TPTP Problem File: RNG131-1.p
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%------------------------------------------------------------------------------
% File : RNG131-1 : TPTP v9.3.1. Released v9.3.0.
% Domain : Rings
% Problem : Brahmagupta Fibonacci identity
% Version : Especial
% English :
% Refs : [Sai24] Saito (2024), Email to Geoff Sutcliffe
% Source : [Sai24]
% Names : brahmagupta-fibonacci.p [Sai24]
% Status : Unsatisfiable
% Rating : 0.56 v9.3.0
% Syntax : Number of clauses : 10 ( 10 unt; 0 nHn; 1 RR)
% Number of literals : 10 ( 10 equ; 1 neg)
% Maximal clause size : 1 ( 1 avg)
% Maximal term depth : 6 ( 2 avg)
% Number of predicates : 1 ( 0 usr; 0 prp; 2-2 aty)
% Number of functors : 9 ( 9 usr; 5 con; 0-2 aty)
% Number of variables : 19 ( 0 sgn)
% SPC : CNF_UNS_RFO_PEQ_UEQ
% Comments : The distributive laws should be used in the distributing way.
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cnf(plus_comm,axiom,
plus(X,Y) = plus(Y,X) ).
cnf(plus_assoc,axiom,
plus(X,plus(Y,Z)) = plus(plus(X,Y),Z) ).
cnf(plus_zero,axiom,
plus(zero,X) = X ).
cnf(plus_inv,axiom,
plus(X,minus(X)) = zero ).
cnf(times_assoc,axiom,
times(X,times(Y,Z)) = times(times(X,Y),Z) ).
cnf(times_com,axiom,
times(X,Y) = times(Y,X) ).
cnf(square,axiom,
sq(X) = times(X,X) ).
cnf(distrib1,axiom,
times(X,plus(Y,Z)) = plus(times(X,Y),times(X,Z)) ).
cnf(distrib2,axiom,
times(plus(X,Y),Z) = plus(times(X,Z),times(Y,Z)) ).
cnf(goals,negated_conjecture,
times(plus(sq(a),sq(b)),plus(sq(c),sq(d))) != plus(sq(plus(times(a,c),times(minus(b),d))),sq(plus(times(a,d),times(b,c)))) ).
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