TPTP Problem File: SWC029+1.p
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%--------------------------------------------------------------------------
% File : SWC029+1 : TPTP v9.0.0. Released v2.4.0.
% Domain : Software Creation
% Problem : cond_id_nil_iff_x_rot_l_total2
% Version : [Wei00] axioms.
% English : Find components in a software library that match a given target
% specification given in first-order logic. The components are
% specified in first-order logic as well. The problem represents
% a test of one library module specification against a target
% specification.
% Refs : [Wei00] Weidenbach (2000), Software Reuse of List Functions Ve
% : [FSS98] Fischer et al. (1998), Deduction-Based Software Compon
% Source : [Wei00]
% Names : cond_id_nil_iff_x_rot_l_total2 [Wei00]
% Status : Theorem
% Rating : 0.36 v9.0.0, 0.42 v8.2.0, 0.39 v8.1.0, 0.36 v7.5.0, 0.41 v7.4.0, 0.27 v7.3.0, 0.34 v7.2.0, 0.31 v7.1.0, 0.35 v7.0.0, 0.30 v6.4.0, 0.38 v6.2.0, 0.44 v6.1.0, 0.53 v6.0.0, 0.52 v5.5.0, 0.59 v5.4.0, 0.61 v5.3.0, 0.63 v5.2.0, 0.50 v5.1.0, 0.52 v5.0.0, 0.54 v4.1.0, 0.52 v4.0.0, 0.50 v3.5.0, 0.47 v3.4.0, 0.53 v3.3.0, 0.43 v3.2.0, 0.45 v3.1.0, 0.56 v2.7.0, 0.50 v2.4.0
% Syntax : Number of formulae : 96 ( 9 unt; 0 def)
% Number of atoms : 411 ( 81 equ)
% Maximal formula atoms : 17 ( 4 avg)
% Number of connectives : 346 ( 31 ~; 15 |; 41 &)
% ( 26 <=>; 233 =>; 0 <=; 0 <~>)
% Maximal formula depth : 20 ( 7 avg)
% Maximal term depth : 4 ( 1 avg)
% Number of predicates : 20 ( 19 usr; 0 prp; 1-2 aty)
% Number of functors : 5 ( 5 usr; 1 con; 0-2 aty)
% Number of variables : 209 ( 196 !; 13 ?)
% SPC : FOF_THM_RFO_SEQ
% Comments :
%--------------------------------------------------------------------------
%----Include list specification axioms
include('Axioms/SWC001+0.ax').
%--------------------------------------------------------------------------
fof(co1,conjecture,
! [U] :
( ssList(U)
=> ! [V] :
( ssList(V)
=> ! [W] :
( ssList(W)
=> ! [X] :
( ssList(X)
=> ( V != X
| U != W
| ( nil != W
& nil = X )
| ( ! [Y] :
( ssItem(Y)
=> ! [Z] :
( ssList(Z)
=> ( app(cons(Y,nil),Z) != X
| app(Z,cons(Y,nil)) != W ) ) )
& neq(X,nil) )
| ( ( nil != V
| nil = U )
& ( nil != U
| nil = V ) ) ) ) ) ) ) ).
%--------------------------------------------------------------------------