TPTP Problem File: GRA119+1.p
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% File : GRA119+1 : TPTP v9.3.1. Released v9.3.0.
% Domain : Graph Theory
% Problem : Ramsey number r(3,3) = 6 with disequations
% Version : Especial.
% English : The Ramsey property that if an undirected graph has at least
% R(m,n) vertices, then it must have either an m-clique or an
% n-anticlique.
% Refs : [Ram30] Ramsey (1930), On a Problem of Formal Logic
% : [Kal24] Kalizyk (2024), Email to G. Sutcliffe
% Source : [Kal24]
% Names : r_3_3_6_k2 [Kal24]
% Status : Unsatisfiable
% Rating : 0.43 v9.3.0
% Syntax : Number of formulae : 7 ( 4 unt; 0 def)
% Number of atoms : 18 ( 10 equ)
% Maximal formula atoms : 6 ( 2 avg)
% Number of connectives : 19 ( 8 ~; 11 |; 0 &)
% ( 0 <=>; 0 =>; 0 <=; 0 <~>)
% Maximal formula depth : 10 ( 5 avg)
% Maximal term depth : 7 ( 2 avg)
% Number of predicates : 2 ( 1 usr; 0 prp; 2-2 aty)
% Number of functors : 2 ( 2 usr; 1 con; 0-1 aty)
% Number of variables : 8 ( 8 !; 0 ?)
% SPC : FOF_UNS_RFO_SEQ
% Comments :
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fof(rsym,axiom,
! [X,Y] :
( ~ r(X,Y)
| r(Y,X) ) ).
fof(rn3cl,axiom,
! [X,Y,Z] :
( X = Y
| X = Z
| Y = Z
| ~ r(X,Y)
| ~ r(X,Z)
| ~ r(Y,Z) ) ).
fof(rn3acl,axiom,
! [X,Y,Z] :
( X = Y
| X = Z
| Y = Z
| r(X,Y)
| r(X,Z)
| r(Y,Z) ) ).
fof(f6ck,axiom,
f(f(f(f(f(f(c)))))) != f(c) ).
fof(f62ck,axiom,
f(f(f(f(f(f(c)))))) != f(f(c)) ).
fof(f63ck,axiom,
f(f(f(f(f(f(c)))))) != f(f(f(c))) ).
fof(f64ck,axiom,
f(f(f(f(f(f(c)))))) != f(f(f(f(c)))) ).
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