TPTP Problem File: COL074-3.p
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- Solve Problem
%--------------------------------------------------------------------------
% File : COL074-3 : TPTP v9.0.0. Released v1.2.0.
% Domain : Combinatory Logic
% Problem : Unsatisfiable variant of TRC
% Version : [Jec95] (equality) axioms : Augmented.
% English : If the function symbol K is replaced by the K combinator then
% the resultant system is inconsistent.
% Refs : [Jec95] Jech (1995), Otter Experiments in a System of Combinat
% Source : [Jec95]
% Names : - [Jec95]
% Status : Unsatisfiable
% Rating : 0.20 v8.2.0, 0.12 v8.1.0, 0.11 v7.5.0, 0.18 v7.3.0, 0.08 v7.2.0, 0.00 v7.0.0, 0.15 v6.4.0, 0.21 v6.3.0, 0.20 v6.2.0, 0.30 v6.1.0, 0.18 v6.0.0, 0.00 v5.5.0, 0.12 v5.4.0, 0.11 v5.3.0, 0.30 v5.2.0, 0.12 v5.1.0, 0.33 v5.0.0, 0.40 v4.1.0, 0.22 v4.0.1, 0.25 v4.0.0, 0.29 v3.4.0, 0.17 v3.3.0, 0.11 v3.1.0, 0.00 v2.7.0, 0.12 v2.6.0, 0.17 v2.5.0, 0.25 v2.4.0, 0.25 v2.3.0, 0.50 v2.2.1, 0.17 v2.2.0, 0.25 v2.1.0, 0.00 v2.0.0
% Syntax : Number of clauses : 13 ( 11 unt; 1 nHn; 5 RR)
% Number of literals : 15 ( 15 equ; 2 neg)
% Maximal clause size : 2 ( 1 avg)
% Maximal term depth : 4 ( 2 avg)
% Number of predicates : 1 ( 0 usr; 0 prp; 2-2 aty)
% Number of functors : 11 ( 11 usr; 8 con; 0-2 aty)
% Number of variables : 18 ( 3 sgn)
% SPC : CNF_UNS_RFO_PEQ_NUE
% Comments :
%--------------------------------------------------------------------------
%----Don't include axioms of Type-respecting combinators
%include('Axioms/COL001-0.ax').
%--------------------------------------------------------------------------
%----Replace k function by k combinator
%input_clause(k_definition,axiom,
% [++equal(apply(k(X),Y),X)]).
cnf(k_definition,negated_conjecture,
apply(apply(k,X),Y) = X ).
cnf(projection1,axiom,
apply(projection1,pair(X,Y)) = X ).
cnf(projection2,axiom,
apply(projection2,pair(X,Y)) = Y ).
cnf(pairing,axiom,
pair(apply(projection1,X),apply(projection2,X)) = X ).
cnf(pairwise_application,axiom,
apply(pair(X,Y),Z) = pair(apply(X,Z),apply(Y,Z)) ).
%----Replace k function by k combinator
%input_clause(abstraction,axiom,
% [++equal(apply(apply(apply(abstraction,X),Y),Z),apply(apply(X,k(Z)),
%apply(Y,Z)))]).
cnf(abstraction,negated_conjecture,
apply(apply(apply(abstraction,X),Y),Z) = apply(apply(X,apply(k,Z)),apply(Y,Z)) ).
cnf(equality,axiom,
apply(eq,pair(X,X)) = projection1 ).
cnf(extensionality1,axiom,
( X = Y
| apply(eq,pair(X,Y)) = projection2 ) ).
cnf(extensionality2,axiom,
( X = Y
| apply(X,n(X,Y)) != apply(Y,n(X,Y)) ) ).
cnf(different_projections,axiom,
projection1 != projection2 ).
%----This are the extra lemmas
cnf(k_projection1,axiom,
apply(k,projection1) = k_projection1 ).
cnf(k_projection2,axiom,
apply(k,projection2) = k_projection2 ).
cnf(self_referential,axiom,
s = apply(eq,pair(apply(k,s),apply(k,projection2))) ).
%--------------------------------------------------------------------------