S5=KM4B and S5=KM5
The 2 Axiomatizations
S5=KM4B
: PC + Necessitation + K + M + 4 + B
S5=KM5
: PC + Necessitation + K + M + 5
Need prove only 4 and B from KM5, and 5 from KM4B
From S5=KM4B
The problem file
S5=KM4B_to_S5=KM5.p
Proved
axiom_5
((only) by providing exactly the required parts of KM4B
(
S5=KM4B_to_S5=KM5.reduced.p
))
From S5=KM5
The problem file
S5=KM5_to_S5=KM4B.p
Proved
axiom_B