TPTP Problem File: BOO026-1.p
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% File : BOO026-1 : TPTP v8.2.0. Released v2.2.0.
% Domain : Boolean Algebra
% Problem : Absorption from self-dual independent 2-basis
% Version : [MP96] (eqiality) axioms : Especial.
% English : This is part of a proof that there exists an independent self-dual
% 2-basis for Boolean Algebra. You may note that the basis
% below has more than 2 equations; but don't worry, it can be
% reduced to 2 (large) equations by Pixley reduction.
% Refs : [Wos98] Wos (1998), Automating the Search for Elegant Proofs
% : [McC98] McCune (1998), Email to G. Sutcliffe
% : [MP96] McCune & Padmanabhan (1996), Automated Deduction in Eq
% Source : [McC98]
% Names : DUAL-BA-3 [MP96]
% : DUAL-BA-3 [Wos98]
% Status : Unsatisfiable
% Rating : 0.18 v8.2.0, 0.21 v8.1.0, 0.20 v7.5.0, 0.25 v7.4.0, 0.30 v7.3.0, 0.32 v7.1.0, 0.22 v7.0.0, 0.32 v6.4.0, 0.42 v6.3.0, 0.47 v6.2.0, 0.50 v6.1.0, 0.31 v6.0.0, 0.48 v5.5.0, 0.47 v5.4.0, 0.27 v5.3.0, 0.17 v5.2.0, 0.21 v5.1.0, 0.20 v5.0.0, 0.21 v4.1.0, 0.09 v4.0.1, 0.14 v4.0.0, 0.23 v3.7.0, 0.11 v3.4.0, 0.12 v3.3.0, 0.07 v3.1.0, 0.11 v2.7.0, 0.00 v2.2.1
% Syntax : Number of clauses : 11 ( 11 unt; 0 nHn; 1 RR)
% Number of literals : 11 ( 11 equ; 1 neg)
% Maximal clause size : 1 ( 1 avg)
% Maximal term depth : 5 ( 2 avg)
% Number of predicates : 1 ( 0 usr; 0 prp; 2-2 aty)
% Number of functors : 7 ( 7 usr; 4 con; 0-2 aty)
% Number of variables : 20 ( 0 sgn)
% SPC : CNF_UNS_RFO_PEQ_UEQ
% Comments : The original proof has 816 steps. Wos later found a 99-step
% proof.
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%----Two Boolean algebra properties and their duals:
cnf(multiply_add_property,axiom,
multiply(X,add(Y,Z)) = add(multiply(Y,X),multiply(Z,X)) ).
cnf(additive_inverse,axiom,
add(X,inverse(X)) = n1 ).
cnf(add_multiply_property,axiom,
add(X,multiply(Y,Z)) = multiply(add(Y,X),add(Z,X)) ).
cnf(multiplicative_inverse,axiom,
multiply(X,inverse(X)) = n0 ).
%----Expanded Pixley properties and their duals:
cnf(pixley1,axiom,
add(multiply(X,inverse(X)),add(multiply(X,Y),multiply(inverse(X),Y))) = Y ).
cnf(pixley2,axiom,
add(multiply(X,inverse(Y)),add(multiply(X,Y),multiply(inverse(Y),Y))) = X ).
cnf(pixley3,axiom,
add(multiply(X,inverse(Y)),add(multiply(X,X),multiply(inverse(Y),X))) = X ).
cnf(pixley1_dual,axiom,
multiply(add(X,inverse(X)),multiply(add(X,Y),add(inverse(X),Y))) = Y ).
cnf(pixley2_dual,axiom,
multiply(add(X,inverse(Y)),multiply(add(X,Y),add(inverse(Y),Y))) = X ).
cnf(pixley3_dual,axiom,
multiply(add(X,inverse(Y)),multiply(add(X,X),add(inverse(Y),X))) = X ).
%----Denial of the conclusion:
cnf(prove_multiply_add,negated_conjecture,
multiply(add(a,b),b) != b ).
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