TPTP Problem File: KRS012-1.p
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- Solve Problem
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% File : KRS012-1 : TPTP v9.0.0. Released v2.0.0.
% Domain : Knowledge Representation
% Problem : Paramasivam problem T-Box 4a
% Version : Especial.
% English : f subsumes c.
% Refs : [PP95] Paramasivam & Plaisted (1995), Automated Deduction Tec
% Source : [PP95]
% Names : Problem 4(a) [PP95]
% Status : Unsatisfiable
% Rating : 0.00 v7.1.0, 0.17 v7.0.0, 0.12 v6.3.0, 0.14 v6.2.0, 0.00 v2.1.0
% Syntax : Number of clauses : 13 ( 2 unt; 6 nHn; 10 RR)
% Number of literals : 34 ( 0 equ; 14 neg)
% Maximal clause size : 4 ( 2 avg)
% Maximal term depth : 2 ( 1 avg)
% Number of predicates : 5 ( 5 usr; 0 prp; 1-2 aty)
% Number of functors : 4 ( 4 usr; 1 con; 0-1 aty)
% Number of variables : 14 ( 0 sgn)
% SPC : CNF_UNS_RFO_NEQ_NHN
% Comments :
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cnf(clause_1,negated_conjecture,
c(exists) ).
cnf(clause_2,negated_conjecture,
~ f(exists) ).
cnf(clause_3,axiom,
( e(X3)
| ~ c(X1)
| ~ r(X1,X3)
| ~ d(X3) ) ).
cnf(clause_4,axiom,
( d(X2)
| ~ c(X1)
| ~ r(X1,X2) ) ).
cnf(clause_5,axiom,
( c(X1)
| ~ d(u0r1(X1))
| ~ e(u0r2(X1)) ) ).
cnf(clause_6,axiom,
( c(X1)
| d(u0r2(X1))
| ~ d(u0r1(X1)) ) ).
cnf(clause_7,axiom,
( c(X1)
| r(X1,u0r2(X1))
| ~ d(u0r1(X1)) ) ).
cnf(clause_8,axiom,
( c(X1)
| r(X1,u0r1(X1))
| ~ e(u0r2(X1)) ) ).
cnf(clause_9,axiom,
( c(X1)
| r(X1,u0r1(X1))
| d(u0r2(X1)) ) ).
cnf(clause_10,axiom,
( c(X1)
| r(X1,u0r1(X1))
| r(X1,u0r2(X1)) ) ).
cnf(clause_11,axiom,
( e(X2)
| ~ f(X1)
| ~ r(X1,X2) ) ).
cnf(clause_12,axiom,
( f(X1)
| ~ e(u1r1(X1)) ) ).
cnf(clause_13,axiom,
( f(X1)
| r(X1,u1r1(X1)) ) ).
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