))))))),introduced(definition,[new_symbols(definition,[sP5])])).
% 5.55/5.75  thf(sP6,plain,sP6 <=> ((!!) @ ((possibly_likes @ piotr) @ pepsi)),introduced(definition,[new_symbols(definition,[sP6])])).
% 5.55/5.75  thf(sP7,plain,sP7 <=> (![X1:$i]:(((a3 @ eigen__0) @ X1) => (~((((likes @ piotr) @ pepsi) @ X1))))),introduced(definition,[new_symbols(definition,[sP7])])).
% 5.55/5.75  thf(sP8,plain,sP8 <=> (((possibly_likes @ piotr) @ pepsi) @ eigen__0),introduced(definition,[new_symbols(definition,[sP8])])).
% 5.55/5.75  thf(def_mnot,definition,(mnot = (^[X1:$i>$o]:(^[X2:$i]:(~((X1 @ X2))))))).
% 5.55/5.75  thf(def_mor,definition,(mor = (^[X1:$i>$o]:(^[X2:$i>$o]:(^[X3:$i]:((~((X1 @ X3))) => (X2 @ X3))))))).
% 5.55/5.75  thf(def_mand,definition,(mand = (^[X1:$i>$o]:(^[X2:$i>$o]:(mnot @ ((mor @ (mnot @ X1)) @ (mnot @ X2))))))).
% 5.55/5.75  thf(def_mimplies,definition,(mimplies = (^[X1:$i>$o]:(mor @ (mnot @ X1))))).
% 5.55/5.75  thf(def_mforall_ind,definition,(mforall_ind = (^[X1:mu>$i>$o]:(^[X2:$i]:(![X3:mu]:((X1 @ X3) @ X2)))))).
% 5.55/5.75  thf(def_mbox,definition,(mbox = (^[X1:$i>$i>$o]:(^[X2:$i>$o]:(^[X3:$i]:(![X4:$i]:(((X1 @ X3) @ X4) => (X2 @ X4)))))))).
% 5.55/5.75  thf(def_mdia,definition,(mdia = (^[X1:$i>$i>$o]:(^[X2:$i>$o]:(mnot @ ((mbox @ X1) @ (mnot @ X2))))))).
% 5.55/5.75  thf(def_mvalid,definition,(mvalid = (!!))).
% 5.55/5.75  thf(conj,conjecture,sP6).
% 5.55/5.75  thf(h1,negated_conjecture,(~(sP6)),inference(assume_negation,[status(cth)],[conj])).
% 5.55/5.75  thf(1,plain,(~(sP4) | sP2),inference(all_rule,[status(thm)],[])).
% 5.55/5.75  thf(2,plain,(~(sP2) | sP3),inference(all_rule,[status(thm)],[])).
% 5.55/5.75  thf(3,plain,(~(sP3) | sP1),inference(all_rule,[status(thm)],[])).
% 5.55/5.75  thf(4,plain,((~(sP1) | sP7) | sP8),inference(prop_rule,[status(thm)],[])).
% 5.55/5.75  thf(5,plain,(~(sP5) | ~(sP7)),inference(all_rule,[status(thm)],[])).
% 5.55/5.75  thf(6,plain,(sP6 | ~(sP8)),inference(eigen_choice_rule,[status(thm),assumptions([h0])],[h0,eigendef_eigen__0])).
% 5.55/5.75  thf(axiom_user_communication_5,axiom,(mvalid @ (mforall_ind @ (^[X1:mu]:(mforall_ind @ (^[X2:mu]:((mimplies @ ((mdia @ a3) @ ((likes @ X1) @ X2))) @ ((possibly_likes @ X1) @ X2)))))))).
% 5.55/5.75  thf(7,plain,sP4,inference(preprocess,[status(thm)],[axiom_user_communication_5]).
% 5.55/5.75  thf(axiom_a3_2,axiom,(mvalid @ ((mdia @ a3) @ ((likes @ piotr) @ pepsi)))).
% 5.55/5.75  thf(8,plain,sP5,inference(preprocess,[status(thm)],[axiom_a3_2]).
% 5.55/5.75  thf(9,plain,$false,inference(prop_unsat,[status(thm),assumptions([h1,h0])],[1,2,3,4,5,6,7,8,h1])).
% 5.55/5.75  thf(10,plain,$false,inference(eigenvar_choice,[status(thm),assumptions([h1]),eigenvar_choice(discharge,[h0])],[9,h0])).
% 5.55/5.75  thf(0,theorem,sP6,inference(contra,[status(thm),contra(discharge,[h1])],[9,h1])).
% 5.55/5.75  % SZS output end Proof
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