TPTP Problem File: LCL642+1.001.p
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%------------------------------------------------------------------------------
% File : LCL642+1.001 : TPTP v9.0.0. Released v4.0.0.
% Domain : Logic Calculi (Modal Logic)
% Problem : In K, box Grz & Grz{C() & A4{C()/p0}/p0} -> Grz1, size 1
% Version : Especial.
% English :
% Refs : [BHS00] Balsiger et al. (2000), A Benchmark Method for the Pro
% : [Kam08] Kaminski (2008), Email to G. Sutcliffe
% Source : [Kam08]
% Names : k_grz_p [BHS00]
% Status : Theorem
% Rating : 0.13 v9.0.0, 0.06 v8.2.0, 0.20 v8.1.0, 0.14 v7.4.0, 0.06 v7.3.0, 0.14 v7.2.0, 0.17 v7.1.0, 0.00 v7.0.0, 0.07 v6.4.0, 0.21 v6.3.0, 0.15 v6.2.0, 0.18 v6.1.0, 0.28 v6.0.0, 0.25 v5.5.0, 0.46 v5.4.0, 0.43 v5.3.0, 0.52 v5.2.0, 0.29 v5.0.0, 0.55 v4.1.0, 0.50 v4.0.1, 0.42 v4.0.0
% Syntax : Number of formulae : 1 ( 0 unt; 0 def)
% Number of atoms : 107 ( 0 equ)
% Maximal formula atoms : 107 ( 107 avg)
% Number of connectives : 207 ( 101 ~; 101 |; 5 &)
% ( 0 <=>; 0 =>; 0 <=; 0 <~>)
% Maximal formula depth : 37 ( 37 avg)
% Maximal term depth : 1 ( 1 avg)
% Number of predicates : 4 ( 4 usr; 0 prp; 1-2 aty)
% Number of functors : 0 ( 0 usr; 0 con; --- aty)
% Number of variables : 56 ( 55 !; 1 ?)
% SPC : FOF_THM_RFO_NEQ
% Comments : A naive relational encoding of the modal logic problem into
% first-order logic.
%------------------------------------------------------------------------------
fof(main,conjecture,
~ ? [X] :
~ ( ! [Y] :
( ~ r1(X,Y)
| p3(Y) )
| ~ ! [Y] :
( ~ r1(X,Y)
| p3(Y)
| ~ ! [X] :
( ~ r1(Y,X)
| ! [Y] :
( ~ r1(X,Y)
| p3(Y) )
| ~ p3(X) ) )
| ! [Y] :
( ~ r1(X,Y)
| p2(Y) )
| ~ ! [Y] :
( ~ r1(X,Y)
| p2(Y)
| ~ ! [X] :
( ~ r1(Y,X)
| ! [Y] :
( ~ r1(X,Y)
| p2(Y) )
| ~ p2(X) ) )
| ! [Y] :
( ~ r1(X,Y)
| p1(Y) )
| ~ ! [Y] :
( ~ r1(X,Y)
| p1(Y)
| ~ ! [X] :
( ~ r1(Y,X)
| ! [Y] :
( ~ r1(X,Y)
| p1(Y) )
| ~ p1(X) ) )
| ~ ( ( ( ( ! [Y] :
( ~ r1(X,Y)
| ! [X] :
( ~ r1(Y,X)
| p2(X)
| ~ ! [Y] :
( ~ r1(X,Y)
| ! [X] :
( ~ r1(Y,X)
| p2(X) )
| ~ p2(Y) ) ) )
| ~ ! [Y] :
( ~ r1(X,Y)
| p2(Y)
| ~ ! [X] :
( ~ r1(Y,X)
| ! [Y] :
( ~ r1(X,Y)
| p2(Y) )
| ~ p2(X) ) ) )
& ( p2(X)
| ~ ! [Y] :
( ~ r1(X,Y)
| ! [X] :
( ~ r1(Y,X)
| p2(X) )
| ~ p2(Y) ) ) )
| ~ ! [Y] :
( ~ r1(X,Y)
| ( ( ! [X] :
( ~ r1(Y,X)
| ! [Y] :
( ~ r1(X,Y)
| p2(Y)
| ~ ! [X] :
( ~ r1(Y,X)
| ! [Y] :
( ~ r1(X,Y)
| p2(Y) )
| ~ p2(X) ) ) )
| ~ ! [X] :
( ~ r1(Y,X)
| p2(X)
| ~ ! [Y] :
( ~ r1(X,Y)
| ! [X] :
( ~ r1(Y,X)
| p2(X) )
| ~ p2(Y) ) ) )
& ( p2(Y)
| ~ ! [X] :
( ~ r1(Y,X)
| ! [Y] :
( ~ r1(X,Y)
| p2(Y) )
| ~ p2(X) ) ) )
| ~ ! [X] :
( ~ r1(Y,X)
| ! [Y] :
( ~ r1(X,Y)
| ( ( ! [X] :
( ~ r1(Y,X)
| ! [Y] :
( ~ r1(X,Y)
| p2(Y)
| ~ ! [X] :
( ~ r1(Y,X)
| ! [Y] :
( ~ r1(X,Y)
| p2(Y) )
| ~ p2(X) ) ) )
| ~ ! [X] :
( ~ r1(Y,X)
| p2(X)
| ~ ! [Y] :
( ~ r1(X,Y)
| ! [X] :
( ~ r1(Y,X)
| p2(X) )
| ~ p2(Y) ) ) )
& ( p2(Y)
| ~ ! [X] :
( ~ r1(Y,X)
| ! [Y] :
( ~ r1(X,Y)
| p2(Y) )
| ~ p2(X) ) ) ) )
| ~ ( ( ! [Y] :
( ~ r1(X,Y)
| ! [X] :
( ~ r1(Y,X)
| p2(X)
| ~ ! [Y] :
( ~ r1(X,Y)
| ! [X] :
( ~ r1(Y,X)
| p2(X) )
| ~ p2(Y) ) ) )
| ~ ! [Y] :
( ~ r1(X,Y)
| p2(Y)
| ~ ! [X] :
( ~ r1(Y,X)
| ! [Y] :
( ~ r1(X,Y)
| p2(Y) )
| ~ p2(X) ) ) )
& ( p2(X)
| ~ ! [Y] :
( ~ r1(X,Y)
| ! [X] :
( ~ r1(Y,X)
| p2(X) )
| ~ p2(Y) ) ) ) ) ) )
& ! [Y] :
( ~ r1(X,Y)
| p2(Y)
| ~ ! [X] :
( ~ r1(Y,X)
| p2(X)
| ~ ! [Y] :
( ~ r1(X,Y)
| ! [X] :
( ~ r1(Y,X)
| p2(X) )
| ~ p2(Y) ) ) ) ) ) ).
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