TPTP Problem File: SYN063-2.p
View Solutions
- Solve Problem
%--------------------------------------------------------------------------
% File : SYN063-2 : TPTP v9.0.0. Released v1.2.0.
% Domain : Syntactic
% Problem : Pelletier Problem 33
% Version : Especial.
% Theorem formulation : Different clausification.
% English :
% Refs : [KM64] Kalish & Montegue (1964), Logic: Techniques of Formal
% : [Pel86] Pelletier (1986), Seventy-five Problems for Testing Au
% Source : [TPTP]
% Names :
% Status : Unsatisfiable
% Rating : 0.00 v2.0.0
% Syntax : Number of clauses : 3 ( 2 unt; 0 nHn; 3 RR)
% Number of literals : 4 ( 0 equ; 2 neg)
% Maximal clause size : 2 ( 1 avg)
% Maximal term depth : 1 ( 1 avg)
% Number of predicates : 1 ( 1 usr; 0 prp; 1-1 aty)
% Number of functors : 2 ( 2 usr; 2 con; 0-0 aty)
% Number of variables : 0 ( 0 sgn)
% SPC : CNF_UNS_EPR_NEQ_HRN
% Comments : This is a monadic predicate formulation of Pelletier 17.
% : Created using the TPTP clausifier.
%--------------------------------------------------------------------------
cnf(pel33_1,negated_conjecture,
( big_p(c)
| ~ big_p(a) ) ).
cnf(pel33_2,negated_conjecture,
big_p(a) ).
cnf(pel33_3,negated_conjecture,
~ big_p(c) ).
%--------------------------------------------------------------------------