TPTP Problem File: SET839-2.p
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- Solve Problem
%------------------------------------------------------------------------------
% File : SET839-2 : TPTP v9.0.0. Released v3.2.0.
% Domain : Set Theory
% Problem : Problem about set theory
% Version : [Pau06] axioms : Reduced > Especial.
% English :
% Refs : [Pau06] Paulson (2006), Email to G. Sutcliffe
% Source : [Pau06]
% Names :
% Status : Unsatisfiable
% Rating : 0.10 v9.0.0, 0.15 v8.2.0, 0.14 v8.1.0, 0.05 v7.5.0, 0.11 v7.4.0, 0.12 v7.3.0, 0.17 v7.1.0, 0.08 v7.0.0, 0.20 v6.3.0, 0.18 v6.2.0, 0.20 v6.1.0, 0.36 v6.0.0, 0.20 v5.5.0, 0.30 v5.4.0, 0.35 v5.3.0, 0.33 v5.2.0, 0.25 v5.1.0, 0.24 v5.0.0, 0.21 v4.1.0, 0.31 v4.0.1, 0.36 v3.7.0, 0.10 v3.5.0, 0.18 v3.4.0, 0.25 v3.3.0, 0.29 v3.2.0
% Syntax : Number of clauses : 6 ( 2 unt; 1 nHn; 4 RR)
% Number of literals : 12 ( 1 equ; 6 neg)
% Maximal clause size : 3 ( 2 avg)
% Maximal term depth : 3 ( 1 avg)
% Number of predicates : 3 ( 2 usr; 0 prp; 2-3 aty)
% Number of functors : 6 ( 6 usr; 3 con; 0-3 aty)
% Number of variables : 15 ( 2 sgn)
% SPC : CNF_UNS_RFO_SEQ_NHN
% Comments : The problems in the [Pau06] collection each have very many axioms,
% of which only a small selection are required for the refutation.
% The mission is to find those few axioms, after which a refutation
% can be quite easily found. This version has only the necessary
% axioms.
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cnf(cls_conjecture_0,negated_conjecture,
~ c_lessequals(v_S,c_insert(V_U,c_emptyset,tc_set(t_a)),tc_set(tc_set(t_a))) ).
cnf(cls_conjecture_1,negated_conjecture,
( c_lessequals(V_U,V_V,tc_set(t_a))
| ~ c_in(V_V,v_S,tc_set(t_a))
| ~ c_in(V_U,v_S,tc_set(t_a)) ) ).
cnf(cls_Set_OinsertCI_1,axiom,
c_in(V_x,c_insert(V_x,V_B,T_a),T_a) ).
cnf(cls_Set_OsubsetI_0,axiom,
( c_in(c_Main_OsubsetI__1(V_A,V_B,T_a),V_A,T_a)
| c_lessequals(V_A,V_B,tc_set(T_a)) ) ).
cnf(cls_Set_OsubsetI_1,axiom,
( ~ c_in(c_Main_OsubsetI__1(V_A,V_B,T_a),V_B,T_a)
| c_lessequals(V_A,V_B,tc_set(T_a)) ) ).
cnf(cls_Set_Osubset__antisym_0,axiom,
( ~ c_lessequals(V_B,V_A,tc_set(T_a))
| ~ c_lessequals(V_A,V_B,tc_set(T_a))
| V_A = V_B ) ).
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