TPTP Problem File: PUZ061+1.p
View Solutions
- Solve Problem
%------------------------------------------------------------------------------
% File : PUZ061+1 : TPTP v9.0.0. Released v3.1.0.
% Domain : Puzzles
% Problem : Food problems
% Version : Especial.
% English :
% Refs : [Shu04] Shults (2004), Email to G. Sutcliffe
% Source : [Shu04]
% Names :
% Status : Theorem
% Rating : 0.00 v5.3.0, 0.09 v5.2.0, 0.00 v3.1.0
% Syntax : Number of formulae : 1 ( 0 unt; 0 def)
% Number of atoms : 17 ( 0 equ)
% Maximal formula atoms : 17 ( 17 avg)
% Number of connectives : 16 ( 0 ~; 0 |; 10 &)
% ( 0 <=>; 6 =>; 0 <=; 0 <~>)
% Maximal formula depth : 19 ( 19 avg)
% Maximal term depth : 1 ( 1 avg)
% Number of predicates : 5 ( 5 usr; 0 prp; 1-2 aty)
% Number of functors : 0 ( 0 usr; 0 con; --- aty)
% Number of variables : 14 ( 13 !; 1 ?)
% SPC : FOF_THM_EPR_NEQ
% Comments :
%------------------------------------------------------------------------------
fof(prove_this,conjecture,
! [Peanuts,John,Bill,Sue,Apples,Chicken] :
( ( ! [X,Y] :
( ( alive(Y)
& eats(Y,Chicken) )
=> likes(Y,X) )
& ! [X] :
( food(X)
=> likes(John,X) )
& food(Apples)
& food(Chicken)
& ! [X] :
( ? [Y] :
( eats(Y,X)
& not_killed_by(Y,X) )
=> food(X) )
& eats(Bill,Peanuts)
& alive(Bill)
& ! [X] :
( eats(Bill,X)
=> eats(Sue,X) )
& ! [Y] :
( alive(Y)
=> ! [X] : not_killed_by(Y,X) ) )
=> likes(John,Peanuts) ) ).
%------------------------------------------------------------------------------