TPTP Problem File: SYN305-1.p
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- Solve Problem
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% File : SYN305-1 : TPTP v8.2.0. Released v1.2.0.
% Domain : Syntactic
% Problem : Problem for testing satisfiability
% Version : Especial.
% English :
% Refs : [BCP94] Bourely et al. (1994), A Method for Building Models Au
% Source : [BCP94]
% Names : Example 3 [BCP94]
% Status : Satisfiable
% Rating : 0.44 v8.2.0, 0.60 v8.1.0, 0.50 v7.5.0, 0.75 v7.1.0, 0.67 v6.4.0, 0.75 v6.3.0, 0.67 v6.2.0, 0.83 v6.1.0, 0.80 v5.4.0, 0.75 v5.3.0, 0.67 v2.4.0, 0.33 v2.2.1, 0.25 v2.2.0, 0.67 v2.1.0, 0.00 v2.0.0
% Syntax : Number of clauses : 3 ( 3 unt; 0 nHn; 1 RR)
% Number of literals : 3 ( 3 equ; 1 neg)
% Maximal clause size : 1 ( 1 avg)
% Maximal term depth : 3 ( 2 avg)
% Number of predicates : 1 ( 0 usr; 0 prp; 2-2 aty)
% Number of functors : 3 ( 3 usr; 0 con; 1-1 aty)
% Number of variables : 3 ( 0 sgn)
% SPC : CNF_SAT_RFO_PEQ_UEQ
% Comments : Infinox says this has no finite (counter-) models.
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cnf(clause1,negated_conjecture,
f(g1(X)) = X ).
cnf(clause2,negated_conjecture,
f(g2(X)) = X ).
cnf(clause3,negated_conjecture,
g1(X) != g2(X) ).
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